Functions- lecture video Flashcards

1
Q

How many outcomes can a function have

A

one
each input determines one unique output

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2
Q

What is the Domain

A

x value or input value or independent variable

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3
Q

what is the range

A

y value or output value or dependent variable

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4
Q

What test can we use to determine if a graph is a function

A

vertical line test
- the vertical line can only pass through one co-ordinate

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5
Q

is this a function? Why or why not
X^2 + y^2 = 25

A

no, we need to
at 15:15 add more
but you end up with more than one answer +/_ so it is not a function

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6
Q

What is important about graphing piecewise functions

A

by graphing each piece individually

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7
Q

What are the restrictions for A=S^2

A

S must be greater than or = to zero
(cannot be a negative number)

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8
Q

what are the restrictions for y = 1/ x

A

x cannot = 0

0 would make it undefined

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9
Q

what are the restrictions for F(x) = the square root of x

A

x must be greater than or = to zero

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10
Q

what are the restrictions for f(x) = x ^3

A

no restrictions, so the domain is all real numbers

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11
Q

what are the restrictions for f(x) = 1 / (x-1) (x-3)

A

X is all really numbers except x cannot = 1 or 3

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12
Q

What happens if you cannot simplify restrictions out of your functions

A

these will be vertical asymptotes

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13
Q

What are the restrictions for f(x) = Tan x

A

(an s shape for tangents, because it is undefined at certain points)

= sin x / cos x
therefore, cos x cannot = 0

x cannot = pi/ 2
x cannot = 3 pi / 2
etc

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14
Q

what are the restrictions for f(x) = square root (x^2-5x +6)

A
  1. if you have a square root, the numbers must be positive in it
  2. we know that (x^2 - 5x + 6 must be greater than or = to zero)
  3. We need to factor this question because it is a quadratic equation

= (x - 3)(x-2) is greater than or = 0

this is an inequality, becareful, it’s not 3 and 2

  1. so we know x = 2 and x = 3 are important points, make a number line and put the points on the number line then do a test
  2. here we plug in 0 (to the left of 2) into the equation, you get positive 6
    - every number to the left of 2, will be a positive number
  3. try a point greater than 3, we plug in 4 and we get a positive number
  4. try a point b/w 2 and 3, we choose 2.5 and we get a negative number

Therfore the domain is:
(- infinity,2]U [3, + infinity)

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15
Q

Big thing with restrictions is

A

look for
1. denominators
- the bottom cannot = 0

  1. roots
    - cannot use negative numbers as the answer
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16
Q

What are the restrictions for f (x) = x^2 - 4 / x-2

A
  1. we know the denominator cannot be 0 however, we can factor this
  2. factor this out we get
    (x+2) (x-2) /x-2
    - we can now cancel out the two x-2s and we get
    x+2
  3. so the domain is all real numbers except we still have to keep the original domain restriction that x cannot = 2
17
Q

If the restriction is x cannot = 2 what also can we say about x = 2 on the graph

A

we have a point on the graph not filled in or a hole

or a removable discontinuity (or not continuous graph)

18
Q

If you can cancel out your domain problem (ie. the denominator can be cancelled out by factoring) then you have what

A

a hole

19
Q

If you cannot cancel out your domain problem (ie. the denominator by factoring) what is it

A

an asymptote

20
Q

What are the restrictions for 3x / x-4

do you have a hole or asymptote

A
  1. x cannot = 4
  2. we cannot factor the denominator out so we have a vertical asymptote
21
Q

what are the restrictions for
f(x) = 2 + square root of x-1

What is the domain and what is the range

A

x-1 cannot = be negative or must be greater than or = to zero

so x must be greater than or equal to 1
Domain:
interval
[1, infinity)

Range: [2, infinity)

22
Q

how do you find your range?

A

plug in your domain (for now, for simple items)

23
Q

what is the domain and range for y = (x+1)/ (x-1)

A

Domain: x cannot = 1
bc 1 -1 =0 in the denominator

all real numbers except 1

now plug in 1 into the whole equation you get
2/ 0 which is a vertical asymptote

Range: if you solve for y you get
x = y+1 / y-1
y cannot = 1
horizontal asymptote

24
Q

What are even functions

A

functions that have 2s, 4s, 6s, and 8,s in them etc

25
Q

What are odd functions

A

functions that have odd numbers in them

26
Q

even functions are symmetric how

A

symmetric across the y-axis
f(-x) = f(x)

27
Q

odd functions are symmetric how

A

symmetric about the origin (mirror image)
f(-x) = -f(x)

28
Q

how to test to see if something is even

If f(x) = x^4 - x^2+1

A

plug in negative x and see what happens
f(-x) = (-x)^4 - (-x)^2+1
becomes…

x^4-x^2+1 - we got back the same thing!

THis means it is an EVEN function

29
Q

is it even or odd function

f(x) = x^3 - x

A

to figure out, plug in -x

f(-x) = (-x)^3 - (-X)
becomes….

F(-x)= -x^3 +1

We got the opposite back so this means it is

an ODD Function