Final Exam Flashcards
(137 cards)
A point against which position is measured
Reference point
A physical measurement that contains directional information
Vector quantity
A physical measurement that does not contain directional information
Scalar quantity
The time rate of change of an object’s velocity
Acceleration
The motion of an object when it is falling solely under the influence of gravity
Free fall
Why must one use a reference point to determine whether or not an object is in motion?
In order for motion to occur, an object’s position must change. In order to determine position, there must be a reference point. The reference point allows you to determine whether or not position changes.
After a visit to your grandmother’s house, you get in your car to go home. You are in the front passenger’s seat and your mother is driving. As you back out of your grandmother’s driveway, she stands outside, waving good-bye.
a. Who is in motion relative to you?
b. Who is motionless relative to you?
a. Your grandmother is in motion relative to you. Even though your grandmother is standing still, her position relative to you is changing. Thus, she is in motion relative to you.
b. Your mother is motionless relative to you. Her position relative to you does not change. She is therefore motionless with respect to you.
How many miles per hour does a car travel if it makes a 40-mile trip in 30 minutes?
This problem gives us distance and time and asks for speed. We know it is asking for speed because a distance unit divided by a time unit is speed or velocity. There is no direction here, so we are talking about speed. Thus, we need to use Equation (9.1). The problem wants the answer in miles per hour, however. We are given the time in minutes. Thus, we must make a conversion first:

What is the velocity of a bicycle (in meters per second) if it travels 1 kilometer west in 4.1 minutes?
The problem wants velocity, which is speed and direction. To get speed, we will use Equation (9.1). Unfortunately, the problem tells us to give the answer in meters per second, but the distance is in kilometers and the time is in minutes. Thus, we need to do two conversions:

You are looking in a scientist’s lab notebook and find the following unlabeled measurements. In each case, determine what physical quantity the scientist was measuring.
a. 12.1 meters per second
b. 31.2 feet
c. 14 millimeters per hour to the west
d. 4.5 yards per minute2 north
a. This measurement has a distance unit divided by a time unit. That’s speed or velocity. Since no direction is given, this is speed.
b. The unit of feet by itself measures distance.
c. This measurement has a distance unit divided by a time unit. That’s speed or velocity. Since a direction is given, this is velocity.
d. This measurement has a distance unit divided by a time unit squared. That’s acceleration. The direction is necessary because acceleration is a vector quantity.
An eagle swoops down to catch a baby rabbit. Luckily for the rabbit, he sees the eagle and runs. An all-out chase ensues with the rabbit running east at 5.4 meters per second and the eagle pursuing at 4.4 meters per second. What is the relative velocity of predator and prey?

As the picture shows, the eagle is behind the rabbit, but they are both traveling in the same direction. Thus, we get their relative velocity by subtracting their individual velocities:
relative velocity = 5.4 meters/second - 4.4 meters/second = 1.0 meter/second
Since the rabbit is traveling faster than the eagle, the rabbit is pulling away. Thus, the relative velocity is 1.0 meter per second away from each other.
What is the acceleration of an object that moves with a constant velocity?
Since the velocity is not changing, the acceleration is zero.
A skier reaches the bottom of a slope with a velocity of 12 meters per second north. If the skier comes to a complete stop in 3 seconds, what was her acceleration?
The initial velocity is 12 meters per second north, and the final velocity is 0. The time is 3 seconds. This is a straightforward application of Equation (9.2).

A car goes from 0 to 60 miles per hour north in 5 seconds. What is the car’s acceleration?
This is another application of Equation (9.2), because we are given time (5 seconds), initial velocity (0) and final velocity (60 miles per hour north). We can’t use the equation yet, however, because our time units do not agree. We’ll fix that first:

A person standing on a bridge over a river holds a rock and a ball in each hand. He throws the ball down towards the river as hard as he can and at the same time simply drops the rock. After both have left the person’s hand, does one have a greater acceleration? If so, which one?
Neither has greater acceleration. Both objects are falling near the surface of the earth; thus, they are each in free fall. That means they both have equal acceleration. The ball was given moreinitial velocity, so it will travel faster. The acceleration on both is the same, however.
Why does a dropped feather hit the ground later than a rock dropped at the same time?
The feather is more affected by air resistance than the rock. This is the same situation as Experiment 9.2.
A physics student climbs a tree. To measure how high she has climbed, she drops a rock and times its fall. It takes 1.3 seconds for the rock to hit the ground. How many feet has she climbed?
The rock is in free fall, so we can use Equation (9.3). Since the problem wants the answer in feet, we need to use 32 feet per second2 as the acceleration.

The tendency of an object to resist changes in its velocity
Inertia
A force that opposes motion, resulting from the contact of two surfaces
Friction
Friction that opposes motion once the motion has already started
Kinetic friction
Friction that opposes the initiation of motion
Static friction
State Newton’s three laws of motion.
Newton’s First Law – An object in motion (or at rest) will tend to stay in motion (or at rest) until it is acted upon by an outside force.
Newton’s Second Law – When an object is acted on by one or more outside forces, the total force is equal to the mass of the object times the resulting acceleration
Newton’s Third Law – For every action, there is an equal and opposite reaction.
A pilot is flying a mission to drop bombs on an enemy airfield. The plane is flying high and fast to the north, and the city is due north. Should the pilot drop the bombs before the plane is over the airfield, when the plane is over the airfield, or after the plane has passed the airfield?
The pilot must drop the bombs before the plane reaches the airfield. The bombs will have a velocity equal to that of the plane when they are dropped. Thus, they will continue to fly north as they fall. In order to hit the airfield, then, they must be dropped south of it.
A cruel boy has placed a mouse on the outer edge of a disk. He slowly starts to spin the disk, accelerating it faster and faster until the disk and mouse are both spinning around at an alarming rate. What will happen to the mouse if the boy suddenly stops the disk without touching the mouse: will the mouse continue to spin like it was before; will the mouse stop with the disk; or will the mouse start moving straight, skidding off the disk?
The mouse will start moving straight, skidding off of the disk. This is like Experiment 10.2. When the disk stops, the mouse has a velocity pointed in a certain direction. Without sufficient time, the frictional force will not be able to keep the mouse on the disk. This will cause the mouse to start traveling in a straight line, in the direction it was moving right before the disk stopped.













