Chapter 5 Geometry of regular surfaces Flashcards

(82 cards)

1
Q

intrinsic geometry

A

intrinsic geometry, that is the study of geometric properties
that are seen by the inhabitants of a surface only.

e.g if we bend a surface the length of curve wont change from point of observers geometry wont change but the shape of surface changes

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2
Q

dot product

A

in R^n is a positive definite symmetric bilinear form on R^n

dot prod refers to notion of chosen basis
for any scalar product B on R^n there exists basis
e_1‾,….,e_n‾ s,t for any vectors u and v in R^n

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3
Q

symmetric bilinear form,

A

Let V be a finite-dimensional vector space. A map B : V × V → R is called a symmetric bilinear form, if it satisfies the following properties

(i) B(α1u1 + α2u2, v) = α1B(u__1, v) + α2B(u2, v) for any vectors u1, u2, and v ∈ V , and any real
numbers α1 and α2;

(ii) B(u, v) = B(v, u) for any vectors u and v ∈ V

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4
Q

positive definite

A

A symmetric bilinear form B on a vector space V is called positive definite (or a scalar product), if B(u, u) > 0 for any u ∈ V , and B(u, u) = 0 if and only if u = 0

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5
Q

matrix of the basis

A

by property 2: symmetric b_ij=b_ji for any i and j

A MATRIX CAN REPRESENT BILINEAR FORMS

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6
Q

First Fundamental Form G

A

(RESTRICTION to the tangent space of the dot prod from euclidean spae R^n)

on a regular surface Σ^n ⊂ R^m is a family of scalar products G_p : T_pΣ^n×T_pΣ^n → R (that is a family of positive definite symmetric bilinear forms), where

p ranges over Σ^n, such that
G_p(X, Y ) = X · Y for any X, Y ∈ T_pΣ^n and any p ∈ Σ^n
——————————–

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7
Q

Let P_n be space of polynomials
f:R to R whose degree not greater than n
is this a positive definite symmetric bilinear form on P_n:
B(f,g) =∫_{0,1} f(t)g(t).dt

A

We claim that the scalar product B is
uniquely determined by the matrix bij = B(ei
, ej ), where i, j = 1, . . . , n. Indeed, for any vectors u and v ∈ V by properties (i) and (ii)

B(u,v) = sum_i,j b_ij u_i v_j
Thus, we conclude that the value B(u, v) can be computed from the knowledge of the matrix (bij ), and the claim holds.

checking linear wrt first var
non neg integral is non neg

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8
Q

measuring length of vector in Bilinear form

distance and angles

A

given vector in V
length in sense of given bilinear form

they can also imply cs
b(u,v) <= sqrt (B(u,u) B(v,v))

so we can do everything that we can in euclidean space

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9
Q

CS bilinear form

A
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10
Q

bilinear triangle inequality

A
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11
Q

interested inpath length?
We are concerned with computing
the lengths of curves on surfaces Σ^n ⊂ R^m

A

Let γ : [a, b] → R^m be a PC such that γ(t) ∈ Σ
n for any t ∈ [a, b]. As we know, the length of γ is given by the formula
L(γ) = integral_[a,b] |γ’(t)| dt.

Since γ lies in Σn, the velocity vector γ’(t) lies in the tangent space Tγ(t)Σ^n; due Definition IV.15
(to show γ’(t) lies in tangent space sufficient to construct generating curve γ~ :(-e,e) to surface s,t γ~(0)=p and γ~’(0)=γ’(t)

we are interested in the geometry of the surface ie being able to compute lengths of paths that lie in surface

and hence we only need to know values |X| for |X| in the tangent space for all p in the surface
(speeds lengths for tangent vectors AND THATS ALL WE NEED TO KNOW)

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12
Q

Consider the space P_2 of polynomials f : R → R whose degree is not greater than two. Pick a basis in this space and compute the matrix of the form given by formula corresponding to it

what is dimension of this space?

A

what is dimension of this space?
basis consists of 3 polynomials so it is 3
basis
(1,t,t^2)
compute
matrix of
B(f,g) = integral_[0,a] f(t)g(t).dt in this basis

bij = B(ei, ej )
integrating
1, t, t^2
t, t^2, t^3
t^2, t^3, t^4

integrating over [0,1]

[ 1 1/2 1/3]
[1/2 1/3 1/4]
[1/3 1/4 1/5]

on 6 components

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13
Q

MATRICES AND COMPUTATION

A

for some chart (U,phi,V) around p in Σ^n
we have a CANONICAL BASIS
X_i(p) = D_x(ϕ(e_i)) = ∂ϕ/∂xi(x),

of tangent space and we may compute corresponding matrix in this chart

we obtain
gij (ϕ(x)) = G_ϕ(x) (Xi, Xj ) = ∂ϕ/∂xi(x) ·∂ϕ/∂xj
(x)

if p lies in this chart then
D_x(ϕ) :R^n to tangent space
is a linear isometry
in maps the standard basis in R^n to the tangent space spanned by above

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14
Q

THE FIRST FUNDAMENTAL FORM

A
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15
Q

for a given chart the first fundamental form

A
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16
Q

G_p for a given point on surface and basis

A
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17
Q

Using the First Fundamental Form we can now re-write the formula for the length of a curve on
Σn in the following fashion:

A

L(γ) = integral_[a,b]
SQRT(Gγ(t)(γ’(t), γ’(t))dt.

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18
Q

so how would we compute the arc length? of a curve

if you are inhabitant of the surface and you dont know the formula, directions and lengths of tose directions not tangent to surface

A

gij (ϕ(x)) = G_ϕ(x) (Xi, Xj ) = ∂ϕ/∂xi(x) ·∂ϕ/∂xj
(x) we know

could write coordinates on surface
ϕ-1 . γ(t) = (γ¹(t),…, γⁿ(t))

speed of tangent vector: in terms of first fundamental form speed would be
|γ’(t)|_R^n = sqrt(G_γ(t)( γ’(t), γ’(t))

so using this into integral of:
sqrt[sum_ij (gij(γ¹(t),…,γⁿ(t))) dγ^i/dt (t)dγ^j/dt(t) ].dt

FORMULA FOR THE LENGTH FOR __SURFACE
has no idea what R^n is

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19
Q

Let Σn ⊂ R^{n+1} be a graph of a smooth function f : Ω → R, that is the set
Σ^n = {(x, f(x)) : x ∈ Ω}.

using charts

A

we have only one chart (Ω, ϕ, Ω×R), where the map
ϕ : Ω → Ω×R is given by
ϕ(x) = (x, f(x)).
(cylinder Ω×R

Using relations
X_i(p) = D_x(ϕ(e_i)) = ∂ϕ/∂xi(x),
=(0,…,1,0,..,0,∂f/∂x_i), for ith place
we obtain the following formula for the matrix of the first fundamental form:
g_ij (ϕ(x)) =
∂ϕ/∂xi(x) ·∂ϕ/∂xj(x)
=X_i . X_i
= δ_ij +∂f/∂xi(x) ∂f/∂xj(x),
where i, j = 1, . . . , n, and
δij is the Kronecker delta. δij = 1 iff i = j,

in this e.g if f(x) =c constant the surface is just the plane itself, so becomes identity matrix as the euclidean matrix

e.g f(x,y)=x^3+y^3 decide on curve (t,0)
inhabitants see, but if we live in R^3 for us the curv will be gamma(t)=(t,0, t^3 +0)
g_ij (ϕ(x)) =
= δ_ij +∂f/∂xi(x) ∂f/∂xj(x),
…9x^2 etc

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20
Q

matrix representation

A

The family of matrices (gij ) ◦ ϕ defined by relation (V.7) is called the matrix
representation of the first fundamental form in a given coordinate chart (U, ϕ, V ) on a regular surface Σ^n ⊂ R^m.

(not discussed)

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21
Q

e.g
Unit sphere S^n ⊂ R^{n+1). Consider a unit sphere S^n ⊂ R^{n+1}

A
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22
Q

Hyperplace subset viewed as graph of 0 function

A
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23
Q

why is first fundamental form useful?

INNER GEOMETRIC

A

geometric properties/quantaties of a regular surface that are determined by the first fundamental form only are called intrinsic or INNER GEOMETRIC

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24
Q

INTRINSIC DISTANCE FUNCTION

A

an example of an intrinsic quality

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25
example instrinsic distance function on unit sphere **SPHERICAL DISTANCE**
26
PROP 5.1 **inequality for intrinsic distance**
it has constant speed then using CS inequality and corollary 2.22
27
example: on a plane the instrisic distance coincides with euclidean distance
the inequality might be strict only for a curved shape
28
LOCAL ISOMETRY BETWEEN SURFACES
29
when is a local isometry a GLOBAL ISOMETRY
A local isometry is called a global isometry if it is a bijective map between surfaces
30
REMARKS ABOUT ISOMETRIES relationships first fundamental forms
31
example for an ORTHOGONAL TRANSFORMATION map restricted is a GLOBAL ISOMETRY OF THE UNIT SPHERE
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example: PLANE AND CYLINDER REGULAR 2 DIM SURFACES SHOW THERE IS A LOCAL ISOMETRY BETWEEN THE TWO
33
INTRINSIC QUALITY AND GLOBAL ISOMETRY
Using the notion of isometry, one can re-state Definition V.9 in the following form: a geometric quantity is called intrinsic if it is ”preserved” by all global isometries.
34
PROPN 5.2 local isometry instrinsic distance functions inequality
35
corollary 5.3 GLOBAL ISOMETRY and intrinsic distance
36
COROLLARY 5.4 **global isometry** **Euclidean isometry** did he go over these?
Corollary V.4. Let Φ : R^n → R^n be a smooth map. Then Φ is a **global isometry** of R n in the sense of Definition V.13 if and only if it is a **Euclidean isometry** in the sense of Definition I.20.
37
hypersurface
regular surfaces whose dimension is one less than the dimension of the ambient space
38
**GAUSS MAP** Is applied to a hyperspace units nomal field
diagram: VECTORS coming out at different points on surface p N_p and q N_q these form our unit normal field
39
EXAMPLE of **GAUSS MAP** of the unit sphere
40
further on example of S^n in R^{n+1) sphere
given this surface this example will have tangent space thus giving the normal fields on p with different orientations N(p) =p is a unit normal field the Gauss map coincides with identity N(p)-p is another unit normal field corresponding gauss map is called antipodal map
41
**SHAPE OPERATOR**
42
**propn shape operator is self adjoint**
eigenvalues always real
43
self-adjoint linear operator
44
**SHAPE OPERATOR PROPERTIES** PRINCIPLE CURVATURES MEAN CURVATURES GAUSS CURVATURES
45
UNIT SPHERE shape operator principle curvatures mean gauss curvature
differwntial N_1 =-id as k_n(p)=-1 D_p N_2=id
46
HYPERPLANE shape operator principle curvatures mean gauss curvature
Can you see that principal curvatures in Definition V.19 depend on an orientation on Σn? More precisely, can you see that principal curvatures change sign when a unit normal field N is replaced by −N? reversed orientation changes sign of principle curvatures
47
**SECOND FUNDAMENTAL FORM**
48
COROLLARY 5.6 second fundamental form for tangent vectors XY for a regular hypersurface oriented by unit normal N
49
COROLLARY 5.7 proving the PROP 5.5
50
PROPN 5.8 relationship between (b_ij) gauss curvature and g_ij useful?
51
SUMMARY properties of sec fund form
52
applying our useful relations: EXAMPLE cylinder
53
CYLINDER EXAMPLE notes
54
cylinder example working out partial derivs
spent all lecture...
55
gauss curvature: plane and cylinder locally isometric their curvatures related?
56
instrinsic? curvatures?
the principal curvatures, mean curvature (and hence, the shape operator and second fundamental form) are not intrinsic geometric quantities. GAUSS CURVATURE IS
57
Theorem V.9 (Theorema Egregium)
58
summary
59
EXAMPLE: using Theorem V.9 (Theorema Egregium) on eucludean plane and sphere
60
thm gauss curvature vanishes then
61
rotation index visually: with signed curvature
62
L5: missing recording lecture
COVARIANT DERIVATIVE AS INTRINSIC DERIVATIVE SECTION
63
l5: PRE SECTION I MISSED
64
L5 prop 5.1:
65
**LIE BRACKET** and properties
IT DOESNT DEPEND ON GEOMETRY OF SURFACE AND IF IS DIFFEOMORPHISM...
66
LIE BRACKET properties
67
lie bracket example from lecture
68
**C(surface^n)**
69
**CURVATURE TENSOR) level 5**
measures how far the separation
70
**CURVATURE TENSOR PROPERTIES** prop 5.2
e.g multiplied by function factors out.... R is an intrinsic geometric quantity
71
corollary 5.3 another curvature tensor
missed
72
remark
for Euclidean spaces the curvature tensor vanishes identically. Computation of the curvature tensor for general surfaces can be a highly non-trivial problem. Later we will see that for two-dimensional surfaces in R^ 3 the curvature tensor is entirely determined by the Gauss curvature
73
example: curvature tensor for n dimensional euclidean space covered by a chart
missed
74
PROPN 5.4 local isometry and relationships missed
75
PROP 5.5 THE CURVATURE TENSOR OF A REGULAR N DIM SURFACE SATISFIES (l5)
missed
76
PROPN 5.6 GAUSS EQUATIONS will this be on exam?
gone through with proof
77
gauss equation from lecture
USES PROPN 5.6!! Tangent vectors will give 0
78
PROP 5.7 shape operator satisfies equations GAUSS EQUATION
79
propn 5.8 (Theorema Egregium)
80
level 5 e.g summary 1 for notes
computing these is hard: THIS THM IS INTERESTING FOR DIMENSION 2
81
COROLLARY 5.9 LOCAL ISOMETRY AND GAUSS CURVATURE
gone through in lecture and proven
82
EXAMPLE