Chapter 1: Flashcards

(33 cards)

1
Q

Ground state:

A

The state of an atom at its lowest energy, where all electrons are in the lowest possible orbitals.

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2
Q

Excited state:

A

An atom in a state where at least one electron has moved to a subshell of higher than normal energy.

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3
Q

Define effective nuclear charge - Zeff:

A

The net positive force experience by an electron, determined by the number of protons and the shielding effect by electrons in lower orbitals.

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4
Q

An electron in a 1s orbital would have the highest effective nuclear energy in which of the following elements?

a. H
b. Na
c. Cl
d. O

A

Cl - Because the Zeff depends on number of protons and shielding by electrons in lower orbitals. Since it is in 1s - the lowest possible oribital - the only thing to consider is protons. Cl has the greatest number of protons - with 17.

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5
Q

What fraction of 125I decays in 180 day, if it’s half life is 60 days?

A

In 180 days, 3 half lives will occur. So the total amount that will decay is:

1-(1/2)^3 = 7/8

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6
Q

B-decay:

A

The number of protons decreases by 1.

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7
Q

Gamma decay:

A

The emission of a high energy photon - does not create a new element.

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8
Q

If Sulfer goes through B-decay twice, and then gamma decay one, what atom will result?

A

Silicon.

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9
Q

Alpha decay:

A

An atom loses two protons and two neutrons.

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10
Q

If arsenic goes through 1 alpha decay and 1 beta decay, what atom will result?

A

Zn.

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11
Q

Maximum number of electrons in a S subshell:

A

2

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12
Q

Maximum number of electrons in a P orbital:

A

6

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13
Q

Maximum number of electrons in a D orbital:

A

10

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14
Q

Maximum number of electrons in a F orbital:

A

14

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15
Q

What is the ratio of the maximum number of electrons in an F orbital compared to a D orbital:

A

14/10

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16
Q

Which of the following is the correct electron configuration for Zn2+:

a. 1s^2, 2s^2, 2p^6, 3s^2, 3P^6, 4s^0, 3d^10
b. 1s^2, 2s^2, 2p^6, 3s^2, 3P^6, 4s^2, 3d^8
c. 1s^2, 2s^2, 2P^6, 3s^2, 3P^6, 4s^2, 3d^10.

17
Q

Which of the following quantum number sets is possible:

a. n = 2; l = 2; ml = 1; ms = +1/2
b. n = 2; l = 1; ml = -1; ms = +1/2.
c. n = 2; l = 0; ml = -1; ms = - 1/2
d. n = 2; l = 0; ml = 1; ms = -1/2.

A

b -
1. Azimuthal quantum number (l) cannot be higher than n.
2. ml can only be an integer number between -l and l -

18
Q

What is the maximum number of electrons allowed in a single atomic energy level in terms of the principal quantum number (n)?

a. 2n
b. 2n + 2
c. 2n^2.
d. 2n^2 + 2

19
Q

Which of the following equations describes the maximum number of electrons that can fill a subshell:

a. 2l + 2
b. 4l + 2
c. 2l^2
d. 2l^2 + 2

20
Q

Which of the following atoms only has paired electrons in its ground state:

a. sodium.
b. iron.
c. cobalt.
d. helium.

21
Q

What is the proper electron configuration of Ti(2+)?

  1. 1s^2, 2s^2, 2p^6, 2d^10.
  2. 1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 4s^2.
  3. 1s^2, 2s^2, 2p^6, 3s^2. 3p^6, 3d^2.
  4. 1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 4s^2, 3d^2.
A

3 - 1s^2, 2s^2, 2p^6, 3s^2, 3p^6, 3d^2.

This is because neutral Ti has 22 protons and electrons, so Ti2+ must have 20 electrons. Even though on neutral Ti, 4s^2 would come first, when removing electrons, they would remove from the 4 level before the 3 level.

22
Q

Researchers are interested in discovering new elements to be used as a source of nuclear energy through an alpha decay process. They begin by analyzing Silicon. What is this elements electron configuration.

  1. 1s^2, 2s^2, 2p^6, 3s^2, 3p^2.
  2. 1s^2, 1p^6, 1d^6.
  3. 1s^2, 2s^2, 2p^6, 3s^2, 3p^6.
  4. 1s^2, 2s^2, 2p^4, 3s^2, 3p^4.
A
  1. 1s^2, 2s^2, 2p^6, 3s^2, 3p^2.

Silicon has 14 protons, so neutral silicon would have 14 electrons. #1 is the onyl one that is formatted properly.

23
Q

How does the angular momentum (azithumal) quantum number (l) relate to the prinicple quantum number (n)?

A

l = n -1 ALWAYS

24
Q

An angular momentum (azithumal) quantum number of 0 corresponds to what type of oribital?

A

A spherical S oribital

25
An angular momentum (azithumal) quantum number of 1 corresponds to what type of oribital?
P - dumbell orbital.
26
An angular momentum (azithumal) quantum number of 2 corresponds to what type of oribital?
A four-leaf clover D orbital
27
An angular momentum (azithumal) quantum number of 3 corresponds to what type of oribital?
A 6 leafed F oribital
28
What is the magnetic quantum (ml) number and how does it relate to the angular momentum quantum number (l)
Magnetic quantum number (ml) tells us all of the possible orientations of an orbital. This is eqault to any values between -l and +l. l = 1 ml = -1, 0, +1 = 3 possible orientations.
29
What is the angular momentum (azithumal) quantum number (l) and how does it relate to the principle quantum number (n)?
The angular momentum quantum number (l) tells us the shape of an orbital. This is always equal to n-1. n =1 l = 0 shape = s (sphere) n=2 l = 1 shape = p (dumbell) n = 3 l = 2 shape = d (four leaf clover) n = 4 l = 3 shape = f (6 leafed)
30
What is the principle quantum number, and what are its possible values?
The principle quantum number tells us what energy level (shell) an electron is in, which measures size of the atom as higher energy levels will be farther away from the nucleus. This can be any positive integer.
31
As the principle quantum number increases: a. The size of the atom decreases. b. The shape of the orbital changes. c. The spin of the electron swaps direction. d. The size of the atom increases.
d - the size of the atom increases.
32
What is the magnetic spin number (ms) and what are its possible values?
The magenetic spin number tells us the direction an electron is spinning in its oribital. This can either be +1/2 (up spin) or -1/2 (down spin).
33
What are the four quantum numbers for the last electron added in a nitrogen atom (atomic number 7)?
**n = 2, ℓ = 1, mℓ = +1, ms = +½** Nitrogen (Z = 7) has 7 electrons. The electron configuration is: 1s² 2s² 2p³ Principal quantum number (n): The 2p orbital → n = 2 Angular momentum quantum number (ℓ): For a p orbital → ℓ = 1 Magnetic quantum number (mℓ): For ℓ = 1, mℓ can be -1, 0, or +1. Since there are 3 electrons in 2p, they will each occupy a separate orbital (Hund’s Rule). Let’s say the last one enters the mℓ = +1 orbital → mℓ = +1 Spin quantum number (ms): As the orbital is half-filled first, the spin will be +½ → ms = +½