Amines Flashcards

1
Q

Classes of amines

A

Number of alkyl groups connected to N atom

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2
Q

N-methylethanamine

A

CH3CH2NHCH3

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3
Q

Chemical test for an amine

A

Conc. HCl gives white fumes

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4
Q

Why propan-1-amine can act as a base

A

It has a lone pair on the N so can accept a proton to form a dative covalent bond

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5
Q

Equation showing propan-1-amine acting as a base

A

CH3CH2CH2NH2 + H2O CH3CH2CH2N+H3 + OH-

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6
Q

Why butan-1-amine is a stronger base than ethanamine

A

Longer carbon chain
Greater electron releasing effect from alkyl group
Lone pair more available to accept a proton

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7
Q

Why is phenylamine a weaker base than ammonia

A

The lone pair is partially delocalised into the benzene ring
Lone pair is less able to accept a proton

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8
Q

Ammonia + bromopropane equation

A

CH3CH2CH2Br + 2 NH3 > CH3CH2CH2NH2 + NH4Br

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9
Q

Roles of ammonia in reaction with bromopropane

A

First acts as a nucleophile attacking 𝛿+ C to replace Br
Then acts as a base accepting a proton from bromopropane

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10
Q

Reaction between ethanamine and bromopropane
Type

A

Nucleophilic substitution

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11
Q

Reaction between ethanamine and bromopropane, Mechanism

A

ethanamine N lone pair > 𝛿+ C
C-Br > Br
N+-H > N+
(:Br-)

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12
Q

Reaction between ammonia and bromopropane
Type

A

Nucleophilic substitution

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13
Q

Reaction between ammonia and bromopropane
Mechanism

A

NH3 lone pair > 𝛿+ C
C-Br > Br
NH3 lone pair > H
N+-H > N+
(+ :Br-)
(+ NH4Br)

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14
Q

Why does NH3 + bromopropane have a low yield

A

Further substitution occurs as product contains a lone pair so can act as a nucleophile
Unless an excess of NH3 is used

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15
Q

Use of quaternary ammonium salt and why

A

Fabric softener - coat fibres with positive charges allowing them to move past each other more easily

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16
Q

Reduction of propanenitrile equation

A

CH3CH2CN + 4 [H] > CH3CH2CH2NH2

17
Q

2 examples of reducing agents in reduction of propanenitrile

A

H2 (g) in a presence of a nickel catalyst
LiAlH4

18
Q

Reduction of nitrobenzene equation

A

{o}/NO2 + 6 [H] > {o}/NH2 + 2 H2O

19
Q

Reducing agent needed for reduction of nitrobenzene

A

Sn or Fe with conc. HCl

20
Q

3 reasons why phenylamine cannot be made by reducing bromobenzene with ammonia

A

C bonded to Br is not 𝛿+
NH3 is a nucleophile
Lone pair on NH3 is repeller by the delocalised ring