chemical equilibria, le chatelier's principle + Kc Flashcards
(16 cards)
what is dynamic equilibrium
the rate of forward reaction is the same as the rate of the backward reaction in a CLOSED SYSTEM, and the concentrations of the reactants and products is constant
what happens when position of equilibrium shifts to the
1. left
2. right
left = conc of reactants increase
right = conc of products increases
what does le chatelier’s principle state?
if a change is made to a system in dynamic equilibrium, the position of the equilibrium moves to counteract this change
how does the equilibrium shift when
1. increase in conc
2. decrease in conc
- equilibrium shifts to the RIGHT to reduce the effect of increase of conc in the reactant
- equilibrium shifts to the LEFT to reduce the effect of a decrease in reactant
how does the equilibrium shift when
1. increase in pressure
2. decrease in pressure
- shifts in direction with LESS moles
- shifts in direction with MORE moles
how does equilibrium shift when
1. temperature increases
2. temperature decreases
- moves in the endothermic direction
- moves in the exothermic direction
what effect does a catalyst have on equilibrium?
catalysts only increase the rate of reaction, dont have an effect on the position of equilibrium
what is the formula for Kc
[C]^c [D]^d
Kc = ——————-
[A]^a [B]^b
formula for concentration
conc = moles / volume
formula for Kp
pp(C)^c pp(D)^d
Kp = ————————-
pp(A)^a pp(B)^b
method to calculate KC
- ICE = initial moles, change in moles, moles at equilibrium
what effect does an increase in temperature have on the value of Kc in endo and exo
An increase in temp in an ENDOthermic = Kc increases bc conc of products increases, and conc of reactants decreases
An increase in temp in an EXOthermic = Kc decreases bc product conc increases and reactant conc decreases
what is the formula for the Haber process and is it exothermic or endothermic?
N₂ (g) + 3H₂ (g) ⇌ 2NH₃ (g)
exothermic
how to maximise yield of haber process
- ↑↑ pressure shifts eq to right .: ↑↑ yield of ammonia bc fewer gas moles
- compromise pressure - 200atm bc high pressure = high cost
- lower temp favours exothermic .: more ammonia
- too low = slow reaction
- compromise = 400-500ºC
- iron catalyst used
what are the reaction steps of the Contact Process
2SO₂ (g) + O₂ (g) ⇌ 2SO₃ (g) ΔH = –197 kJ mol⁻¹ (exothermic)
SO₃ + H₂SO₄ → H₂S₂O₇ (oleum)
H₂S₂O₇ + H₂O → 2H₂SO₄
how to maximise yield of contact process
- ↑↑ pressure shifts eq to right .: ↑↑ SO3 yield
- but Kc already high so eq already far to the right
- compromise pressure = around 1 atm
- lower temp favours SO3 production
- lower temp = too slow
- .: compromise temperature = 450ºC
- catalyst Vanadium (V) oxide (V₂O₅)