Wrong Anwsers Flashcards

(10 cards)

1
Q

Deduce the formula of the compound that contains 2+ ions and 3- ions that both have the same electron configuration as argon.

A

Ca3P2

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2
Q

Deduce which of Na+ and Mg2+ is the smaller ion.
Explain your answer.

A

Mg2+
Because it has the more protons with the same amount of shielding

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3
Q

Explain why the first ionisation energy of sulfur is different from that of phosphorus

A

E- paired in the 3p orbital in S and
paired e- repel more so less energy is required to remove electrons

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4
Q

Using the same apparatus, suggest how the procedure could be improved to reduce the percentage uncertainty in using the burette.
Justify your suggested improvement.

A

Use a larger mass of the solid
So there would be a larger titrate value which will decrease uncertainty

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5
Q

In terms of structure and bonding explain why the boiling point of bromine is
different from that of magnesium. Suggest why magnesium is a liquid over a much greater temperature range compared to bromine.

A

M1 Bromine is simple molecules

M2 Magnesium is metallic

M3 Br2 has weak IMFs

M4 so more energy is needed to overcome the stronger metallic bonds

M5 molten mg is stronger

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6
Q

Explain how ions are accelerated, detected and have their abundance determined in a time of flight TOF mass spectrometer

A

(lons accelerated by) attraction to negatively charged plate / electric field
Ions detected by gaining electrons
Abundance determined by (size) of current flowing (or amount of electrons gained) in the detector

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7
Q

Name the type of bond formed between N and Al in H3NAlCl3 and explain how
this bond is formed.

A

Dative (covalent) /co-ordinate bond

Shared pair of / both electrons come from the N(H3)

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8
Q

Explain how the value of the Cl-Al-Cl bond angle in ACl3 changes, if at all, on formation of the compound H3NAICl3

A

Aluminium is now surrounded by 4 electron pairs/bonds or is tetrahedral

Therefore Cl-Al-Cl bond angle decreases / changes (from 120° in AlCls ) to allow range 107-111° in H3NAICl3

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9
Q

Half equations for oxidation of chlorine ions

A

2Cl- —> Cl2 + 2e-

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10
Q

Half equations for reduction of chlorite (I) ions to chlorine in acidic conditions

A

2ClO- + H+ 2e- —> Cl2 + 2H2O

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