The pressure and volume of a gas are inversely proportional at a constant temperature.
P1V1 = P2V2
The volume of a gas is directly proportional with the KELVIN temperature at a constant pressure.
Kinetic Molecular Theory of Gases
1. Gases consist of tiny particles.
2.These particles are so small, their volume can be assumed to be negligible (zero).
3. The particles are in constant, random motion, colliding with the walls of the container. These collisions with the walls cause the pressure exerted by the gas.
4.The particles are assumed not to attract or repel each other.
5. The kinetic energy of the particles is directly proportional to the Kelvin temperature of the gas.
(As the temperature increases the energy increases)
Standard Temperature & Pressure (STP) - a shorthand method that can be used when writing word problems.
Measures atomospheric pressure.
Combined Gas Law
P1V1T2 = P2V2T1
Ideal Gas Law
Dalton's Law of Partial Pressures
Molar Volume of a Gas
1 mole of any gas at STP = 22.4 Liters
The energy an object has due to its motion.
Pressure resulting from the collisions of atoms and molecules with objects.
What are the conversions between pressure units? (What amount of atm equals what amount of kPa, psi, torr, etc)
1 atm = 760 torr = 760 mmHg = 101.3 kPa
If 2.5g of sulfur hexafluoride is introduced to an evacuated 500.0mL container at 83*C, what is the pressure, in atmospheres, inside the container?
PV = nRT
2.5g SF6 (1mole SF6/ 146.08 g SF6) = 0.017 moles SF6
P = (nRT)/V
P =[ (0.017 moles)x(0.08205746 L atm/K mol)x(83+273K)/(.5 L)
If the total pressure of a two gas system is 100 torr and the partial pressure of one gas is 70 torr, what is the pressure of the other gas?
Pother = 30 torr
Gases deviate most from ideal behavior under conditions of very ______ temperature and very _______ pressure
According to _____________ law, pressure and volume are ______________ proportional provided all other factors remain constant. Mathematically, this means that their ____________ is a constant.
Boyle's; inversely; temperature
If pressure is constant, the volume of a sample of gas _____________ as temperature increases.
At constant pressure, the volume of a sample of gas is ___________ proportional to temperature as measured on the ____________ temperature scale
A balloon with a volume of 2.0 L is filled with a gas at 3 atmospheres. If the pressure is reduced to 0.5 atmospheres without a change in temperature, what would be the volume of the balloon?
Since the temperature does not change, Boyle's law can be used. Boyle's gas law can be expressed as:
PiVi = PfVf (i=initial and f=final)
To find the final volume, solve the equation for Vf:
Vf = PiVi/Pf
Vi = 2.0 L
Pi = 3 atm
Pf = 0.5 atm
Vf = (2.0 L)(3 atm)/(0.5 atm)
Vf = 6 L/0.5
Vf = 12 L
The volume of the balloon will expand to 12 L.
A 600 mL sample of nitrogen is heated from 27 °C to 77 °C at constant pressure. What is the final volume?
The first step to solving gas law problems should be converting all temperatures to absolute temperatures. This is the most common place mistakes are made in this type of homework problem.
K = 273 + °C
Ti = initial temperature = 27 °C
K = 273 + 27
Ki = 300 K
Tf = final temperature = 77 °C
K = 273 + 77
Kf = 350 K
The next step is to use Charles' law to find the final volume. Charles' law is expressed as:
ViTf = VfTi
Vi and Ti is the initial volume and temperature
Vf and Tf is the final volume and temperature
Solve the equation for Vf:
Vf = ViTf/Ti
Enter the known values and solve for Vf.
Vf = (600 mL)(350 K)/(300 K)
Vf = 700 mL
The final volume after heating will be 700 mL.
The pressure of a mixture of nitrogen, carbon dioxide, and oxygen is 150 kPa. What is the partial pressure of oxygen if the partial pressures of the nitrogen and carbon dioxide are 100 kPA and 24 kPa, respectively?
P = Pnitrogen + Pcarbon dioxide + Poxygen
150 kPa = 100 kPa + 24 kPa + Poxygen
Poxygen = 150 kPa - 100 kPa - 24 kPa
Poxygen = 26 kPa
A cylinder contain a gas of volume 30 L, at a pressure of 110 kPa and a temperature of 420 K. Find the temperature of the gas which has a volume 40 L at a pressure of 120 kPa.
Vi = 30 L, Pi = 110 kPa, Ti = 420 K, Vf = 40 L, Pf = 120 kPa
Final Temperature(Tf) = PfVfTi / PiVi
Tf= (120kPa x 40L x 420K) / (110kPa x 30L)
Tf = 610.91 K
A cylinder contain a gas of volume 10 L, at a pressure of 80 kPa and a temperature of 200 K. Find the temperature of the gas which has a volume 20 L at a temperature of 220 K.
Vi = 10 L, Pi = 80 kPa, Ti = 200 K, Vf = 20 L, Tf = 220 kPa
Final Pressure(Pf) = PiViTf / TiVf
Pf= (80 x 10 x 220) / (200 x 20)
Pf = 44 kPa