Chapter 8 Flashcards

1
Q

What is primary gas that causes global warming?

A

CO2

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2
Q

Gasoline is C8H18(l). Write equation for its combustion in CO2(g) and H2O(g)

A

2 C8H18(l) + 25 O2(g) –> 16 CO2(g) + 18 H2O(g)

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3
Q

The numerical relationship between the chemical quantities in a blanced chemical equation is called?

A

reaction stoichiometry

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4
Q

In the reaction 3 H2(g) + N2(g) –> 2NH3(g) what is the molar ratio?

A

3 mol H2: 1 mol N2: 2 mol NH3

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5
Q

In the reaction 3 H2(g) + N2(g) –> 2NH3(g) if 9 moles of H2(g) reacts how many moles of NH3(g) are produced?

A

6

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6
Q

In the reaction 2 Na(s) + Cl2(g) –> 2NaCl(s), how many moles of NaCl are produced with 3.4 moles of Cl2(g)?

A

6.8 moles

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7
Q

In the reaction 2 C8H18(l) + 25 O2(g) –> 16 CO2(g) + 18 H2O(g) which consumes 500 g of C8H18(l), how much CO2(g) is produced?

A

1500 g CO2(g)

since

1 mole C8H18 = 114.3 g

2 moles C8H18 –> 16 moles CO2

1 mole CO2 = 44.01 g

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8
Q

In the reaction 6 CO2(g) + 6 H2O(l) –> 6 O2(g) + C6H12O6(aq), how many grams of glucose can be obtained from 58.5 g of CO2?

A

39.9 g C6H12O6

since

1 mol CO2 = 44.01 g

6 mol CO2 –> 1 mol C6H12O6

1 mol C6H12O6 = 180.2 g

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9
Q

In the reaction 4 NO2(g) + O2(g) + 2 H2O(l) –> 4 HNO3(aq), how much HNO3 is proudced for 1.5 x 103 kg of NO2?

A

2.1 x 103 kg HNO3

since

1000 g = 1 kg

1 mol NO2 = 46.01 g

4 mol NO2 –> 4 mol HNO3

1 mol HNO3 = 63.02 g

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10
Q

In the reaction Ti(s) + 2 Cl2(g) –> TiCl4(s), if there are 1.8 mmol of Ti and 3.2 mol of Cl what is limiting reactant and the theoretical yield of TiCl4?

A

stoichiometric ratio

1 Ti : 2 Cl2 : 1 TiCl4

  1. 8 mol Ti –> 1.8 mol TiCl4
  2. 2 mol Cl2 –> 1.6 mol TiCl4

so limiting ractant is CL2 and theoretical yield is 1.6 mol TiCl4

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11
Q

In the reaction 2 Al(s) + 3 Cl2(g) –> 2 AlCl2(s) with 0.552 mol of Al and 0.887 mol of Cl2 what is limiting reactant and theoretical yield of AlCl2?

A

stoichiometric relation

2 mol Al : 3 mol Cl2 : 2 mol AlCl2

  1. 552 mol Al –> 0.552 AlCl2
  2. 887 mol Cl2 –> 0.591 mol AlCl2

limiting reactant is Al; theoetical yield of ALCL2 is 0.552 mol,

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12
Q

In the reaction 2 Na(s) + F2(g) –> 2 NaF(s), if there are 4.8 mol of Na and 2.6 mol of F2 what is limiting reactant and theoretical yield of NaF?

A

stoichiometric ratio

2 Na : 1 F2 : 2 NaF

  1. 8 mol Na –> 4.8 mol NaF
  2. 6 mol F2 –> 5.2 mol NaF

Na is limiting reactant and theoretical yield is 4.8 mol NaF.

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13
Q

In the reaction 2 NO(g) + 5 H2(g) –> 2 NH3(g) + 2 H2O(g) what is maximum amount of ammonia in grams that can be formed from 45.8 g NO and 12.4 g H2?

A

Molar mass: NO 30.01 g/mol, H2 2.02 g/mol, NH3 17.04 g/mol

Stoichiometric ratio: 2 NO : 5 H2 : 2 NH3 : 2H2O

  1. 8 g NO –> 26.0 g NH3
  2. 4 g H2 –> 41.8 g NH3

NO is limiting ractant and only 26.0 g NH3 can be formed

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14
Q

In the reaction Cu2O(s) + C(s) –> 2 Cu(s) + CO(g) when 11.5 g of C racts with 114.5 g Cu2O, 87.4 g of Cu are obtained. What is the limiting reactant, theoretical yield and percent yield?

A

Molar mass: C 12.01 g/mol, Cu2O 143.10 g/mol, Cu 63.55 g/mol

Stoichiometric ratio: 1 Cu2O : 1 C : 2 Cu : 1 CO

  1. 5 g C –> 122 g Cu
  2. 5 g Cu2O –> 101.7 g Cu

Cu2O limiting reactant with a theoretical yield of 101.7 g

percent yield = 87.4/101.7 = 85.9%

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15
Q

In the reaction C3H8(g) + 5 O2(g) –> 3 CO2(g) + 4 H2O(g) Hrxn = -2044 kJ assume 1.18 x 104 g of C3H8 are burned how much heat is released?

A

Molar mass C3H8 44.11 g/mol

1.18 x 104 g C3H8 = 268 mol ofC3H8

Heat released = 268 * 2044kJ = 5.47 x 105 kJ

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