Core Flashcards
Method of differences
If Uₙ = f(n) - f(n+1)
then sum to n from r=1 = f(1) + f(n+1)
Sums of cubes for quadratic and cubic eq
a^3+b^3 = (a+b)^3-3ab(a+b)
a^3+b^3+y^3
= Σa^3 - 3(Σa)(Σab)+Σaby
Conditions for a transformation to be linear
- Maps origin onto itself
- Can be represented by a matrix
- |ax+by|
|cx+dy|
Properties of linear transformations
T|kx| kT|x|
|ky| = |y|
T((x+x0)(y+y0) = T(x,y) + T(x0,y0)
Properties of stretches (linear transformations)
|a 0|
|0 b| stretch sf a parallel to x axis and b to y axis
stretch parallel to x axis - points on y axis (x=0) invariant n vice versa
reflections self inverse P^2 = I
detM = area scale factor - negative if shape is reflected, 1 if shape is rotated
Reflections about x,ynz axes
x |1 0 0| y |c 0 s|
|0 c -s| |0 1 0|
|0 c s| |-s 0 c|
z |c -s 0|
|s c 0 |
|0 0 1| s=sin etc angle is measured in anticlockwise direction from positive axis
Order of applying multiple transformations
AB (x) = B then A
f(n) = 3^4n + 2^(4n+2)
show f(k+1)-f(k) div by 15
then prove f(n) is div by 5
Write out subtraction, factor 3 n 2 terms, note that 3 coefficient (80) is 5x16, now there’s a factor of 3^k x 5, which will always be a multiple of 15 :)
Assume that f(k) is divisible by 5.
It would follow that f(k)=5m = where
m is an integer
f(k+1) = f(k) +5(16)(3^4k) + 60(2^4k)
take out factor of 1/3
15(16)(3^4k-1) + 60(2^4k)
also non negative integers means prove for 0 azwel
1/i
-i (i/i^2)
argand straight line
Re(z) = k
meth odf differences simplifications for sum of f(r)-f(r+1) n f(r+2)
sum (fr - fr+1 = f(1)-f(n+1)
fr - fr+2 = f1 + f2 - f(n+1) - f(n+2)
What makes a function improper
+ convergent/divergent
If one of the limits is infinite, or if the function is undefined at one of the limits, or in between the interval [a,b]
Convergent - if improper integral exists
Divergent - if integral doesn’t exist
Dont write integral from -inf to inf as integral from -t to t, instead from -t to 0 then 0 to t
both must converge to say function converges
When to STOP using D,I meth
When there’s a 0 in the d row, or where you can integrate product of a row
Mean value transformations
f(x)+k — f+k
kf(x) —– kf
-f(x) —— -f*
mean of f(x) + g(x) = sum of means on interval
where f* is the mean value
Geometric reasoning to explain why mean value of sinx^5 is 0 on interval [0,2pi]
Integral on interval [0,π] is negative of integral on interval [π,2π], so summing them gives 0