Y2, C5 - Forces & Friction Flashcards

(35 cards)

1
Q

What direction does a normal reaction act

A

Perpendicular to the surface

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2
Q

What direction does weight always act

A

Vertically downwards

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3
Q

What is Newton’s first law

A

An object will remain at rest or continue to move with constant velocity unless acted upon by an external force

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4
Q

Why are forces resolved perpendicular to each other

A

Because perpendicular forces do not interact with each other

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5
Q

If a particle is static what do:
a) forces left equal?
b) forces down equal?

A

a) forces left = forces right
b) forces down = forces up

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6
Q

What does it mean if a bead is smooth on a string

A

The two parts of the string can be considered the same and thus the tension is the same throughout

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7
Q

What does it mean in terms of tension if a particle (bead) cannot smoothly move along a string

A

The tension is different both sides (e.g. T1, T2)

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8
Q

What steps should you always take when solving statics problems (2)

A

1) Resolve horizontally
2) Resolve vertically

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9
Q

What is Newton’s second law

A

F = ma
An object will accelerate if there is an overall resultant force on the object

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10
Q

When shown a diagram with lots of forces that need resolving, what can you do

A

Draw a new diagram with all the forces resolved horizontally and vertically

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11
Q

How can you use vectors to combine forces

A

Separate forces into i and j components
Write in vector form
Resultant force = (i, j) where all i components are added and all j components are added
Magnitude = Pythagoras
arctan(j / i) = angle

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12
Q

How should you resolve forces on inclined planes in relation to the plane

A

Parallel and perpendicular to the plane

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13
Q

With inclines plane problems can you draw a new diagram with forces resolved parallel and perpendicular to the plane

A

Yes

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14
Q

When there is no pulling force (tension T = 0), what is the frictional force and is the system in equilibrium

A

μR = 0
No friction
Equilibrium as not moving

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15
Q

When there is a pulling force (tension T < μR(max)), what is the frictional force and is the system in equilibrium

A

μR = T
Friction is the same magnitude as the opposing force
Equilibrium as not moving

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16
Q

When there is a pulling force (tension T > μR(max)), what is the frictional force and is the system in equilibrium

A

μR = μR(max)
Friction has reached its maximum limit
No equilibrium, the forces are imbalanced so the object accelerates

17
Q

When there is a pulling force (tension T = μR(max)), what is the frictional force and is the system in equilibrium (2 situations)

A

μR = μR(max)
Friction is limiting and has reached its maximum
Equilibrium - limiting equilibrium
OR
Equilibrium - object moves with constant velocity

18
Q

What is the relationship between T and μR(max) if a force is applied to an object and it doesn’t move

19
Q

What is the relationship between T and μR(max) if a force is applied to an object and the block accelerates

20
Q

What is the relationship between T and μR(max) if a force is applied to an object and the block is on the point of slipping

21
Q

What is the maximum friction between two surfaces equal to (formula)

A

Friction(max) = μR

22
Q

Can you have a negative coefficient of friction (μ) value

23
Q

What direction does friction act

A

Opposite to motion

24
Q

Can friction be less than it’s maximum value

A

YES, if the force opposing it is small

25
How do you use the assumption that a pulley is smooth in calculations
Tension both sides of it is equal
26
Friction acts up a slope to stop an object from slipping. What direction does the friction act if a horizontal force is applied to the box (into the plane) given that the box remains in equilibrium
Friction changes direction and acts down the slope, opposing the direction of motion up the slope
27
How can you find the maximum value P that can work against a friction while keeping an object in equilibrium
μR is at a maximum Resolve and solve simultaneously to find P
28
How would you find a range of possible values for tension that keep an object at equilibrium on a rough plane
Solve 2 equations for T Slipping UP (friction works down) Slipping DOWN (friction works up) ans = Smallest T <= T <= Biggest T Where smallest T is the limiting equilibrium to move down the plane and biggest T is the limiting equilibrium moving up the plane
29
How do you determine of an object will move on a rough plane
If F > Frictional force Compare F with μR If F > μR it will move (where F is the force up or down the plane opposing the friction)
30
What should you take as the weight of an object if you are not given the mass
mg
31
If a particle is projected up a slope, what is the force upwards
0 There is no force acting on it as it is projected, all forces will work to stop it from going up
32
You have a block (P) on a rough plane attached to a smooth pulley with a block on the other end (Q) hanging freely. When the hanging block is released, how do you go about calculating the acceleration of the system
Write equations of motion for both P and Q separately using F = ma Solve equations simultaneously to find acceleration and force (tension in string)
33
How do you use the fact that a string is inextensible in calculations
Acceleration is the same in particles at both ends
34
What is the equation for the resultant force exerted on a pulley by a string (over an inclined plane)
2 * T * cos((90 - α) / 2) Where T is tension α is the angle of incline of the plane
35
What direction does the resultant force exerted on a pulley by a string (over an inclined plane) act
Directly down the middle into the incline plane (splitting the angle of the corner in half)