3.6 Enthalpy changes for solids and solutions Flashcards

1
Q

Define enthalpy of atomisation

A

The enthalpy change when one mole of gaseous atoms is formed from a compound in its standard state under standard conditions.

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2
Q

Define lattice enthalpy of formation

A

The enthalpy change when one mole of a solid ionic compound is formed from its gaseous constituent ions under standard conditions.

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3
Q

Define lattice dissociation enthalpy

A

The energy required to break apart an ionic lattice into its constituent ions in a gaseous state under standard conditions.

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4
Q

Define enthalpy of solution

A

The enthalpy change when one mole of an ionic solid is dissolved in a solvent to infinite dilution so that the ions no longer interact under standard conditions.

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5
Q

Define enthalpy of hydration

A

The enthalpy change when one mole of aqueous ions is formed from one mole of gaseous ions.

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6
Q

What type of enthalpy change is taking place in the following reaction?
NaCl(s) —> Na+(aq) + Cl-(aq)

A

Enthalpy change of solution

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7
Q

What type of enthalpy change is taking place in the following reaction?
Na+(g) —> Na+(aq)

A

Enthalpy change of hydration

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8
Q

What type of enthalpy change is taking place in the following reaction?
Mg2+(g) + 2Cl-(g) —> MgCl2(s)

A

Lattice enthalpy of formation

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9
Q

What type of enthalpy change is taking place in the following reaction?
1/2Cl2(g) —> Cl(g)

A

Enthalpy of atomisation

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10
Q

What affects the solubility of ionic compounds in water?

A

The solubility of ionic compounds depends on the balance between the hydration enthalpy of the ions in the compound and the lattice dissociation enthalpy of the compound.

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11
Q

What factors affect enthalpy of hydration?

A

Hydration enthalpy of an ion depends on the amount of attraction between the ions and the water molecules. The bigger the charge and the smaller the ion, the larger the enthalpy of hydration.

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12
Q

What is Hess’s law?

A

The enthalpy change of a reaction is independent of the route taken.

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13
Q

How can the enthalpy change of a solution be calculated using an energy cycle?

A

Lattice breaking enthalpy and enthalpy change of hydration can be used in an energy cycle to calculate the enthalpy change of solution using Hess’s law.

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14
Q

What is a Born-Haber cycle?

A

Lattice enthalpy cannot be calculated directly so a Born-Haber cycle can be used to calculate the lattice enthalpy by applying Hess’s law. A Born-Haber cycle calculates lattice enthalpy by comparing the standard enthalpy of formation of the ionic compound to the enthalpy required to make gaseous ions from the elements.

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15
Q

Define standard enthalpy of formation

A

The enthalpy change when one mole of a compound is formed from its elements in their standard states under standard conditions.

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16
Q

Define first ionisation energy

A

The enthalpy change when one mole of gaseous atoms forms one mole of gaseous 1+ ions.

17
Q

Define first electron affinity

A

The enthalpy change when one mole of gaseous 1- ions is formed from one mole of gaseous atoms.

18
Q

Give the equations for the first electron affinity of oxygen and the first ionisation energy of magnesium

A

First electron affinity of oxygen:
O(g) + e- —> O-(g)

First ionisation energy of magnesium:
Mg(g) —> Mg+ + e-

19
Q

What is the perfect ionic model?

A

The perfect ionic model assumes that all ions are perfectly spherical and that the bonds have no covalent character.

20
Q

Why are theoretical lattice enthalpies often different from experimental ones?

A

Theoretical lattice enthalpies use calculations which are based on a perfect ionic model of the lattice. The experimental values often differ because most ionic compounds have some covalent character. The more polarisation in the ionic bond, the more covalent character of the compound.

21
Q

How does exothermicity and endothermicity of enthalpy of formation act as a qualitative indicator of a compound’s stability?

A

For an exothermic reaction the products are more stable than the reactants.
For an endothermic reaction the reactants are more stable than the products.