Concepts Flashcards
(58 cards)
What can we say regarding a global/local minimum/maximum for a quadratic form?
If A is positive definite, then x = 0 is the unique global minimum of the quadratic form. This is the case when all leading principle minors are positive
If A is negative definite, then x = 0 is the unique global maximum of the quadratic form. This is the case when the leading principle minors alter in sign.
What is positive definite, negative definite, and positive and negative semi definite?
This regards not the special case with quadratic form.
A is positive if every principle minor is non-negative.
A is negative semidefinite if every principal minor of odd order is non-positive and every principal minor of even order is non negative.
Vad betyder siffran vi får i vår bordered hessian matrix med constraint?
> 0 så är det en local maximum
< 0 så är det en local minimum
I set-teori, vad betyder:
U
∩
Vi har A = 1,2,3
Vi har B = 3,4
U = Union = det är alla punkter som finns i alla set.
A U B = 1,2,3,4
Upp och ned U = ∩ = intersection = De punkter som är lika i båda setten.
A ∩ B = 3
What can we say about this set?
A = {x ∈ R : −1 ≤ x ≤ 1}
[−1, 1]
Closed, bounded and compact.
What can we say about this set?
B ={x∈R: −1 < x < 1}
(-1,1)
This set is open and bounded
C = {x∈R: −1 < x ≤ 1}
(−1,1]
This set is not open or closed, but bounded.
It is not open, because there is no open ε-ball around x = 1 completely contained in C. It is not closed, because its complement (−∞, −1] ∪ (1, ∞) is not open.
D = { x in R: x > 0}
D is open.
This set is the interval (0, ∞) on the real number line. It is open, since for every point in the interval, you can move a little in either direction and always remain in the interval. It is not closed, since its complement DC = (−∞, 0] is not open, and therefore it is not compact either.
E = {x ∈ R : x ≥ 0}
[0, ∞)
It is closed.
This set is the interval [0, ∞) on the real number line. It is not open, since there is no open ε-ball around x = 0 which is contained entirely within the set. It is closed, since its complement EC = (−∞, 0) is open. However, it is not compact, because it goes off to infinity and there is no upper bound.
F ={1,2,3,4,5,…}
Set is closed.
This set consists of all positive integers. It is not open, since you leave the set when moving a small distance away from any integer. It is closed, since its complement FC = ∞n=1(n,n + 1) ∪ (−∞,1) is an open set. There is no upper bound, so it is not compact.
G={1/x :x∈N}∪{0}
This set is closed and compact (since it also is bounded).
Here one should note that it is in N nor R. N means all integers.
This set is given by {1, 1/2, 1/3, 1/4, 1/5, …, 0}.
It is not open; if you move some
small ε from x = 1 for instance, you leave the set. It is closed, since its complement is open. It is also bounded, sinceML = 0 n=1 n n+1
is less than or equal to all numbers in the set, and MU = 1 is greater than or equal to all numbers in the set. Thus, it is compact.
G={1/x :x∈N}
This is not open or closed.
This set is given by {1, 1/2, 1/3, 1/4, 1/5, …}.
It is not open, since for example you leave the set when moving a small ε away from x = 1.
It is not closed either. Its complement HC contains zero, and no open ε-ball around zero is entirely contained within HC (since no matter how small you make ε, you can always find some point x1 < ε in the open ε-ball which is an element of H and therefore not an element of HC).
Though it is bounded by the same argument as for G, it cannot be compact since it is not closed.
Exercis 8.2 ouch 8.4 handlar också om sets.
What is the sandwich formula
AP=PD
What is D in terms of P and D?
D = P^{-1}AP
Express A in terms of P and D
A = DPP^{-1}
Express A^{-1} in terms of P and D
PD^{-1}P^{-1}
Move A to LHS
ABC = DE
Move E to LHS
ABC = DE
Premultiply A^{-1}
ABC = DE
BC = A^{-1}DE
ABCE^{-1}=D
A^{-1}ABC=A^{-1}DE
or
ABCA^{-1}=DEA^{-1}
Trace(A) =
A = any matrix
Trace(A) = Trace(D)
D = The diagonal vector of eigen values
Det(D)
Determinant of a matrix A
Det(D) = Det(A)
What can you do with trace()
One can set Trace(A) = Trace(D) and solve for a variable a that is in A.
Vad är trace() ?
Summan av de diagonala numrern i en matris.
Det finns Hessian, borderd hessian och borderd matrix…. vilken är vilken och vad kan man säga.
KOLLA DETTA PÅ YOUTUBE. Verkar finnas bra filmer.
If the bordered hessian matrix is > 0, it is a local maximum.
If the bordered hessian matrix is < 0, it is a local minimum.
Dubbelkolla detta
If the hessian matrix is > 0, it is a local minimum.
If the bordered hessian matrix is < 0, it is a local minimum.
{x ∈ R: x > 0}
Open, not bounded.