Exam 2 Flashcards

(15 cards)

1
Q

How to find area between two curves

A

1) Graph the functions
2) Find the intersection point by setting both functions equal to 0
3) Set up the integral from a to b (a being the left bound placed on bottom of integral and b being the right bound placed on top of the integral)
4) The integral inside is the top function minus the bottom function dx
5) Integrate and then plug in b and subtract plugged in a

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2
Q

How to find area between two curves in terms of y

A

1) Rewrite the function from y= to x=
2) Find the intersection point by setting both functions equal to 0
3) Set up the integram from a to b with a being the lowest bound on the bottom of integral and b being the highest bound on the top of the integral
4) The integral inside is the right function minus the left function dy
5) integrate and then plug in b and subtract plugged in a

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3
Q

How to find volume w/ cross sections (semicircle)

A

integral from a to b 1/2*pi((f(x)-g(x))/2)^2 dx
= 1/2pi int from a to b ((f(x)-g(x))/2)^2 dx

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4
Q

How to find volume w/ cross sections (squares)

A

int from a to b (f(x)-g(x))^2 dx

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5
Q

How to find volume w/ cross sections (rectangle)

A

int from a to b k*(f(x)-g(x))^2 dx

(height is k of length)

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6
Q

How to find volume w/ cross sections (circle)

A

int from a to b pi(1/2(f(x)-g(x))^2 dx

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7
Q

How to find volume w/ cross sections (isosceles right triangle)

A

int from a to b 1/2(f(x)-g(x))^2 dx

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8
Q

How to find volume w/ cross sections (equilateral triangle)

A

int from a to b (sqrt of 3)/2*(f(x)-g(x))^2 dx

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9
Q

Disk method

A

int from a to b pi(f(x))^2 dx

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10
Q

Washer method

A

int from a to b pi[(R(x))^2-(r(x))^2] dx

big R is the outer radius (or top function)

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11
Q

Shell method

A

int from a to b 2pixf(x) dx

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12
Q

Arc length

A

int from a to b sqrt: 1+(f’)^2 dx

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13
Q

Surface area

A

int from a to b 2pif(x)sqrt: 1+(f’)^2 dx

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14
Q

Find work of movement

A

int from 0 to h (weight) dx

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15
Q

Find work of spring

A

int from a to b k*x dx

F=kx
F= force, x=distance adjusted

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