VBT ,isomerism and CFT

Question 1

Magnetic moment

Answer 1

√n(n+2)

Question 2

nd

Answer 2

outer orbital complex, high spin, spin free

Question 3

(n-1)d

Answer 3

inner orbital complex, spin paired, low spin

Question 4

spectrochemical series

Answer 4

I- < Br-1 < SCN-1 < Cl-1 < S2- < NO3- < F- < OH- < C2O4 2- < H20 < NCS- < EDTA 4- < CH3CN < py < NH3 < en < dipy < NO2- < CN- < CO

Question 5

d2sp3

Answer 5

sq. planner : dx2-y2 + s + px + py

linnear : pz + dz2

Question 6

dsp3

Answer 6

sp2 : triangular

dz2 + pz : linear

Question 7

d3sp3

Answer 7

pentagonal planner: s + px + py + dxy + dx2-y2

linear : pz + dz2

Question 8

[Cu(NH3)4]2+

Answer 8

dsp2(square planner)

Question 9

[Co(NH3)6]2+

Answer 9

d2sp3

Question 10

[Co(C2O4)3]3- and [Co(H2O)6]3+

Answer 10

d2sp3 strong field ligand

Question 11

4d and 5d series

Answer 11

all ligand act as strong field ligand

Question 12

Pt2+ , Pd2+ , Au3+

Answer 12

square planner complex (inner)

Question 13

structural isomerism

Answer 13

1. linkage
2. ionisation
3. hydrate
4. coordination

Question 14

[Ma3b3]

Answer 14

meridinal and facial

Question 15

90 and 180

Answer 15

cis and trans

Question 16

neutral ligand are treated (CFT)

Answer 16

as point dipoles

Question 17

force b/w ligand and central atom (CFT)

Answer 17

elctrostatic

Question 18

point of split (CFT)

Answer 18

baricenter

Question 19

octahedral dxy dyz dzx (CFT)

Answer 19

-0.4

Question 20

octahedral dx2-y2 ,dz2 (CFT)

Answer 20

+0.6

Question 21

crystal field splitting

Answer 21

1. strength of ligand
2. oxidation state
3. 3d < 4d < 5d
4. geometry (sq. planer > octahedral > tetrahedral)

Question 22

CFSE (octahedral)

Answer 22

nt2g(-0.4) + neg(+0.6) + n(pi)

Question 23

tetrahedral (CFT) t2g

Answer 23

+0.4

Question 24

tetrahedral (CFT) eg

Answer 24

-0.6

Question 25

CFSE for tetrahedral

Answer 25

t2g(+0.4) + eg(-0.6) + n(pi)

Question 26

square planner order (CFT)

Answer 26

dx2-y2 > dxy > dz2 > dzx = dyz

Question 27

delta t, s , o (CFT)

Answer 27

delta s * 3/4 = delta o = delta t * 9/4

Question 28

embreld and ruby

Answer 28

e: green - Cr3+ r: red - Cr3+

Question 29

d0 colourless

Answer 29

Sc3+ , Ti4+

Question 30

d10 colourless

Answer 30

Zn2+ , Cu+

Question 31

Example of compounds having colour due to ligand metal charge transfer

Answer 31

KMnO4 (deep pink) K2Cr2O7 (orange) CrO2Cl2(orange)

Question 32

HOMO - LUMO transition is the reason for colour in

Answer 32

Halogen

Question 33

Reason for colour is

Answer 33

1. d-d transition 2. HOMO-LUMO transition 3. ligand metal charge transfer

Question 34

stability of coordination compound

Answer 34

1. strength of ligand 2. charge density on central atom 3. chelation

Question 35

complimentary colours (CFT)

Answer 35

V - Y B - O G - R