Final Review

Question 1

To display the name of each customer and the title of each book purchased by the customers would require how many join conditions?

4
3
2
1

Answer 1

3

Question 2

Which of the following keywords can be used to join two tables that do not contain a commonly named and defined column?

NATURAL JOIN
JOIN…ON
JOIN…USING
none of the above

Answer 2

JOIN…ON

Question 3

Which SQL statement will return the same results as the following SQL statement?
SELECT * FROM orders, customers;

SELECT * FROM orders CROSS JOIN customers;

SELECT * FROM orders, customers
WHERE orders.customer# = customers.customer#;

SELECT * FROM orders, customers
WHERE orders.customer# > customers.customer#;

SELECT * FROM o orders , c customers
WHERE o.customer# = c.customer#;

Answer 3

SELECT * FROM orders CROSS JOIN customers;

Question 4

In Oracle11g, tables can be linked through which clause(s)?

SELECT
FROM
WHERE
both b and c

Answer 4

both b and c

Question 5

Which of the following SQL statements will display the gift that should be sent to any customer who orders the book titled THE WOK WAY TO COOK?

SELECT title FROM promotion
WHERE retail BETWEEN minretail AND maxretail;

SELECT title FROM promotion NATURAL JOIN books
WHERE retail BETWEEN minretail AND maxretail;

SELECT title FROM promotion JOIN books
USING retail BETWEEN minretail AND maxretail;

none of the above

Answer 5

none of the above

Question 6

A(n) ____ is used to combine the results of two queries.

concatenation operator
set operator
comparison operator
logical operator

Answer 6

set operator

Question 7

Which of the following SQL statements will list the name of each customer stored in the CUSTOMERS table, and, if the customer has placed an order that is contained in the ORDERS table, the order# of any order each customer has placed?

SELECT lastname, firstname, order#
FROM customers NATURAL JOIN orders
WHERE orders.customer# IS NOT NULL;

SELECT lastname, firstname, order#
FROM customers, orders
WHERE orders.customer# (+) = customers.customer#;

SELECT lastname, firstname, order#
FROM customers, orders
WHERE orders.customer# = customers.customer# (+);

SELECT lastname, firstname, order#
FROM customers NATURAL JOIN orders
WHERE orders.customer# IS NULL;

Answer 7

SELECT lastname, firstname, order#
FROM customers, orders
WHERE orders.customer# (+) = customers.customer#;

Question 8

Which of the following SQL statements will display the title of the books ordered by customer# 1003?

SELECT title
FROM customers NATURAL JOIN books
WHERE customer# = 1003;

SELECT title
FROM customers JOIN orders USING (customer#)
JOIN orderitems USING (order#) JOIN books USING (isbn)
WHERE customer# = 1003;

SELECT title
FROM customers JOIN orders ON (customer#)
JOIN orderitems ON (order#) JOIN books ON (isbn)
WHERE customer# = 1003;

both a and b

Answer 8

SELECT title
FROM customers JOIN orders USING (customer#)
JOIN orderitems USING (order#) JOIN books USING (isbn)
WHERE customer# = 1003;

Question 9

Which of the following set operators can be used to make certain that only the rows returned by both queries are displayed in the results?

UNION
UNION ALL
INTERSECT
MINUS

Answer 9

INTERSECT

Question 10

Which of the following set operators will display the results of the combined SQL statements without suppressing duplicate rows?

UNION
UNION ALL
INTERSECT
MINUS

Answer 10

UNION ALL

Question 11

Which of the following SQL statements will display books that have not been ordered recently?

SELECT title
FROM books, orderitems
WHERE books.isbn orderitems.isbn;

SELECT title
FROM books NATURAL JOIN orderitems
WHERE JOIN IS NULL;

SELECT title FROM books NATURAL JOIN orderitems
MINUS
SELECT title FROM books;

SELECT title FROM books
MINUS
SELECT title FROM books NATURAL JOIN orderitems;

Answer 11

SELECT title FROM books
MINUS
SELECT title FROM books NATURAL JOIN orderitems;

Question 12

Which of the following SQL statements will return the names of all customers who placed an order on April 12, 2003?

SELECT lastname, firstname
FROM customers
WHERE orderdate = ‘12-APR-03’;

SELECT lastname, firstname
FROM customers NATURAL JOIN orders
WHERE orderdate = ‘12-APR-03’;

SELECT lastname, firstname
FROM customers JOIN orders ON (customer#)
WHERE orderdate = ‘12-APR-03’;

both a and b

Answer 12

SELECT lastname, firstname
FROM customers NATURAL JOIN orders
WHERE orderdate = ‘12-APR-03’;

Question 13

Which of the following queries will display the first and last name of the individual who referred another customer, along with the customer# of the referred customer?

SELECT r.firstname, r.lastname, c.customer#
FROM customers r, customers c
WHERE r.customer# = c.referred;

SELECT r.firstname, r.lastname, c.customer#
FROM customers r JOIN customers c
ON r.customer# = c.referred;

SELECT r.firstname, r.lastname, c.customer#
FROM customers r NATURAL JOIN customers c;

both a and b

Answer 13

both a and b

Question 14

Which of the following keywords is used to create a Cartesian join?

OUTER JOIN
CROSS JOIN
NATURAL JOIN
JOIN…USING

Answer 14

CROSS JOIN

Question 15

Which of the following can only be used to link tables that have a common column?

FULL OUTER JOIN
JOIN…ON
NATURAL JOIN
CROSS JOIN

Answer 15

NATURAL JOIN

Question 16

Which of the following will display the title, publication date, and publisher name of each book in the BUSINESS category?

SELECT title, pubdate, name
FROM publisher JOIN books USING (pubid)
WHERE category = ‘BUSINESS’;

SELECT title, pubdate, name
FROM publisher JOIN books ON (pubid)
WHERE category = ‘BUSINESS’;

SELECT title, pubdate, name
FROM publisher OUTER JOIN books USING (pubid)
WHERE category = ‘BUSINESS’;

SELECT title, pubdate, name
FROM publisher CROSS JOIN books USING (pubid)
WHERE category = ‘BUSINESS’;

Answer 16

SELECT title, pubdate, name
FROM publisher JOIN books USING (pubid)
WHERE category = ‘BUSINESS’;

Question 17

Which of the following is an example of assigning “o” as a table alias for the ORDERS table in the FROM clause?

FROM o orders, c customers
FROM o.orders, c.customers
FROM orders o, customers c
FROM orders.o, customers.c

Answer 17

FROM orders o, customers c

Question 18

Which of the following queries will display data from both the ORDERS and CUSTOMERS tables?

SELECT * FROM orders, customers;

SELECT lastname, firstname, order#
FROM orders NATURAL JOIN customers;

SELECT lastname, firstname, order#
FROM orders, customers
WHERE orders.customer# = customers.customer#;

all of the above

Answer 18

all of the above

Question 19

Which of the following types of joins refers to joining a table to itself?

Cartesian join
equality join
self-join
outer join

Answer 19

self-join

Question 20

If you are attempting to join two tables that have multiple common columns, which of the following JOIN keywords should be used to specify how the tables should be linked?

OUTER JOIN
CROSS JOIN
JOIN…USING
none of the above

Answer 20

JOIN…USING

Question 21

A temporary table that is created when a multiple-column subquery is used in the FROM clause of an outer query is called a(n) ____.

inner view
outer view
inline view
natural view

Answer 21

inline view

Question 22

Which of the following operators is used with a multiple-row subquery?

IN
ANY
ALL
all of the above

Answer 22

all of the above

Question 23

The following SQL statement contains which type of subquery?
SELECT title, retail, (SELECT AVG(retail) FROM books) FROM books;

single-row
multiple-row
multiple-column
inline view

Answer 23

single-row

Question 24

The

Answer 24

less than the lowest

Question 25

A subquery, except one in the FROM clause, cannot contain a(n) ____ clause. GROUP BY HAVING ORDER BY WHERE

Answer 25

ORDER BY

Question 26

Which of the following can be used in a WHERE clause? single-row subquery multiple-column subquery multiple-row subquery all of the above

Answer 26

all of the above

Question 27

Which operator will instruct Oracle11g to list all records with a value that is more than the highest value returned by the subquery? ALL >ANY

Answer 27

>ALL

Question 28

The operators =, , =, and are referred to as ____ operators. multiple-row single-row correlated multiple column

Answer 28

single-row

Question 29

Based on the contents of the BOOKS table, which of the following SQL statements will return an error message? SELECT title FROM books WHERE retail = (SELECT MAX(retail) FROM books); SELECT title FROM books WHERE retail IN (SELECT MAX(retail) FROM books); SELECT title FROM books WHERE retail > (SELECT MAX(retail) FROM books); none of the above

Answer 29

none of the above

Question 30

When a multiple-column subquery is included in the WHERE or HAVING clause of the outer query, which operator is used by the outer query to evaluate the results of the subquery? > BETWEEN IN none of the above

Answer 30

IN

Question 31

Based upon the contents of the BOOKS table, which of the following will display the retail price of the most expensive book provided by publisher 3? SELECT MAX(retail) FROM books GROUP BY pubid; ``` SELECT MAXIMUM(retail) FROM books WHERE pubid = 3; ``` ``` SELECT MAX(retail) FROM books WHERE pubid = 3; ``` ``` SELECT MAXIMUM(retail) FROM books HAVING pubid = 3; ```

Answer 31

``` SELECT MAX(retail) FROM books WHERE pubid = 3; ```

Question 32

The default keyword for group functions is ____. ALL DISTINCT INCLUDENULLS NONULLS

Answer 32

ALL

Question 33

Based on the contents of the BOOKS table, which of the following SQL statements will return the total profit generated by books provided by publisher 4? ``` SELECT TOTAL(retail-cost) FROM books WHERE pubid = 4; ``` ``` SELECT TOTAL(retail-cost) FROM books GROUP BY pubid; ``` ``` SELECT SUM(retail-cost) FROM books WHERE pubid = 4; ``` ``` SELECT SUM(retail-cost) FROM books GROUP BY pubid = 4; ```

Answer 33

``` SELECT SUM(retail-cost) FROM books WHERE pubid = 4; ```

Question 34

Based upon the contents of the BOOKS tables, which of the following SQL statements will return the number of different publishers represented in the table? SELECT COUNT(DISTINCT pubid) FROM books; SELECT DISTINCT COUNT(pubid) FROM books; SELECT DISTINCT (COUNT(pubid)) FROM books; SELECT (DISTINCT COUNT(pubid)) FROM books;

Answer 34

SELECT COUNT(DISTINCT pubid) FROM books;

Question 35

If the DISTINCT keyword is not included in the STDDEV function, the ____ keyword will be assumed. UNIQUE ALL NONULLS none of the above

Answer 35

ALL

Question 36

Which of the following is a valid SQL statement? ``` SELECT SUM(quantity*retail) "Total Sales" FROM orders JOIN orderitems ON orders.order# = orderitems.order# JOIN books ON orderitems.ISBN = books.ISBN WHERE orderdate = '02-APR-03'; ``` ``` SELECT SUM(quantity*retail) "Total Sales" FROM orders JOIN orderitems ON orders.order# = orderitems.order# JOIN books ON orderitems ON orderitems.ISBN = books.ISBN HAVING orderdate = '02-APR-03'; ``` SELECT customer#, SUM(quantity*retail) "Total Sales" FROM orders JOIN orderitems ON orders.order# = orderitems.order# JOIN books ON orderitems ON orderitems.ISBN = books.ISBN HAVING orderdate = '02-APR-03'; SELECT customer#, SUM(quantity*retail) "Total Sales" FROM orders JOIN orderitems ON orders.order# = orderitems.order# JOIN books ON orderitems ON orderitems.ISBN = books.ISBN HAVING orderdate = '02-APR-03' GROUP BY customer#;

Answer 36

``` SELECT SUM(quantity*retail) "Total Sales" FROM orders JOIN orderitems ON orders.order# = orderitems.order# JOIN books ON orderitems.ISBN = books.ISBN WHERE orderdate = '02-APR-03'; ```

Question 37

Based upon the contents of the ORDERS table, which of the following will display how many orders were shipped to each state? SELECT shipstate, COUNT(*) FROM orders; SELECT shipstate, COUNT(customer#) FROM orders; SELECT shipstate, COUNT(*) FROM orders HAVING COUNT(*) >0; SELECT shipstate, COUNT(*) FROM orders GROUP BY shipstate;

Answer 37

SELECT shipstate, COUNT(*) FROM orders GROUP BY shipstate;

Question 38

Based on the contents of the ORDERS table, which of the following SQL statements will display the number of orders that have not been shipped? SELECT order#, COUNT(shipdate) FROM orders WHERE shipdate IS NULL; SELECT order#, COUNT(shipdate) FROM orders WHERE shipdate IS NULL GROUP BY order#; SELECT COUNT(shipdate) FROM orders WHERE shipdate IS NULL; SELECT COUNT(*) FROM orders WHERE shipdate IS NULL;

Answer 38

SELECT COUNT(*) FROM orders WHERE shipdate IS NULL;

Question 39

Functions that return one result per group of rows are called ____ functions. group multiple-row aggregate all of the above

Answer 39

all of the above

Question 40

The SUM function can only be used with ____ data. numeric character date alphanumeric

Answer 40

numeric

Question 41

Which of the following cannot be used with date columns? MIN MAX AVG all of the above

Answer 41

AVG

Question 42

If a SELECT statement contains HAVING, GROUP BY, and WHERE clauses, the ____ clause will be processed last. HAVING GROUP BY WHERE SELECT

Answer 42

HAVING

Question 43

The AVG function can be used with ____ values. numeric character date all of the above

Answer 43

numeric

Question 44

Which of the following can be used with date columns? MIN MAX COUNT all of the above

Answer 44

all of the above

Question 45

Which of the following is a valid statement? A single-row function can be nested inside a group function. Group functions can be nested inside other group functions. Group functions can be nested inside single-row functions. all of the above

Answer 45

all of the above

Question 46

Based on the contents of the BOOKS table, which of the following will display the date of the book with the earliest publication date? ``` SELECT MIN(pubdate) FROM books; ``` SELECT title FROM books WHERE pubdate = MIN(pubdate); SELECT title FROM books WHERE pubdate = MINIMUM(pubdate); ``` SELECT MINIMUM(pubdate) FROM books; ```

Answer 46

``` SELECT MIN(pubdate) FROM books; ```