Analysis of DNA Length Polymorphism for Applications in Mutant Gene Tracking

Question 1

SNPs due to DNA point variations show only two forms (presence or absence of the base change) and hence, at most, only ____ of the population will be heterozygous at a site.

Answer 1

one - half

Question 2

In using SNPs are genetic markers, if key individuals in a family are ____ for the marker, it can no longer be used for genetic prediction.

Answer 2

homozygous

Question 3

The limitation associated with using SNP as markers can be avoided by the use of ____, which often have multiple alleles and corresponding ____.

Answer 3

DNA length polymorphism; high heterozygosity frequencies

Question 4

____ are tandem repeats under 1 kb in length.

Answer 4

microsatellites

Question 4

What are common repeat motifs for microsatellites?

Answer 4

A; CA; AAN (N is any nucleotide); GA

Question 5

CA repeats commonly have ____ repeats and are found every ____ in the genome.

Answer 5

10-60 repeats; 30 kb

Question 6

In about ____ of individuals, the number of microsatellite repeats differs between the two homologous chromosomes and thus the length of a DNA fragment (generated by PCR or restriction enzyme digestion) that carries the repeat will vary in length.

Answer 6

70%

Question 7

Because of their high variability, ____ can be used to track neighbouring mutant genes within families if when the pathogenic point mutation itself has not been detected.

Answer 7

polymorphic microsatellite DNA