2nd: Dynamics; Forces, density & pressure; Work, energy & power Flashcards
(42 cards)
centre of gravity
The point at which the weight of the object may be considered to act
where is CoG
-symmetrical objects with uniform density, the centre of gravity is located at the point of symmetry
-centre of gravity is roughly in the middle of the body behind the navel, and for a sphere, it is at the centre
stability
position of the centre of gravity of an object affects the object’s stability
An object is stable when its centre of gravity lies above its base
The wider the base of an object = lower its centre of gravity = more stable the object is
MOST STABLE have WIDE BASES AND LOW COG
The narrower the base of an object = higher its centre of gravity = less stable the object is
Centre of gravity versus centre of mass
in uniform gravitational field, the centre of gravity is identical to the centre of mass. Centre of mass does not depend on the gravitational field
+W = mg, the centre of gravity does depend on the gravitational field
++When an object is in space:
📍Its centre of gravity will be closer to object with larger gravitational field
📍Its centre of mass will be close to its geometric centre- CENTRE OF MASS IN MIDDLE
also: Since the centre of gravity is a hypothetical point, it can lie inside or outside of a body. Centre of gravity can also move, depending on the shape or the orientation of the object being considered. E.g, a human body’s centre of gravity is lower when leaning forwards than when standing upright.
moment = Fd
turning effect of a force (about a pivot)
-occurs when forces cause objects to rotate about a pivot
+The force may not always be applied perpendicularly to the pivot. But distance used in the equation must be the perpendicular distance from the pivot. In these cases, the component of the distance that is perpendicular to the pivot must be used
e.g in daily life
📍tip
opening a door
+door handle is placed on the opposite side of the door to the hinge (the hinge is the pivot)
+maximises the distance for a given force
-Which provides a greater moment (turning effect)
This makes it easier (requires less force) to push or pull the door open
📍📍
-only round your answer right at the end of your calculation. Always work with at least one, preferably two more significant figures than final answer requires.
-Sketching a quick diagram of all the forces acting on the object will help you visualise which forces are perpendicular to the distance from the pivot. Not all forces will provide a turning effect and it is common for questions to provide more forces than required to increase the level of difficulty of the question.
-DEFINITION - couple
-a couple consists of a pair of forces that are:
-couples produce…
-couples CANNOT…
📌 a pair of forces that acts to produce rotation only 📌
-a couple consists of a PAIR OF FORCES that are: EQUAL in magnitude ;; OPPOSITE in direction ;; PERPENDICULAR to the distance between them
-Couples produce a resultant force of zero
(so due to Newton’s 2nd law F=ma, object doesn’t accelerate)
-the forces that make up a couple cannot share the same line of action. The line of action is a line through the point at which the force is applied.
whats the difference between the moment of a single force and moment of a couple?
-moment of a single force depends on the perpendicular distance to the pivot
-However, the moment of a couple depends on the perpendicular distance 📌 BETWEEN 📌 the two forces
DEFINITION torque = Fd where d is perpendicular distance between the forces
moment of a couple =
moment of a pair of forces that acts to produce rotation only
[eg tau (torque) = 10 [FORCE OF COUPLE: opposite, perpendicular, equal] x 0.4 [length of steering wheel along the whole thing] = 4Nm.
4sin(30) [VERTICAL F] x 0.3 [RULER LENGTH] = 0.6Nm.]
DEFINITION! Principle of Moments
For a system to be in equilibrium, the sum of clockwise moments about a point must be equal to the sum of the anticlockwise moments (about the same point)
TIP
distances same units
know if forces CW or ACW
Make sure that all the distances are in the same units and you’re considering the correct forces as clockwise or anticlockwise, as seen in the diagram
force - up, right, CW & down left CW
up, left, ACW
down right ACW
DEFINITION - equilibrium
system is in equilibrium when all the forces are balanced
There is no resultant force and no resultant torque
so according to Newton’s 1st law -
an object in equilibrium will therefore remain at rest, or at a constant velocity, and will not rotate
so for moments, CW = ACW moments.
Coplanar forces in equilibrium
-Coplanar forces can be represented by vector triangles.
-Equilibrium, => coplanar forces are represented by closed vector triangles [forming closed path, keeping SAME LENGTH & DIRECTION - rearrange, connect tip to tail.]
-Forces are in equilibrium if an object is either: At rest, OR Moving at constant velocity
common F: weight, normal reaction force, normal contact force, tension (from cords & strings), friction
-USE RULER for exam
density = m/V
📍Gases are less dense than liquids, which are less dense than solids ;;; bc there are fewer particles, and therefore less mass, per unit volume
📍CALC VOLUME - sphere 4/3pir^3, cube d^3, cylinder pir^2xl
📍1000mm = 1m. IS smaller unit to larger (mm to cm), divide
pressure = F/A
📍DEFINE: force per unit area
📍 how concentrated a force is. SCALAR
📍If a force is spread over a large area it will result in a small pressure; spread over a small area = a large pressure
📍DEFINE - Hydrostatic pressure: the pressure at any given point within a fluid, that is exerted by the weight of the fluid above that point
📍if fluid is at rest, then all the points within the fluid are in equilibrium, so the pressure acts in all directions at each point
derivation of f ∆p = ρg∆h
Using W=mg, p=m/V, P=F/A
replace m and V in eqn.
- Rearrange to form m=pV, and V = Ah
- P = F/A = mg/A = pVg/A = pAhg/a = phg
- P = phg
Using the equation for hydrostatic pressure
📌📌 Total pressure = Hydrostatic pressure + Atmospheric pressure 📌📌
Atmospheric pressure (also known as barometric pressure) is 101 325 Pa 📌
📍When an object is immersed in a liquid, the liquid will exert a pressure which acts in all directions, squeezing the object
📍The size of this pressure depends upon: density, ρ, of the liquid;; depth, h, of the object;; gravitational field strength, g
📍The total pressure acting on the object considers both the weight of the fluid above the object, and the weight of the air above the object
When asked about the total pressure, the atmospheric pressure must also be included
📍 manometer: an instrument to measure pressure and density of two liquids
📍how it works: In Figure 1: The level of liquid is equal because the atmospheric pressure (Patm) is the same
In Figure 2: If the pressure on one side rises, the liquid will be forced down making the liquid in the other limb rise. The difference between the two levels gives the pressure difference between the two ends of the tube
In Figure 3: The U-tube now has two different liquids. The density of the blue one is greater than that of the orange one. The pressure at each point is due to the atmospheric pressure plus the weight of the liquid above it
e.g Atmospheric pressure at sea level has a value of 100 kPa. The density of sea water is 1020 kg m-3.
At what depth in the sea would the total pressure be 250 kPa?
D) 15m
h= (250,000 - 150,000) / (1020 x 9.81) = 15m.
REMEMBER:
-convert all the pressure values to SI units (Pa) before you begin the calculation
-kPa => Pa, x1000
-mPa => Pa, x 10⁶
upthrust
TIP: Since upthrust is a force, it is influenced by pressure, not by the density of the object
📍upthrust: a force which pushes upwards on an object submerged in a fluid (liquids and gases)
📍Also known as buoyancy force, upthrust is due to the difference in hydrostatic pressure at the top and bottom of the immersed object
📍 force of upthrust is significantly greater in liquids than in gases, this is because liquids are much denser than gases
📍UPTHRUST DIRECTLY PROPPORTIONAL TO PRESSURE
📍force on the bottom of the can will be greater than the force on top of the can. Resultant pressure causes a resultant upward force on the can known as upthrust
📍 why objects appear to weigh less when immersed in a liquid. If the upthrust is greater than the weight of the object, the object will rise up
📍For an object to float, it must have a density less than the density of the fluid it is immersed in
e.g 2m², experiences pressures of 3000 Pa and 7700 Pa at the top and bottom of the cube.
P = F/A. F = pressure x area = (7700 - 3000) x 2 = 4700 x 2 = 9400N.
DERIVAT Archimedes’ Principle
states that…
eqn… DERIVATION
📍”An object submerged in a fluid at rest has an
upward buoyancy force (upthrust)
equal
to the weight of the fluid displaced by the object”
📍📍 F = ρVg📍📍
UPTHRUST = density x 9.81 x V
BC F=ma where m = ρV, upthrust is equal to F = (m)g = (ρV)g
or ρ =m/V, F=ma equals m=F/a, so ρ = F/a ÷ V then ρV = F/a then a=g so ρVg = F
physics of Archimedes’ principle
📍object sinks until the weight of the fluid displaced is equal to its own weight
📍Therefore, the object floats when the magnitude of the upthrust equals the weight of the object
eqn how much of iceberg is not submerged?
density of ice / density of water = volume of water/volume of ice
pi / pw = vw / vi.
vw = pi x vi / pw = 917 Vi / 1020 = 0.9Vi
90% of iceberg submerged.
10% not submerged.