Biological molecules Flashcards

(32 cards)

1
Q

What’s the difference between starch and cellulose molecules?

A

Cellulose is B glucose and starch is A glucose

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2
Q

Explain one way in which starch is adapted for their function in plant cells.

A

•insoluble
OR
•long helix shaped chains that are formed by hydrogen bonds

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3
Q

The enzyme sucrase catalyses the breakdown of sucrose into monosaccharides. What type of reaction is this breakdown?

A

Hydrolysis

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4
Q

Explain how cellulose molecules are adapted for their function in plant cells.

A
  • cellulose chains are long and straight

* create strong cell walls in plants

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5
Q

Describe a biochemical test to find out if the solution collected from an experiment contains glucose and fructose.

A

Benedicts test and heating the solution.

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6
Q

Describe a sample test you would carry out to show that lactose is a reducing sugar.

A

Add benedicts solution and place in a 90 degree water bath for 10 mins, if the solution turns orange/red a reducing sugar is present

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7
Q

Describe how the structure of a phospholipid differs from the structure of a triglyceride.

A

•phospholipids have phosphate and 2 fatty acids

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8
Q

What does the term “unsaturated” mean?

A

Contains a carbon carbon double bond (C=C)

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9
Q

What’s the advantage of writing data sets as percentages?

A

Data can be compared to other data sets

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10
Q

Out of A and B glucose, which can’t be digested? And why?

A

A because the OH’s are both on the bottom side of the molecule at each end meaning the H bond that forms during a condensation reaction isn’t under any strain and is very strong.

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11
Q

Complete these formations:

A) …………. + Glucose —> Maltose
B) Glucose + ………….. —> Sucrose
C) Glucose + Galactose —> ……….

A

A) Glucose
B) Fructose
C) Lactose

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12
Q

What’s the test for non-reducing sugars?

A
  • if sample is not liquid (must be ground up in water)
  • add benedicts and place tube into gently boiling water - if it doesn’t change, reducing sugar is NOT present
  • start with a new sample and add same vol of dil. HCl and place into gently boiling water (for 5 mins)
  • slowly add NaHCO3 (check not alkaline)
  • do benedicts year again on this sample
  • if a non reducing sugar is present the sample will turn orange/brown.
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13
Q

What are the properties of starch?

A
  • insoluble (dosent affect water potential so no osmosis)
  • large and insoluble (can’t diffuse out of cells)
  • compact (for storage)
  • made out of A Glucose (which when hydrolysed can be easily transported and ready for respiration)
  • Many branches (so enzymes can attack with ease meaning glucose monomers are released rapidly)
  • A Glucose
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14
Q

What are the properties of Glycogen?

A
  • insoluble (therefore no osmosis)
  • insoluble (so it dosent diffuse out of cells)
  • Compact (can be stored in small places)
  • Very branched (more than starch) therefore more ends can be acted on simultaneously by enzymes therefore bore rapidly broken down to form glucose monomers which are used in resp. — this is important for animals that have a high metabolic rate so they need more energy quicker •A glucose
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15
Q

What Properties of cellulose?

A
  • B glucose
  • straight
  • unbranched (allowing links between chains)
  • every other molecule flips in the chain
  • run in parallel chains
  • these chains are grouped to form microfibrils which turns into fibre
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16
Q

What’s fibre made out of? Why can’t it be digested?

A
  • made out of Cellulose (A Glucose) bunched together to form microfibrils
  • cant be digested bc A glucose’s structure doesn’t allow enzymes to access the bonds very easily and the bonds aren’t under any stress (due to the structure again)
  • no branches therefore less access point to the bonds for the enzymes to hydrolyse
17
Q

What are the roles of lipids?

A
  • source of energy
  • waterproofing
  • insulation
  • protection
18
Q

Explain the structure of Triglycerides.

A

Glycerol + 3 fatty acids

19
Q

How’s the structure of triglycerides related to their properties?

A
  • they have a high ratio of energy stirring C-H bonds therefore excellent at STORING ENERGY
  • low mass to energy ratio, therefore they’re GOOD STORAGE MOLECULES
  • Large and non polar therefore INSOLUBLE
  • their storage dosent effect the water potential in the cell
20
Q

Describe the structure of phospholipids.

A
  • Hydrophilic phosphate head

* Hydrophobic fatty avid tail

21
Q

What’s the test for lipids?

A
  1. Take completely dry and grease free test tube and add 2cm^3 of sample to test tube
  2. Add 5sm^3 ethanol
  3. Shake to dissolve any lipids in sample
  4. Add 5cm^3 of water and shake gently
  5. Cloudy white = lipids present
22
Q

What are the 4 chemical groups attached to the central carbon to form amino acids?

And describe the structure of the molecule.

A

•amino group
•carboxyl group
•R group H H
•hydrogen atom \ /
N
|
R—C—H
|
C
// \
O OH

23
Q

How does a peptide bond form?

A

Through a condensation reaction:
•the carboxyl group at the bottom of the molecule lines up with the amino group on the top of the second
•a bond between the C and N on opposing molecules forms
•This is called a peptide home

24
Q

Describe the structure of primary protein.

A
  • Sequence of amino acids

* determines the ultimate shape of the protein

25
Describe the structure of a tertiary protein.
* disulphide bridges * ionic bonds * hydrogen bonds
26
What’s the difference between quaternary and tertiary structure?
•quaternary has many chains and prosthetic groups attached
27
Describe secondary structure.
* A helix | * peptide chains
28
What’s the test for proteins and describe it.
* place sample into test tube and add an equal amount of NaOH at RTP * add a few drops of very dilute Cu(ll)SO4 solution and mix gently * purple means presence of peptide bonds therefore protein
29
``` Lols enzyme graph | _____________ | / | / | / | / |/_____________________ ``` Explain why the rate of the reaction decreases as the reaction progresses.
* bc the substrate runs out | * therefore no enzyme substrate complexes can be formed
30
Why is there a use for an enzyme buffer during reactions?
To control the pH
31
Explain how enzyme inhibitors affect the rate of reaction. | [6 marks]
Competitive inhibitors •similar molecular shape to substrate therefore bind to the active site and preventing ESC’s to be formed. Non competitive inhibitors •attach to a binding site that’s not the active site therefore altering the tertiary stricture of the enzyme and thus it’s active site meaning the substrate no longer fits, preventing ESC’s to be formed.
32
In humans, the enzyme Maltase breaks down maltose to glucose. This takes place at normal body temperature. Explain why: • only breaks down maltase • allows this reaction to take place at normal body temp.
* maltose has tertiary structure * complimentary active site shape * forms an enzyme substrate complex * (description of enduced fit) * enzyme binds * enzyme changed shape * stress on bonds * enzymes lower activation energy (act as a catalyst)