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Flashcards in Electron scattering Deck (15)
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1
Q

Why is electron scattering more accurate than alpha particle scattering

A

Electrons are leptons and so do not interact with the SNF but interact with electrostatic force which is better understood compared to the SNF meaning it is a more accurate method for estimating the nuclear radius

2
Q

Why can electrons be diffracted

A

because they have a wave-particle duality

3
Q

When a beam of high energy electrons are directed at at a thin metal, the incident electrons are

A

diffracted by the nuclei of the atoms in the foil

4
Q

The beam of electrons is produced by

A

accelerating electrons through a very high pd so at high speeds their de Broglie wavelength, = h/mv will be small enough to be similar to the size of the nuclear radius ~ 1fm for maximum diffraction

5
Q

A detector measures

A

the number of electrons per second diffracted through different angles

6
Q

The beam of electrons are fired through… causing

A

The beam of electrons are fired through an atomic lattice causing them to scatter and form a diffraction pattern with a central bright circular maxima surrounded by other rings of dimmer maximima

7
Q

Scattering of the beam of electrons occurs because of

A

their charge and their de Broglie wavelength

8
Q

Difference between the scattering of electrons and alpha particles

A

Scattering of the beam electrons by the nuclei occurs due to their charge. This is the same as alpha-scattering except the electrons are attracted not repelled causing intensity to decrease as charge or angle of diffraction increases

9
Q

In every reaction, what is conserved

A

energy, momentum and charge

10
Q

Intensity =

A

number of electrons per second

11
Q

First minimum (theta min) appears when

A

sinX = 0.61*lambda/Radius of nuelcus

12
Q

Graph of intensity (y) against angle of diffraction (x) (one quadrant)

A

starts at top of y axis and decreases 1/x style to a non-zero minimum then increases to a peak then decreases 1/x style

non-zero min at (theta min, y)

13
Q

Graph of intensity (y) against angle of diffraction (x) (two quadrants)

A

big central peak symmetrical about intensity axis then symmetrical decreases non-zero peaks

14
Q

Explain what happens to the intensity as the angle of diffraction increases

A

The graph shows that as the angle from the source to the zero order beam is increases, the number of electrons per second = intensity of the beam diffracted decreases then increases slightly then decreases again

15
Q

How is a diffraction pattern formed and how is this used to calculate the nuclear radius

A

Diffraction of the beam electrons by each nucleus causes maxima and minima to be superimposed. This happens provided the de Broglie wavelength of the electrons in the beam is no greater than the dimensions of the nucleus. The angle of the first minimum from the centre is measured and used to calculate the diameter of the nucleus