Y2, C7 - Differential Equations Flashcards

1
Q

How would you separate the variables in: dy/dx = f(x) g(y)

A

1/g(y) * dy/dx = f(x)
int(1/g(y)) * dy = int(f(x)) * dx

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2
Q

Find general solutions to dy/dx = -y/x

A

1/y * dy/dx = -1/x
int(1/y) * dy = int(-1/x) * dx
lnlyl = -lnlxl + lnlkl
y = k/x

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3
Q

Solve d/dx * (ysin(x))

A

sin * dy/dx + ycos(x)

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4
Q

Find general solutions of the equation x^3 dy/dx + 3x^2 * y = sinx

A

d/dx * (x^3 * y) = sinx
x^3 * y = int(sinx) dx
x^3 * y = -cosx
x^3 * y = -cos(x) + c

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5
Q

Using the reverse product rule, find general solutions to 4xy * dy/dx + 2y^2 = x^2

A

d/dx * (2xy^2) = x^2
2xy^2 = int(x^2)dx
2xy^2 = (1/3) * x^3 + c
y^2 = (1/6) * x^2 + c/2x

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6
Q

What is the integrating factor

A

e^(int(P)dx)

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7
Q

How do you solve equations in the form dy/dx + Py = Q
(where P and Q are functions of x)

A

Reverse product rule

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8
Q

What form of equation can you use the reverse product rule on

A

dy/dx + Py + Q
(where P and Q are functions of x)

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9
Q

What is the integrating factor of dy/dx - 4y = e^x

A

I.F. = e^(int(-4dx))
= e^-4x

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10
Q

What do you do once you have found the integrating factor

A

Multiply all terms in the expression by the integrating factor
Then solve the usual way (reverse product rule)

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11
Q

What do you do if there is a coefficient in front of the dy/dx term in an expression of form dy/dx + Py = Q

A

Divide all terms by the coefficient to remove

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12
Q

What would the solution of a * dy/dx + by = 0 be in the form of

A

y = Ae^(x * -b/a)

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13
Q

What would the solution of a(d2y/dx2) + b(dy/dx) + cy = 0 be in the form of

A

y = Ae^mx

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14
Q

What is the Auxiliary equation

A

am^2 + bm + c = 0

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15
Q

What does auxiliary mean

A

Helpful

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16
Q

What is the general solution to a differential equation if the auxiliary equation has two distinct roots

A

y = Ae^αx + Be^βx

17
Q

What is the auxiliary equation of 2(d2y/dx2) + 5(dy/dx) + 3y = 0

A

2m^2 + 5m + 3 = 0

18
Q

When the auxiliary equation has two equal roots, what is the general solution

A

y = (A + Bx)e^αx

19
Q

When the auxiliary equation has no real roots, what is the general equation

A

y = Ae^αx + Be^βx
(the same as if the roots are real)

20
Q

Find the general solution of d2y/dx2 + 16y = 0

A

y = Ae^4ix + Be^-4ix
= A(cos4x + isin4x) + B(cos4x - isin4x)
= (A+B)cos4x + (A-B)isin4x
y = Pcos4x + Qsin4x
P = A+B
Q = (A-B)i

21
Q

If the auxiliary equation has two imaginary roots ±Ω, what is the general solution

A

y = Acos(Ωx) + Bsin(Ωx)
where A and B are arbitrary constants

22
Q

If the auxiliary equation has two complex roots p ±iq, what is the general solution

A

y = e^px (Acosqx + Bsinqx)
where A and B are arbitrary constants

23
Q

Find the general solution to d2y/dx2 - 6 * dy/dx + 34y = 0

A

y = Ae^(3+5i)x + Be^(3-5i)x
y = e^3x * (Pcos5x + Qsin5x)

24
Q

What do you do if you have a non-homogeneous second order differential equation = f(x) (not equal to zero on RHS)

A

Solve as if RHS = 0 to obtain ‘complimentary function’ (C.F.
Then solve equation = f(x), can be found by using appropriate substitutions and comparing coefficients (solution known as particular integral (P.I.))
y = C.F. + P.I. as C.F. = 0 and P.I. = f(x) which sum to f(x)

25
Q

If the form of f(x) is a cos or sin, what should the form of the particular integral be

A

λcosΩx + μsinΩx

26
Q

What is the particular integral of d2y/dx2 - 5 * dy/dx + 6y = 3

A

y = λ
dy/dx = 0
d2y/dx2 = 0
6λ = 3
λ = 1/2
P.I. is y = 1/2

27
Q

Find the general solution to d2y/dx2 - 5 * dy/dx + 6y = 3

A

C.F. = y = Ae^3x + Be^2x
P.I. = 1/2
Therefore:
G.S. = Ae^3x + Be^2x + 1/2

28
Q

What happens if the f(x) is part of the complimentary function e.g. f(x) = e^2x and C.F. = y = Ae^2x + Be^3x

A

Everything in the P.I. (particular integral) cancels and LHS = 0

29
Q

What should you do if the f(x) is part of your complimentary function

A

Add an x or sometimes an x^2 in front of your usual P.I. form

30
Q

When should you add an x^2 coefficient to your complimentary function

A

If there is already an x term and a term with no x coefficient in the auxiliary equation

31
Q

How do you find particular solutions for differential equations when given boundary conditions

A

Sub in the value and solve simultaneous equations for A and B

32
Q

What should the particular integral be if RHS = ke^px + c

A

λe^px + μ