Week 1-3 Flashcards

Atomic Structure Chemical Equilibria Functional Groups Chirality Carbohydrate Lipids

1
Q

ATOMS + ATOMIC STRUCTURE

  • Electronic Structure of Atoms
  • Electron shell configuration
  • Octet Rule
A
1s
2s 2p
3s 3p 3d
4s 4p 4d 4f
5s 5p 5d 5f
6s 6p 6d
7s 7p

Octet Rule: Atom always strive to have 8 valence electrons

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2
Q

ATOMS + ATOMIC STRUCTURE

  • Molecular Bonding
  • Covalent, Ionic, Hydrogen, Dipole-Dipole, Van Der Waals
  • Electronegativity
A

Covalent: Atoms share electrons
Ionic: Transfer of electrons
Hydrogen: Weakly bonds atoms together, H
bonds with O, F or N
Dipole-dipole: Weaker than H-bond
Van Der Waals: Forces between same molecules ie. Dipole dipole, H bond, dispersion

Electronegativity:
<0.2 = non polar covalent
0.3-0.4 = polar covalent
>1.5 = ionic

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3
Q

ATOMS + ATOMIC STRUCTURE

- Lewis Structure

A
  • involves sharing of 1 or more electrons between atoms
  • staisfy Octet Rule
  • multiple bonds can be formed
  • electrons that don’t take part = lone pairs

Rule:

  1. Find total e, subtract 1e for every +ve charge
  2. Decide on central atom (least e-ve, not H)
  3. Assign leftover e to other atoms
  4. Leftover = central atom (exceed octet= double bond)
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4
Q

ATOMS + ATOMIC STRUCTURE

- Resonance Structures: Formal Charge

A
  • electron pair delocalisation
  • more than one possible structure for ALTERNATE SINGLE DOUBLE bond arrangement
  • Formal charge
    = #Ve in free atom - #Ve in bonded atom
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5
Q

ATOMS + ATOMIC STRUCTURE

- Polar + Nonpolar molecules

A
  • electronegativity affects parent geometry
  • will not affect VSPER
  • happens due to net dipole movement
  • can learn about solubility (net dipole)
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6
Q

CHEMICAL EQUILIBRIA

- Predict acid and base strength

A

strong acid:

  • dissociates completely in aqueous solution
  • usually have 1 H only
  • eg. HCl, H2SO4, HBr, H2PO4, HNO3

weak acid (Ka):

  • doesn’t completely dissociate
    eg. CH3OOH, HNO2, H3PO4

strong base
eg. NaOH, KOH, CaO, Mg(OH)2

weak base
eg. NH3, C5H5N

  • conjugate acid and base

Equations:
pH = -ln[H3O+]
pOH = -ln[OH-]
Kw = [H3O+][OH-] = 10^-14 at 25 C

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7
Q

CHEMICAL EQUILIBRIA

- Postion of equilibrium in acid base reactions

A

K«0.001

  • only reactants present at eq.
  • essentially no reaction occurs
  1. 001>1000
    - only products are produced at eq.
    - reaction goes essentially to completion
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8
Q

CHEMICAL EQUILIBRIA

  • Calculate pH, pKa, pKo using Ka and Ko
  • Apply Henderson-Hasselbatch equation to understand pH buffers
A

[H3O+][A-] = [HA]

Ka = [H3O+][A-]/[HA]
[H3O+] = Ka ([HA]/[A-])
-ln[H3O+] = -ln(Ka [HA]/[A])
pH = -ln(Ka) - ln([HA]/[A])

pH = pKa + ln([HA]/[A])

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9
Q

FUNCTIONAL GROUPS

  • Ethers
  • Ketones
  • Aldehydes
  • Amines and Amides
  • Saturated and Unsaturated
A

Ethers: methoxymethane, ethoxymethane
Ketones: propanone
Aldehydes: butanal

Amines: propan-1-amine (NH2)
Amides: propan-1-amide (CONH2)

Primary carbon: bonded to 1 C … etc

Saturated = C - C
Unsat = C = C
Prefix = # of C atoms in parent
Infix = nature of C-C bonds
Suffix = class of compound
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10
Q

CHIRALITY

  • Constitutional Isomers
  • Stereoisomers
  • Enantiomers
  • Diastereoisomers
  • Meso compounds
A

Constitutional:

  • Same molecular formula
  • Have different connectivities
  • Different physical + chemical properties

Stereo (spatial isomers):

  • Same connectivities
  • Different spatial arrangement
  • # of stereo isomers = # of chiral carbon centres * number of times molecule can rotate

Enantiomers:

  • stereoisomers
  • pairs of chiral molecules
  • no mirror image, not superimposable

Dia:

  • stereoisomers
  • not mirror images
  • can’t be superimposed
  • have at least 2 chiral centres

Meso compounds:

  • all meso compounds are dia
  • are achiral
  • mirror image is within itself
  • superimposable upon folding itself
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11
Q

CHIRALITY

  • E/Z isomerisation
  • R/S chiral configuration
A
  • E/Z = cis and trans via molecular weight (priority)
  • E = trans, Z = cis
  • R/S = rotating of molecule
  • lowest priority points away
  • R = rectus (clockwise),
    S = sinister (anticlockwise)
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12
Q

CARBOHYDRATE

- D and L configuration

A

D = OH on RIGHT of penultimate carbon

L = OH on LEFT of penultimate carbon

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13
Q

CARBOHYDRATE

  • Penultimate Carbon
  • Anomeric Carbon
  • Anomers
  • Hemiacetal: Reactions included
  • Acetal
  • Glycosides

Pyran and Furan -ose

A

Penultimate C:

  • Second to last carbon on Fisher Projection
  • Ensure that CH2OH is on the end of it

Anomeric C:
- C that is attached to OH and O in Hawthorn Projection + Chair Projection

Anomers:

  • Beta anomer = CH2OH and OH group on anomeric C are in cis
  • Alpha anomer = CH2OH and OH group on anomeric C are in trans

Hemiacetal:
alcohol + aldehyde/ketone = hemiacetal
C bonded to OH, H , OR and R group

Acetal:
C bonded to 2 OR groups, R group and H group
- More stable than Hemiacetal

Glycosides:

  • Cyclic acetals are not in equilibrium with their open chain carbonyl-containing form
  • Hence will not undergo mutarotation
Pyran = 6 sided ring structure
Furan = 5 sided ring structure
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14
Q

CARBOHYDRATE

  • Fisher Projection
  • Hawthorn Projection: axial and equatorial
  • Chair conformation
A

Fisher:
- flat suraface, cross like

Hawthorn:
- ring structure
axial = up/down, equatorial = horizontal
- larger group in equatorial = more stable, less likely to undergo mutarotation

Chair:

  • bowtie
  • more stable form for sugars
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15
Q

CARBOHYDRATE

- Mutarotation

A
  • Optical rotation due to change in equilibrium between 2 anomers (alpha and beta of one sugar)
  • first, break up bond between anomeric carbon and O, to create an OH in place of O, and O in place of OH
  • O and H attached to anomeric carbon rotate
  • bond reformed, OH on anomeric C now points down in axial position, H in equatorial
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16
Q

CARBOHYDRATE

- Reactions

A

hemiacetal = alcohol + ketone/aldehyde

glycosides = cyclic acetals that cannot undergo mutarotation due to instability of new form taken during process

1-4 glycosidic bond occurs between 1C and 4C

1-6 glycosidic bond occurs between 1C and 6C

such formations of di/poly sacch. form H2O

17
Q

STRUCTURE OF BIOLOGICAL MOLECULES

- Naming Carbs

A
triose     C3H6O3
tetrose   C4H8O4
pentose C5H10O5
hexose   C6H12O6
heptose C7H14O7
octose   C8H16O8

Beta-N-glycosidic bond

the CH2OH group is in cis with OH on anomeric C

bond is between OH on anomeric C and N in the ring structure of another sugar