Exam 1 Flashcards
(55 cards)
When this polypeptide is treated with 1-fluoro-2,4-dinitrobenzene followed by hydrolysis the product
found is
A. dinitrophenyl-phenylalanine
B. dinitrophenyl-alanine
C. dinitrophenyl-alanine and d-dinitrophenyl-arginine
D. dinitrophenyl-alanine and dinitrophenyl-leucine
E. dinitrophenyl-phenylalanine and dinitrophenylalanine
B. dinitrophenyl-alanine
When this polypeptide is treated with Carboxypeptidase A the first product found is
A. phenylalanine
B. alanine
C. arginine
D. leucine
E. dinitrophenyl-phenylalanine and d-dinitrophenyl-arginine
A. phenylalanine
One of the amino acids in the polypeptide is Tryptophan the one letter abbreviation and structure of Tryptophan is A. W, 1 B. T, 2 C. Y, 5 D. F, 3 E. W, 5
E. W, 5
This polypeptide has ________ peptide bonds
Ala-Leu-Ser-Arg-Met-Val-Ile-Trp-Ala-Met-Ala-Ala-Phe
A. 8
B. 9
C. 11
D. 12
E. 13
D. 12
When this peptide is subject to Edman degradation the 4 amino acids will be released in the following order A. F, A, A, M B. A, L, S, R C. A, F, S, R D. A, F, S, A E. L, S, R, M
B. A, L, S, R
When this polypeptide is treated with cyanogen bromide the fragments formed will be
Ala-Leu-Ser-Arg-Met-Val-Ile-Trp-Ala-Met-Ala-Ala-Phe
A. Ala-Leu-Ser-Arg and Met-Val-Ile-Trp-Ala-Met-Ala-Ala-Phe
B. Ala-Leu-Ser-Arg-Met and Val-Ile-Trp-Ala-Met-Ala-Ala-Phe
C. Ala-Leu-Ser-Arg-Met and Val-Ile-Trp-Ala-Met and Ala-Ala-Phe
D. Ala-Leu-Ser-Arg and Met-Val-Ile-Trp-Ala and Met-Ala-Ala-Phe
E. all of the above
C. Ala-Leu-Ser-Arg-Met and Val-Ile-Trp-Ala-Met and Ala-Ala-Phe
Cleavage of this polypeptide with chymotrypsin and trypsin will yield \_\_\_\_\_ and \_\_\_\_ fragments, respectively Ala-Leu-Ser-Arg-Met-Val-Ile-Trp-Ala-Met-Ala-Ala-Phe A. 1 and 1 B. 3 and 3 C. 2 and 3 D. 2 and 2 E. 3 and 2
D. 2 and 2
When this polypeptide is titrated one would expect that the titration curve would look like
Ala-Leu-Ser-Arg-Met-Val-Ile-Trp-Ala-Met-Ala-Ala-Phe
A. 1 B. 2 C. 3 D. 4 E. None of the above
D. 4
Estimate the pI of the polypeptide. Ala-Leu-Ser-Arg-Met-Val-Ile-Trp-Ala-Met-Ala-Ala-Phe A. 4.3 B. 6.0 C. 10.5 D. 2.2 E. 3.25
C. 10.5
The overall tertiary structures of myoglobin and the a and b chains of hemoglobin are very similar. However, there are several regions on the myoglobin surface where the residues are polar or charged whereas these same regions on the surface of the a and b chains are nonpolar. The consequence of this change is that
A. There is no functional consequence to this change.
B. The chains of Hb stay apart in solution whereas those of Mb aggregate
C. The a and b chains of Hb associate into a tetramer due to hydrophobic interactions
D. The a and b chains of Hb associate into a tetramer due to polar interactions
E. The a and b chains of Hb associate into a tetramer due to the formation of salt bridges
C. The a and b chains of Hb associate into a tetramer due to hydrophobic interactions
Answer the following two questions (11-12) based on the figures below
11. Structures A, B and C are mostly _____________, ____________, and ________, respectively
A. a-helical, b-sheet, and a + b
B. a-helical, b-sheet, and disordered
C. b-sheet, a-helical, and a + b
D. b-sheet, a-helical, and disordered
E. b-sheet, a-helical, and a + b + disordered
E. b-sheet, a-helical, and a + b + disordered
. Using the Ramachandran plot below. Structure A above would likely have dihedral angles of A. j = -60, Y = -60 B. j = -150, Y = +150 C. j = -60, Y = -150 D. j = --60, Y = +150 E. j = +60, Y = +60
B. j = -150, Y = +150
Collagen and silk both are _____________ but differ in that the H-bonds in silk are ______ to the chain whereas those in collagen are ______________to (in) the collagen helix.
A. globular proteins, parallel, perpendicular
B. fibrous proteins, perpendicular, parallel
C. fibrous proteins, perpendicular, not involved
D. globular proteins, perpendicular, not involved
E. fibrous proteins, parallel, perpendicular
C. fibrous proteins, perpendicular, not involved
Collagen has high percentages of hydroxyproline. This is not one of the 20(21) amino acids in the genetic code. Rather it is formed __________________ and this process requires _________, a lack of which results in ____________.
A. by posttranslational modification; vitamin D3; rickets
B. in the mitochondria; vitamin B; anemia
C. by post translational modification; vitamin C; sickle cell disease
D. by post translational modification; vitamin C; scurvy
E. by post translational modification; vitamin D3; scurvy
D. by post translational modification; vitamin C; scurvy
Hemoglobin A and Hemoglobin S differ in that a __________residue on the ______ chain is replaced by
_______. This results in a(n) ___________ in the pI of the hemoglobin.
A. Glu; b; Val; increase.
B. Glu; a; Val; increase.
C. Glu; b; Leu; decrease.
D. Glu; b; Val; decrease.
E. Glu; a; Val; decrease
A. Glu; b; Val; increase.
Sickle cell trait is highly associated with residence in certain parts of Africa and is related to increased resistance to \_\_\_\_\_\_\_\_\_\_\_\_\_\_. The linkage between these traits is called\_\_\_\_\_\_\_\_\_. A. Beriberi; transduction. B. Malaria; balanced polymorphism. C. Malaria; gene hopping. D. Beriberi; balanced polymorphism. E. Malaria; transduction.
B. Malaria; balanced polymorphism
Based on this graph
A. Mb binds O2 with higher affinity than Hb.
B. Hb binds O2 with higher affinity than Mb.
C. Hb binds O2 with higher affinity than Mb but only at pH 6.8.
D. Mb and Hb have the same affinity.
E. You cannot determine relative affinity from this graph.
A. Mb binds O2 with higher affinity than Hb
The effect of pH shown in this plot is known as A. Hill effect B. Michaelis effect C. Bohr effect D. Menten effect E. Lineweaver Burk effect
C. Bohr effect
Assuming that the above graph was determined in the absence of BPG, the addition of BPG
would______________
A. Shift all curves to the right.
B. Shift all curves to the left.
C. Shift the curve for Mb to the right and the curves for Hb to the left.
D. Shift the curves for Hb to the right.
E. Shift the curves for Hb to the right and the curve for Mb to the left
D. Shift the curves for Hb to the right.
CO (carbon monoxide) and CO2 both bind to Hb. However, CO is extremely toxic. One of the reasons is that
it has a much higher affinity than oxygen. 50% of the Hb subunits bound to CO is lethal. This is because
A. CO decreases the affinity of O2 for the remaining Hb subunits.
B. CO increases the affinity of O2 for the remaining Hb subunits.
C. CO and O2 do not bind at the same binding site.
D. CO has a lower Molecular weight than O2.
E. None of the above.
B. CO increases the affinity of O2 for the remaining Hb subunits
Calculate the pH of a dilute solution that contains a molar ratio of potassium acetate to acetic acid (pKa =
4.76) of 5:1.
Answer formula: pH=4.76 + log(5/1)=5.46
If bacterial cells are taken from an isotonic medium and placed in a hypotonic medium A. They swell. B. They shrink. C. They remain the same. D. They burst. E. The nucleus leaks out of the cell
A. They swell
Which of the following is likely to form a b-turn structure A. Ala-Pro-Gly-Met. B. Lys-Val-Phe-Trp. C. Ala-Ala-Met-Val. D. Gly-Pro-Hyp. E. None of these forms a b-turn.
A. Ala-Pro-Gly-Met
At what substrate concentration would an enzyme with a kcat of 33.0 s−1 and a Km of 0.0065 M operate at one-tenth of its maximum rate
7.2 * 10^-4