Exan Dos Flashcards

(45 cards)

1
Q

Proof of crossing over

A

Creighton and McClintock

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2
Q

What did creighton and McClintock conclude

A

Crossing over does involve a physical exchange between homologous chromosomes

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3
Q

Advantages of using bacteria for genetic studies

A
Lots of progeny 
Can be genetically engineered 
Reproduction is rapid 
Growth is easy with little space 
Easy to isolate
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4
Q

Prototroph

A

Can grow on minimal media

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5
Q

Auxotroph

A

Mutant that requires additional nutrients

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6
Q

Lederberg and Tatum

A

Conducted an experiment to determine if bacteria can transfer genetic material

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7
Q

Purpose of U tube experiment

A

To understand if bacteria must touch in order to exchange genetic information

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8
Q

Davis

A

U tube experience for to understand if cell contact is required for transfer of genetic information

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9
Q

Conjugation

A

Temporary fusion of two single cell organisms for the sexual exchange of genetic material

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10
Q

Bacteria cells that can transfer genetic material through fusion

A

F+ and F- cells

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11
Q

F-

A

Recipient cell

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12
Q

F+

A

Contains F factor and donates through pili hat contact F-

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13
Q

Process of Conjugation

A

Pilus of F+ come in contact with F-
Conjugation tube forms
One strand of F factor is nicked and the 5’ end leads the way to the F- cell
Replication of the F factor occurs

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14
Q

Benzer experiment

A

Wondered if mutations were all in same gene or if several genes were controlling lysis
Coinfext bacterial with two strains of bacteriophage and see if normal plaques are produced

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15
Q

Population genetics

A

Study of inherited variation within and between populations over time and space

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16
Q

CIs

A

Mutation one same chromosome

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17
Q

Trans

A

Mutation on different chromosomes

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18
Q

Cistron

A

Place where complementation cannot occur (gene)

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19
Q

Two mutations in same gene

20
Q

Two mutations on different genes

21
Q

Lytic cycle

A
Phage infects 
Injects genetic material 
Takes over 
Replicates 
Creates new phages 
Lysis of cell
22
Q

Plaque

A

Seen on lawn of bacteria when lysis occurs

23
Q

Lysogenic cell

A

Bacterial cell with a prophage

24
Q

Prophage

A

A bacterial cell with a phage integrated into the chromosome

25
Life cycle of a temperate phage
Lytic or lysogenic
26
How do we use conjugation to map?
Combine several Hfr x F- makings
27
Interrupted Mating
Combining several HFR x F- pairs to map circular bacteria because different Hfr strands integrate in different places if the bacterial chromosome and will begin transfer af different places and sometimes different directions
28
F’ cells
F factor within an HFR pops out of the bacterial chromosome to produce an F’ cell
29
F’ xF-
F’ merezygote (partial diploid)
30
Transformation
Exogenous DNA transfers genes to competent bacterial cell and brings about heritable change in the cell
31
Result of transformation
Only one daughter cell is transduced
32
How can we use translation for genetic mapping
Cotransformation to determine if genres are located near each other
33
Generalized transduction
Bacteria are infected with phage Bacterial chromosome is fragmented and some of the genes become incorporated into a few phages The cell lysis releases the phages to attach and release bacterial genetics instead of the phage genetics and create a transduced bacterial cell
34
How can we use generalized transduction for mapping?
Two genes co transduce if they are close together
35
Specialized transduction
Prophage pops out of bacterial chromosome and takes one or more genes with it The progeny virus transfer these genes when infecting other cells
36
How can we use specialized transduction for genetic mapping
Not useful since the only genes are affects are those next to the integration site
37
Cell contact required in conjugation?
Yes
38
Cell contact required in transformation?
No
39
Cell contact required in transduction?
No
40
Conjugation sensitive to DNase?
No
41
Transformation sensitive to DNase?
Yes
42
Transduction sensitive to DNase?
Yes
43
Hardy Weinberg law
Allele and genotypes frequencies will arrive at and remain at equilibrium frequencies after one generation of random mating of all sssumotions are met
44
Assumptions of hardy Weinberg
``` Infinitely large population Random mating No selection (all genotypes equally fit) No migration No mutation ```
45
At equilibrium.. what equation represents genotypic frequency?
P2AA + 2pq Aa + q2 aa | p and q are the frequencies of the A and a alleles respectively