exam 4 part 3 Flashcards
(37 cards)
multiple factor hypothesis
multiple genes contributing to single phenotype
when standard deviation is small =
everyone next to average (small range)
knowing the variance can tell you
the width of the curve
phenotype =
genotype + environment
genotype =
additive and dominance effects
broad sense heritibility
H2 = VG / VP
narrow sense heritability
h2 = VA / VP
if heritability = 1
all VP due to genetic variation
if heritability = 0
all VP is due to environmental variation
heritability is based on
population not an individual
steps to a PCR
- heat and denature (separate)
- cool and add primer
- synthesize
in electrophoresis, DNA loaded at — pole
negative
limitations to PCR
- must know about sequence surrounding the gene
- easily contaminated
- polymerase doesn’t proofread and correct
- fragments amplified are small
types of repeats used in DNA fingerprinting are
- STR
- VNTR
- microsatellite regions
allele in identification is based on
the length of the DNA segment
loci used for paternity/forensic purposes must be
polymorphic
CODIS
uses 20 polymorphic regions for forensic identification
recombinant DNA
creating new DNA molecules by combining DNA from different sources
restriction enzyme
endonuclease that recognizes a specific DNA sequence and cleaves dsDNA at that sequence
origin of replication
allows it (cloning vectors) to replicate in the host cell
selectable/insertional markers
allow cells containing the vector and the recombinant molecule to be identified
multiple cloning sites
has restriction enzyme cut sites that can be used in producing a recombinant DNA molecule
ligation experiment
conducted to join foreign DNA to vector
transformation experiment
conducted to allow cells to take up products from a ligation experiment