Formulae Flashcards
(26 cards)
The remainder theorem
Given the polynomial f(x), the remainder when f(x) is divided by (x – a) is f(a).
The factor theorem
If (x – a) is a factor of a polynomial f(x), then x = a is a root (solution) of the equation f(x) = 0.
Quadratic equation
(-b±√b²-4ac) / 2a
Parallel lines gradient
m¹=m²
Perpendicular line gradient
m¹xm²=-1
Straight line equation
y=mx+c
Distance between two points
(x¹,y¹),(x²,y²)= √(x¹-x²)²+(y¹-y²)
Midpoint of a line
(x¹,y¹),(x²,y²)= {(x¹+x²)/2,(y¹+y²)/2}
Circle on a graph
The circle (x-a)²+(y-b)²=r² has centre (a,b) and radius r .
Sine rule
a/sinA=b/sinB=c/sinC or sinA/a=sinB/b=sinC/c
Cosine rule
a²=b²+c²-2bccosA
Area rule
Area=½absinC
Identity with tan, cos and sin
tanϴ=sinϴ/cosϴ
Identity with sin and cos
sin²ϴ+cos²ϴ=1
Stationary points
Stationary points occur when dy/dx=0
Differentiation
y=axⁿ —> dy/dx=naxⁿ-¹ (thats n-1)
Integration
if y=axⁿ then ⌠ydx=(a/n+1)xⁿ+¹
Area under a curve
Area under curve between x=a and x=b is
b⌠y dx
a⌡
Kinematic, constant acceleration with v,u,a and t
v=u+at
Kinematic, constant acceleration with s,u,v and t
s=½(u+v)t
Kinematic, constant acceleration with s,u,t and a
s=ut+½at²
Kinematic, constant acceleration with s,v,t and a
s=vt-½at²
Kinematic, constant acceleration with v,u,a and s
v²=u²+2as
kinematics non constant acceleration find v
if x = displacement, v = velocity, a = acceleration, t = time
v=ds/dt (differentiate displacement) or v=⌠a dt (integrate acceleration)