unit 2 Flashcards
(62 cards)
State what is meant by standard enthalpy change of neutralisation, ΔneutH d
heat energy released under standard conditions
2. (when) 1 mol of water is produced (by the reaction of acid
with alkali)
Explain how, if at all, the enthalpy change of neutralisation obtained in
(b)(ii) would differ if the heat capacity of the calorimeter was included
in the calculation.
(because the calculation has not taken into account the) energy
required to heat the calorimeter/ the (total) heat capacity would be
greater
2. the value(of the enthalpy change of neutralisation) would be more
exothermic/more negativ
, sodium hydroxide reacts with 1‑bromopropane to
form propene.
Name the type of reaction and a suitable solvent.
elimination
2. ethanol / alcohol
Explain why iodine is more soluble in hexane than in water,
iodine has (only) London forces/cannot form hydrogen bonds
IP2 water molecules form hydrogen bonds (and London forces and
permanent dipoles)
IP3 hydrogen bonds are stronger than London forces/ the strongest
(intermolecular force)
IP4 hexane forms (only) London forces/cannot form hydrogen
bonds
IP5 London forces formed between iodine and hexane are similar
(in strength) to those (broken) in hexane/ iodine (so iodine 6 Iodine cannot form hydrogen bonds/ only forms weak London
forces with water so the (hydrogen) bonds between water molecules
cannot be broken (so iodine does not dissolve in water)
Explain whether or not the mean titre value for strontium hydroxide would be
different from that for calcium hydroxide.
strontium hydroxide is more soluble than calcium hydroxide
15. (so) titre value would be greater(than that for calcium) or
reverse
Explain how a catalyst increases the rate of this reaction.
provides an alternative pathway/route with a lower
activation energy
29. so a greater proportion of molecules have E>Ea/area under
the curve to the right of Ea increases
30. so a higher proportion of collisions are successful
Suggest suitable reagents and conditions for the conversion of propene to
propane‑1,2‑diol.
potassium manganate(VII)/
potassium permanganate/KMnO4
3. acidified/cold/room temperature/dilute aqueous solution
Suggest why the production of propenoic acid from propane‑1,2,3‑triol is
more sustainable than its production from propene.
from propene the starting material is crude oil which is nonrenewable/finite
5. from propane-1,2,3-triol, the starting material is from
biomass/uses a by-product/reduces waste from biodiesel
production
6. propane-1,2,3-triol route produces only water as unwanted
produc
Describe how intermediate J is formed in the first step, naming the process
that occurs.
- heterolytic (bond) fission occurs (1)
- the (pair of) electrons in the C─Br bond are transferred to
the bromine atom
Give two reasons why this value, measured under standard conditions, is
different from the value obtained using bond enthalpy data.
he bond enthalpies are averaged over a (large) number of
compounds (1)
* bond enthalpies always refer to substances in the gas phase
ompare and contrast the intermolecular forces involved when hydrogen and
ammonia liquefy, by describing how these forces are formed.
1both hydrogen and ammonia form London /
dispersion forces
* IP2 a temporary dipole forms in a molecule and induces a
dipole in an adjacent molecule
* IP3 the attraction (between the temporary dipoles) is small(er)
in hydrogen because the H2 electron cloud is not easily
polarised
Differences
* IP4 ammonia forms hydrogen bonds (because nitrogen is very
electronegative)
δ+ δ- :——
hydrogen bond
* IP5 Accept hydrogen bond forms between the nitrogen lone
pair and the (δ+) hydrogen (of a different molecule)
* IP6 ammonia liquefies more easily than hydrogen because
hydrogen bonds are stronger than London forces
(c) Explain how the infrared spectra of methanol and methanal can be used to
distinguish between the two compounds, stating the relevant bond stretching
vibrations and their wavenumber ranges.
Suggest how propane-1,2,3-triol makes disinfectants more viscous.
- propane-1,2,3-triol forms three hydrogen bonds per
molecule (1) - so the molecules are strongly attracted to each other (and
to surfaces
xplain why alcohol B has a higher boiling temperature than alcohol A.
(alcohol B has) stronger London forces
(as) greater (contact) surface area
(between molecules)
why yeild is low
secondary amine
Discuss some aspects of the thermal stability of the anhydrous nitrates of the
elements in Groups 1 and 2 of the Periodic Table.
In your answer you should
* explain the trend in thermal stability of the Group 2 nitrates
* describe any differences in the products of thermal decomposition of the
Group 1 nitrates
* give equations for the thermal decomposition of sodium nitrate and of
magnesium nitrate.
thermal stability increases down Group (2)
IP2: ionic radius / size of ions increases (down groups)
and
polarising power (of cations) decreases / charge remains the same/2+
IP3: NO breaks less easily / requires more energy to break (down groups)
IP4: LiNO3 decomposes like Group 2 nitrates
OR
Group 1 nitrates other than lithium form (metal) nitrite/
nitrate(III)/MNO2
IP5: equation for thermal decomposition of NaNO3
IP6: equation for thermal decomposition of Mg(NO3)2
advanatge of high pressure
shifts the yeild but requires more energery
Suggest two reasons why it is more profitable to carry out all four stages
at the same site, instead of using different sites for each stage in the
industrial production of ammonium nitrate
less work force ,less land lower transport costs
Explain why calcium carbonate decomposes at a higher temperature than
magnesium carbonate, in terms of the charge and size of the cations.
Size (and charge)
calcium ion / Ca2+ has a larger (ionic) radius than a
magnesium ion (but the same charge)
or
magnesium ion / Mg2+ has a smaller (ionic) radius / is
smaller than a calcium ion (but the same charge) (1)
Polarising power
so calcium ion / Ca2+ causes less polarisation /
distortion
or
magnesium ion / Mg2+ causes more polarisation /
distortion (1)
What is polarised
of the carbonate ion / CO32− / anion / negative ion /
C−O bonds / C=O bonds /CO bonds
Descending the group from fluorine to iodine, the electronegativity of the atoms
decreases even though their nuclear charge increases.
Explain the trend in electroneg
atomic radius increases
or
distance between the nucleus and outer electrons
increases
or
there are more shells / energy levels of inner electrons
between the nucleus and the outer shell electrons (1)
so there is less attraction (by the nucleus with a higher
charge) for the bonding electrons / shared pair of
electrons
Explain the trend in the boiling temperatures of the hydrogen halides.
all hydrogen halides have London forces (and
dipole-dipole forces between molecules) (1)
the strength of the London forces increases
as the number of electrons increases (so the
boiling temperature increases from HCl to
HI)
or
the strength of the London forces increases as
the polarisability of the molecules increases
from HCl to HI (1)
(only) HF has hydrogen bonding (between
molecules) (1)
hydrogen bonding is (much) stronger than
London forces / dipole-dipole forces (so HF
has the highest boiling temperature)
The reaction between 2-bromopropane and potassium hydroxide takes place
under two different conditions:
* in aqueous solution
* in ethanolic solution.
Compare and contrast these two reactions.
IP1 –Similarity
Both reactions involve hydroxide ions / OH−
IP2 – Type of reaction
Reaction with aqueous solution is substitution
and
reaction with ethanolic solution is elimination
IP3 – Type of reagent
(OH− is a) nucleophile in aqueous solution
and
a base in ethanolic solution
IP4 – Products
In aqueous solution propan-2-ol / an alcohol forms
and
in ethanolic solution propene / an alkene forms
IP5 – Equation in aqueous solution
CH3CHBrCH3 + OH− → CH3CHOHCH3 + Br−
IP6 – Equation in ethanolic solution
CH3CHBrCH3 + OH− → CH3CH=CH2 + H2O + B
Give two reasons for the difference between the data book value and the
experimental value, other than referring to standard conditions.
heat loss (to the surroundings) (1)
incomplete combustion (of ethanol) (1)
some ethanol evaporates
) State why no ∆fH d value has been given for oxygen
oxygen is an element and in its
standard state