Chapter 11 Flashcards

1
Q

intermolecular forces

A

hold any 2 molecules together; weaker than intramolecular forces

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2
Q

intramolecular forces

A

hold 2 same atoms together
- covalent, ionic, metallic

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3
Q

↑ boiling/melting point = ___IMF

A

↑ IMF

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4
Q

↑ surface tension = ___IMF

A

↑ IMF

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5
Q

↑ viscosity = ___ IMF

A

↑ IMF

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6
Q

↑ capillary action = ___ IMF

A

↑ IMF

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7
Q

↑ volatility = ___ IMF

A

↓ IMF

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8
Q

↑ vapor pressure (ideal gas law) = ___ IMF

A

↓ IMF

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9
Q

Viscosity

A

resistance of a liquid to flow

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10
Q

Surface tension

A

surface of water behaves like elastic

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11
Q

Cohesive forces

A

forces bind similar molecules
- ex: hydrogen bonding in water

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12
Q

Adhesive forces

A

forces bind substance to surface

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13
Q

Capillary action

A

rise of liquids up very narrow tubes

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14
Q

Thermodynamically favored phase

A

least costly phase for 1 material

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15
Q

metastable phase

A

less costly phase, but less stable

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16
Q

Phase change

A

change of state of pure substance by heating or cooling

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17
Q

solid –> liquid

A

melting (fusion)

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18
Q

liquid –> gas

A

vaporization

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19
Q

gas –> solid

A

deposition

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20
Q

solid –> gas

A

sublimination

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21
Q

Heat (Enthalpy) of fusion

A

↑ freedom of motion of particles requires energy
- ex: boiling water

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22
Q

Maxwell Distribution

A

velocities of molecules in vapor phase @ given temp are diff
- relates temp to particles and velocity
- bell curve

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23
Q

Phase Diagram

A

summarizes conditions under equilibria b/w diff states of matter

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24
Q

Critical point

A

at/above only 1 gas-like phase exists
- no surface tension

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25
Triple point
all 3 phases coexist in equilibrium: - all 3 curves intersect - doesn’t matter what phase
26
Permanent gases
substance w/ critical point ↓ than room temp - Helium, hydrogen, nitrogen, argon, oxygen
27
Clausius Clapeyron Equation (constraint of coexistence): R =
8.314 J/mol*K = 8.34 x 10^-3 KJ/mol*K
28
Clausius Clapeyron Equation (constraint of coexistence): pressure =
1 atom = 101 kPa
29
Clausius Clapeyron Equation (constraint of coexistence): T =
temp in Kelvin
30
4 main classes of materials (compounds):
ionic compounds, metals, network covalent, molecular
31
ionic compounds
Electrostatic attraction b/w cation and anion: - ability to form crystals - ↑ enthalpies of fusion/vaporization - ↑ melting/boiling points - hard - conduct electricity - stronger than covalent bonds
32
metals
Collectively share valence e-: - ↑ melting/boiling points - shiny - hard - good heat conductors
33
network covalent
- Compound w/ atoms bonded by covalent bonds in a continuous network - weak interactions - covalent bonds extend throughout large region; many repeating units - crystals; often oxides or sulfides - = rate A common: Si, SiC, SiO2 (quartz), C (diamond), C (graphite), BN, Ge
34
molecular
- Doesn’t conduct electricity - insoluble in water (soluble in nonpolar solvents) - smelly (volatile) - ↓ melting/boiling points
35
Dispersion force
instantaneous dipole on one atom causes atoms to be attracted - all interactions b/w dipole forces - ALL molecules have dispersion forces
36
↑ molar mass =
↑ dispersion force = ↑ boiling point
37
dispersion force: D(t) =
q(t) *R - R = distance/length of molecule -larger molecule = stronger force
38
Dipole force
polar molecules with +/- ends
39
Dipole-dipole interactions
presence of permanent dipole moment in a polar molecule
40
Ion-dipole force
b/w ion and polar molecule - cation (+) attracted to (-) end of dipole - anion (-) attracted to (+) end of dipole
41
critical temp
highest temp a liquid phase can form
42
critical pressure
pressure required to liquify at critical temp - ↑ intermolecular forces = ↑ critical temp of substance
43
Vapor pressure
pressure of vapor attains constant value
44
most ionic (most polar)
atoms in molecule further apart on PT = more ionic
45
Hydrogen bonds...
increase boiling point
46
Hydrogen bonds...
increase boiling point
47
↑ heat of fusion (enthalpy to melt) = ___ IMF
↑ IMF
48
boiling point: polar molecule ___ nonpolar molecule
>>>
49
hydrogen bonding:
bond b/w X-H: - X = N, O, F - R-X-H:---------:X-H
50
hydrogen bonding attractive forces
all 3: dispersion, dipolar (dipole-dipole), hydrogen bonding
51
H bond affects boiling point how?
↑ attraction (bc of all 3 forces) = ↑ boiling point
52
if an atom has at least 1 hydrogen bond it must...
have all 3 attractive forces (dispersion, dipolar, hydrogen bonding)
53
forces by molecule: nonpolar molecules
dispersion forces
54
forces by molecule: polar molecules
dispersion forces + dipole/dipole = ↑ boiling p.
55
forces by molecule: hydrogen bonding in molecule
dispersion forces + dipole/dipole + hydrogen bonding
56
What elements form a hydrogen bond w/ H?
N, O, F
57
how does a hydrogen bond impact boiling point?
increases
58
nonpolar solvents...
will NOT dissolve in water
59
solvents with 5+ C's...
will NOT dissolve in water
60
polar solvents...
WILL dissolve in water
61
hydrophilic molecules
- cation + anion - charged ions polar molecules
62
hydrophobic molecules
hydrocarbons and nonpolar molecules
63
Molecules w/ hydrophobic and hydrophilic parts:
- Still soluble; increased C = less soluble - 5+ C = not soluble
64
↑ in carbon chains = ↓ in
in solubility in water