Chapter 4 Flashcards

1
Q

Exterior Angle Theorem

A

The angle formed when you extend the side of a triangle is equal to the sum of the non-adjacent interior angles

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2
Q

Exterior Angle Theorem Formula

A

m<c’=m<a+m<b

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3
Q

Pythagorean theorem

A

a^2+b^2=c^2

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4
Q

SohCahToa

A

Sin=o/h
cos=a/h
tan=o/a

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5
Q

Law of Sines

A

a/sinA=b/sinB=c/sinC

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6
Q

Law of sines ambiguous case formulas

A

B.1= sin-1(bsinA/a)
B.2= 180-sin-1(bsinA/a)

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7
Q

When to use law of sines

A

when you have AAS, ASA, or SSA

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8
Q

When does the ambiguous case happen?

A

when the opposite side is longer than the amplitude but shorter than the other side.
b<h<a

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9
Q

How to solve ambiguous case?

A

1). find h using sohcahtoa
2). use law of sines to find first angle, using inverse function.
3). Use algebra and 180 rule to find the other angle.

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10
Q

The Law of Cosines (ALL 3)

A

a^2=b^2+c^2-2bc CosA
b^2=a^2+c^2-2ac CosB
c^2=a^2+b^2-2ab CosC

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11
Q

Oblique Triangle

A

Any triangle that is not a right triangle

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12
Q

Pythagorean theorem proof

A

1). Draw 2 squares (one inside of another)
2). Outside one has (b,a) on all 4 sides
3). inside one has “c” on all 4 sides
4) A1=(a+b)^2
5).A2= c^2
6). At=ab/2 all 4= 4(ab/2)==2ab
7). A1=A2+2ab
8). a^2+b^2+2ab=c^2+2ab

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13
Q

The angle bisector

A

An angle bisector divides the opposite side of a triangle into two segments that are proportional to the triangles other two sides.

Formula = AB/BD==AC/CD

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14
Q

Angle bisector proof

A

1). with triangle ABC extend AD to AF
2). Add a line parallel to AB connecting to C
3). Alternate interior angles BAD,DFC are congruent and DFC,CAD
4). ACF is isosceles because AC=FC
5). ADB=CDF - vertical angles
6). Triangles ADB and FDC are similar by AA. thus AB/BD==AC/CD

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15
Q

Geometric construction

A

Need only a compass and a straight edge

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16
Q

Perpendicular bisector theorem

A

If a point is on the perpendicular bisector of a segment then it is equidistant from the segments end points

17
Q

Proof and converse proof

A

Review in notebook