unit 2 Flashcards

(27 cards)

1
Q

What is equilibrium

A

the state attained in a reversible reaction, when the rate of the forward reaction equals the rate of the reverse reaction.
the concentration if the reactants and products are constant.
a catalyst has no effect.

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2
Q

the equilibrium constant

A

aA + bB ⇌ cC + dD

K = [C]^c [D]^d / [A]^a [B]^b

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3
Q

calculations involving equilibrium constants

A

the equilibrium constant has no units
if K >1, equilibrium lies to the right, favouring products
if K<1, equilibrium les to the left, favouring reactants
K gives no indication of rate

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4
Q

calculations involving equilibrium constants further points

A

-the concentrations of pure solids and pure liquids at equilibrium are taken as a contestant and given a value of 1 in equilibrium expression
-the value of K can be affected by changing temps.
-the value of K cannot be affected by changes in pressure or concentration.

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5
Q

increasing temp does what to the value of K

A

increases it

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6
Q

if value of K is lower at a higher temp

A

reaction in exothermic, by lowering temp eq goes right

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7
Q

Standard enthalpy of formation (∆Hf)

A

The enthalpy change involved when one mole of a substance is formed from its elements in their standard states

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8
Q

eqn used to calculate standard enthalpy change for a chemical reaction

A

ΔHf = Σ ΔH products - Σ ΔH reactants

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8
Q

what is the value of the enthalpy of formation of an element

A

0

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9
Q

standard state

A

the standard state of a substance is its most stable form at a pressure of 1atm at a specific temperature usually taken as 298 K or 25c

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10
Q

entropy

A

a measure of the amount of disorder

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11
Q

symbol for entropy

A

S

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12
Q

standard entropy

A

entropy at 298K, 1atm

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13
Q

units for standard entropy

A

JK-1 mol-1

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14
Q

the standard entropy for solids

A

lower compared to liquids and gas

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15
Q

link between temp and entropy

A

as temp goes up entropy goes up

16
Q

at what temp do molecular vibrations stop, giving a substance 0 entropy

17
Q

third law of thermodynamics

A

at 0k, the particles in a solid are no longer vibrating are perfectly ordered. such a solid is described as a perfect crystal. so entropy of a perfect crystal at 0K is zero

18
Q

predicting an increase/decrease in entropy

A

negative entropy when the reactants have a gas (high entropy), the products are solid (low entropy)

19
Q

calculating entropy change

A

ΔS = ΣS prod - ΣSreact

20
Q

feasible reaction

A

one which tends towards the products.

21
Q

eqn that links Gibbs free energy, enthalpy, entropy and temp

22
Q

if ΔG < 0

A

reaction is feasible/spontaneous

23
Q

second law of thermodynamics

A

defines the condition for a feasible reaction.

  • for a reaction to be feasible, the total entropy for a reaction is positive
24
Free energy
At eq: ΔG=0 when ΔG<0: the forward reaction is feasible, with a greater concentration of products. K>1 when ΔG>0 the reverse reaction is feasible, there is a greater concentration of reactants. K<1
25
reaction mechanism and the rate determining step RDS
The rate of a multi step reaction is determined by the slowest step, the RDS a reaction mechanism/ rate eqn cannot be determined from an equation alone. the order and rate eqn can only be determined from experimental results.
26
rate depends on
the concentration of reactants in the slow step.