Chapter 9 enthalpy Flashcards
(15 cards)
Define the term enthalpy of combustion
- is the enthalpy change when one mole of a substance
- is burned completley in oxygen
- under standard conditions (298K and 100 Kpa)
Write the equation for the standard enthalpy change of combustion of propan-1-ol C3H7OH
C3H7OH (l)+4.5O2 (g) ->3CO2 (g) +4H2O (l)
Suggest two reasons for the difference between this value and the one he obtained experimentally
- conditions are not standard
- heat loss
- incomplete combustion
Define the term enthalpy of formation
- is the enthalpy change when one mole of a compound is formed from its constituent elements in their standard stated under standard conditions
Write and equation including state symbols representing the standard enthalpy change of PbO
Pb (s) + O2 (g) -> PbO (s)
Write an equation including tate symbols for the bond enthalpy of I-I
I-I (g) -> 2I (g)
Write an ionic equation for magnesium and hydrochloric acid
2H+ (aq) + Mg (s) -> Mg2+ (aq) + H2 (g)
Explain the difference between strong and weak acids
- strong acid completley dissociate in solution
- weak acid partially dissociates in a solution
Give two propertied of butane that makes it suitable as a fuel
- are exothermic
- low toxicity
- highly flammable
What does standard mean in standard conditions
- 298K
- 100 Kpa
- occurs under standard conditions
Write an equation for the standard enthalpy change of formation of butane C4H10
4C (s) + 5H2 (g) -> C4H10 (g)
Describe how ammonia reacts in a neutralisation reaction
- it is a base
- as it acts as a proton acceptor
4NH3 (g) + 5O2 (g) -> 4NO (g) +6H2O (g)
enthalpy change of reations = -908KJmol-1
NH3(g) - -46KJmol-1
Os (g) - 0KJmol-1
H2O (g) - -242KJmol-1
calcu.ate the standard enthalpy change of formation for NO (G)
(4x-46)= 186
(6x-242) = 1452
-184+1452-908 = 360
360/4 = +90 KJmol-1
What is meant by the term enthalpy change of reaction (2)
- number of moles of reactants
- as specifies in the balanced equation react together
it is very difficult to determine the standard enthalpy change of formation of hexane directly. Suggest a reason why (1)
- reactants don’t react
- many different hydrocarbons would form
- reaction to slow
- activation energy to high