3.2.3 - the halogens Flashcards

1
Q

Diatomic halogen molecules are held together by …

A

Weak vdw

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2
Q

Fluroine exists as

A

Pale yellow gas

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3
Q

Chlorine exists as

A

Green gas

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4
Q

Bromine exists as

A

Red brown liquid

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5
Q

Iodine exists as

A

Grey solid

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6
Q

Trend in boiling points down group 7

A

Boiling points increase down group 7

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7
Q

Why do bp increase down group 7

A

Increasing strength of vdw
Due increasing size and increased number of electrons more chance of dipoles inducing dipoles in the neighbouring molecules

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8
Q

Chlorine has a low bp bc forces bet mol are weak
Explain how these forces arise between molecules of chlorine (3)

A

Imbalance of of e- density leads to temporary dipole in the mol which induces a dipole im a neighbouring mol
These temporary dipoles attract

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9
Q

Trend in bond enthalpies down group 7

A

Decrease down down the group
So i-i bonds easier to break than cl-cl bodnds

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10
Q

Why do bond enthalpies decrease down group 7

A

This is due to the increasing atomic radius, increased shielding and
reduced attraction between the nucleus and bonding pair of electrons

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11
Q

Exception to trend in bond enthalpies down group 7

A

The exception to this is fluorine.
● Fluorine has such a small atomic radius that bonding and non-bonding
electrons repel each other, reducing the strength or bond enthalpy.

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12
Q

Define electronegativity

A

Power of an atom to attract a bonding pair of electrons in a covalent bond

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13
Q

Trend in electronegativity going down group 7

A

● Electronegativity of the halogens decreases going
down the group.

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14
Q

Explain trend of decreasing electronegativity down group 7

A

As the atomic radius increases the shared pair of
electrons in the covalent bond are further from the
nucleus, reducing the strength of the attraction.
● Increasing atomic radius also means increasing
shielding effect, again reducing the electronegativity.
● These factors have a greater effect than the increased
nuclear charge

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15
Q

trend in boiling points down group 7

A

increase down the group

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16
Q

explain trend of increasing boiling points down group 7

A

B.p.s increase down the group because…
* Size of diatomic molecules increase down the group.
* Larger molecules have more electrons, leading to greater induced
dipole-dipole forces.
* Therefore greater van der Waals’s forces between molecules.
* Therefore more energy required to overcome the greater van der Waals’s
forces as you go down the group.

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17
Q

define oxidation agent

A

electron acceptor

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18
Q

trend in oxidising ability down group 7

A

decreases down the group

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19
Q

explain trend in decreasing oxidising ability down the group

A

Oxidising power decreases down the group because…
* Size of ions increase down the group.
* Therefore outer electrons are more shielded and further away from the
nucleus.
* Therefore electrostatic force of attraction by nucleus on the
additional electron becomes weaker down the group.
* Therefore harder to gain an electron.

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20
Q

reactivity down group 7

A

decreases

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21
Q

explain decreasing reactivity down group 7

A

increased atomic rad
outershel has increased dist from nuclues
less electrostatic attraction harder to attract e-

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22
Q

whats is displacment

A

more reactive halogen will displace a less reactive one

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23
Q

whats observed when chlorine water reacts w
kcl
kbr
ki

A

kcl - no reac
kbr - orange br2
ki - brown i2

24
Q

whats observed when bromine water reacts w
kcl
kbr
ki

A

kcl - no reac
kbr - no reac
ki - brown i2 formed

25
Q

whats observed when iodine water reacts w
kcl
kbr
ki

A

no reaction for all 3

26
Q

what is a reducing agnent

A

electron donor
it itslef is oxidised

27
Q

trend in reducing ability down grouo 7

A

increases down thr grouo

28
Q

explain trend in reducing ability of halogens down the group

A

Reducing power increases down the group because:
* Size of the ions increase down the group.
* Therefore outer electrons are more shielded and further away from the
nucleus.
* Therefore electrostatic force of attraction by nucleus on outer
electrons becomes weaker down the group.
* Therefore easier to lose an electron.

29
Q

equation for sodium fluroide + conc sulfuric acid

A

NaF + H2SO4 —> NaHSO4 + HF

30
Q

ionic equation for when chlorine diplaces bromine and iodine

A

cl2 (aq) + 2br-(aq) –> 2cl-(aq) + br2 (aq)

cl2(aq) + 2i- (aq) –> 2cl- + i2

31
Q

ionic equation when bromine displaces iodine

A

br2 + 2i- –> 2br- + i2

32
Q

observation fro soild sodium fluroide w conc sulfuric acid

A

misty white fumes (HF) are evolved.

33
Q

equation for reaction w solild nacl and conc h2so4

A

NaCl + H2SO4 → NaHSO4 + HCl

34
Q

observations w solild nacl and conc h2so4

A

misty white fumes (HCl) are evolved.

35
Q

2 equations for reac of nabr w conc h2so4

A

1 - NaBr + H2SO4 → NaHSO4 + HBr
2 - 2HBr + H2SO4 → Br2 + SO2 + 2H2O

36
Q

obs for reac 1 NaBR + h2so4 —-> naso4 + HBR

A

misty white fumes (HBr) and red-brown vapour (Br2) are evolved.

37
Q

Change in ox number for 2Hbr + H2SO4 —> Br2 + So2 + 2H2O

A

Br is oxidised from -1 (in HBr) to 0 (in Br2) therefore bromine =
oxidation product. - S is reduced from +6 (in H2SO4) to +4 (in SO2) therefore sulphur
dioxide = reduction product.

38
Q

4 eq for reaction of NaI w conc h2so4

A

NaI + H2SO4 → NaHSO4 + HI NOT REDOX
2HI + H2SO4 → I2 + SO2 + 2H2O REDOX
6HI + H2SO4 → 3I2 + S + 4H2O REDOX
8HI + H2SO4 → 4I2 + H2S + 4H2O REDOX

39
Q

obs w NaI w conc h2so4

A

(all these reactions happen in succession - not in
isolation): misty white fumes evolved (HI), purple vapour evolved (I2),
yellow solid formed (S), rotten egg smell (H2S) + black solid formed
(I2).

40
Q

explain the redox eq w soloid sodium iodide

A

➜ For the 1st redox reaction.
- the I is oxidised from -1 (in HI) to 0 (in I2) - the S is reduced from +6 (in H2SO4) to +4 (in SO2)
➜ For the 2nd redox reaction,
- the I is oxidised from -1 (in HI) to 0 (in I2) - the S is reduced from +6 (in H2SO4) to 0 (in S)
➜ For the 3rd redox reaction,
- the I is oxidised from -1 (in HI) to 0 (in I2) - the S is reduced from +6 (in H2SO4) to -2 (in H2S)
Therefore oxidation product = iodine; reduction products = sulphur
dioxide, sulphur and hydrogen sulphide.

41
Q

general equation for tests for halide ions where X is eith

A

Ag+ (aq) + X- (aq) –> AgX(s)

42
Q

test for halide ions

A

Add dilute nitric acid (HNO3), followed by silver(I) nitrate (AgNO3)
solution.

43
Q

colour of solid halide ppt

A

Ag+(aq) + Cl-(aq) → AgCl(s) = white ppt. formed
Ag+(aq) + Br-(aq) → AgBr(s) = cream ppt. formed
Ag+(aq) + I-(aq) → AgI(s) = yellow ppt. formed

44
Q

reason for adding dilute nitric acid

A
  • The dilute nitric acid removes other ions which would react with the
    silver nitrate solution (e.g. carbonates/sulphates/hydroxides)
45
Q

what is further test in halide ion test

A

A further test can be carried out with ammonia solution to confirm the
identity of the halide ion:

46
Q

results of further test

A

AgCl: will redissolve in dilute and concentrated ammonia solution to form
a colourless solution.
AgBr: does redissolve
in conc. ammonia solution forming a colourless solution.
AgI does not redissolve in dilute or conc. ammonia solution.

47
Q

what kind of reaction occurs when you mic chlorine with water

A

disproportionation (This
means Chlorine, Cl2 is both oxidised and reduced).

48
Q

give equation for reaction between chlorine and water and explain whats oxidised and reduced

A

Cl2 + H2O ⇌ HClO + HCl
* The Cl is oxidised from 0 (Cl2) to +1 (HOCl)
* The Cl is reduced from 0 (Cl2) to -1 (HCl)

49
Q

give equation for the reaction of chlorine with water to form chloride ions
and oxygen.

A

2Cl2 + 2H2O ⇌ 4HCl + O2

50
Q

adv and disad of formation of chlorate (i) ions when reacting chlorine with water

A

Chlorate(I) ions kill bacteria, this is why chlorine is used in water
treatment to kill bacteria. It’s been used to treat drinking water and
the water in swimming pools. - The benefits to health (including, the irradiation of bacterial
diseases like cholera) from using chlorine OUTWEIGH the fact it’s toxic
/ carcinogenic to humans.

51
Q

When you mix chlorine gas with ____, _____ sodium hydroxide solution at
room temperature it undergoes ___________

A

When you mix chlorine gas with cold, dilute, sodium hydroxide solution at
room temperature it undergoes disproportionation.

52
Q

equation for reaction of chlorine with cold dilute naoh and whats oxidised and reducee

A

Cl2 + 2NaOH → NaCl + NaClO + H2O
* The Cl is oxidised from 0 (Cl2) to +1 (NaClO)
* The Cl is reduced from 0 (Cl2) to -1 (NaCl)

53
Q

observation when reacting chlorine w cold dilute naoh

A

Observation: green gas forms a colourless solution.

54
Q

what is sodium chlorate

A

One of the products formed is sodium chlorate(I), NaClO. It’s in solution
in this case and that is bleach (which kills bacteria)

55
Q

explain why
-silver nitrate solution is used to identify halide ions

A
  • Silver ions combine with halide ions to produce silver halide precipitates with different colours.
56
Q

explain why the silver nitrate solution is acidified

A

to react with any impurities (mainly carbonate ions) that may be present in the solution. Carbonate ions, for example, would form a white precipitate with the silver ions, making the identification of silver halide salts difficult.

57
Q

explain why
ammonia solution is added.

A

The silver halide precipitates have different solubilities in ammonia (NH3), which can be used to help further identify the halides.