Chapter 9 - Force and momentum Flashcards

1
Q

Define momentum and give it’s units

A

Mass x velocity
Kgms^-1

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2
Q

Define conservation of momentum

A

In a closed system the total momentum before an event = total momentum after the event, provided no external resultant force acts on the system

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3
Q

Write an equation linking force to change in momentum using f = ma

A
f = m(u-v)/t 
f = mv -mu/ t 
force = change in momentum/time
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4
Q

Define the impulse of a force

A

Force x the time for which the force acts
Impulse = F x t =change in momentum
- units: Ns

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5
Q

What is impulse equal to?

A

Change in momentum

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6
Q

What does the area under a force - time graph represent?

A

Impulse or change in momentum

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7
Q

A force of 10N acts for 20s on an object of mass 50kg which is initially at rest.
Calculate:
a.) Change in momentum
b.) Velocity of the object at 20s

A

a.) 10 x 20 = 200 Ns
b.) momentum at 20s = 200Ns
velocity = momentum/mass
= 200/50
= 4ms^-1

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8
Q

How do you calculate force of impact?

A
F = change in momentum/ contact time 
F = mv - mu/t
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9
Q

Calculate change in momentum of ball hitting wall at an angle and re-bounding back.There is no loss of speed

A

Change in momentum = final - initial
= -ucos angle - ucos angle
= -2mucos angle

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10
Q

What is an elastic collision?

A

Collision where there is no loss of kinetic energy

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11
Q

What is an inelastic collision?

A

Collision where the colliding objects have less kinetic energy after the collision than before the collison.

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12
Q

If two vehicles collide, causing damage, is this an elastic or inelastic collision?

A

Inelastic

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13
Q

For a falling object, what does the gain in kinetic energy equal?

A

Loss of gravitational potential energy

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14
Q

What is the equation for kinetic energy?

A

Kinetic energy = 1/2 x mass x velocity^2

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15
Q

How do you work out gravitational potential energy?

A

gravitational potential = mass x g x height

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16
Q

A railway wagon of 8000 kg moving at 3ms^-1 collides with an initially stationary wagon of mass 5000 kg. The two wagons separate after the collision. The 8000 kg wagon moves at a speed of 1ms^-1 without change of direction after the collision.

calculate:
a. ) the speed + direction of the 5000 kg wagon after the collision
b. ) the loss of kinetic energy due to the collision.

A

a.) initial momentum = 8000 x 3 = 24000 kgms^-1
final momentum = (8000 x1) + 5000v
5000v = 16000
v = 3.2ms^-1
b.) kinetic energy before = 1/2 x 8000 x 3^2 = 36000J
Ek of 8000kg wagon after = 1/2 x 8000 x 1^2 = 4000J
Ek of 5000kg wagon after = 1/2 x 5000 x 3.2^2 = 25600J
loss of kinetic energy = 36000 - (4000 +25600)
= 6400J

17
Q

What happens to two objects when they fly apart from each other after initially being at rest?

A

Recoil from each other with equal and opposite amount of momentum

18
Q

How is total kinetic energy affected when 2 objects collide and move stuck together?

A

Decreases (inelastic collision)

19
Q

Describe motion of two objects after they collide elastically head on?

A

Move in opposite directions/rebound (objects always seperate in leastic collisions)