Functions- lecture video Flashcards
(29 cards)
How many outcomes can a function have
one
each input determines one unique output
What is the Domain
x value or input value or independent variable
what is the range
y value or output value or dependent variable
What test can we use to determine if a graph is a function
vertical line test
- the vertical line can only pass through one co-ordinate
is this a function? Why or why not
X^2 + y^2 = 25
no, we need to
at 15:15 add more
but you end up with more than one answer +/_ so it is not a function
What is important about graphing piecewise functions
by graphing each piece individually
What are the restrictions for A=S^2
S must be greater than or = to zero
(cannot be a negative number)
what are the restrictions for y = 1/ x
x cannot = 0
0 would make it undefined
what are the restrictions for F(x) = the square root of x
x must be greater than or = to zero
what are the restrictions for f(x) = x ^3
no restrictions, so the domain is all real numbers
what are the restrictions for f(x) = 1 / (x-1) (x-3)
X is all really numbers except x cannot = 1 or 3
What happens if you cannot simplify restrictions out of your functions
these will be vertical asymptotes
What are the restrictions for f(x) = Tan x
(an s shape for tangents, because it is undefined at certain points)
= sin x / cos x
therefore, cos x cannot = 0
x cannot = pi/ 2
x cannot = 3 pi / 2
etc
what are the restrictions for f(x) = square root (x^2-5x +6)
- if you have a square root, the numbers must be positive in it
- we know that (x^2 - 5x + 6 must be greater than or = to zero)
- We need to factor this question because it is a quadratic equation
= (x - 3)(x-2) is greater than or = 0
this is an inequality, becareful, it’s not 3 and 2
- so we know x = 2 and x = 3 are important points, make a number line and put the points on the number line then do a test
- here we plug in 0 (to the left of 2) into the equation, you get positive 6
- every number to the left of 2, will be a positive number - try a point greater than 3, we plug in 4 and we get a positive number
- try a point b/w 2 and 3, we choose 2.5 and we get a negative number
Therfore the domain is:
(- infinity,2]U [3, + infinity)
Big thing with restrictions is
look for
1. denominators
- the bottom cannot = 0
- roots
- cannot use negative numbers as the answer
What are the restrictions for f (x) = x^2 - 4 / x-2
- we know the denominator cannot be 0 however, we can factor this
- factor this out we get
(x+2) (x-2) /x-2
- we can now cancel out the two x-2s and we get
x+2 - so the domain is all real numbers except we still have to keep the original domain restriction that x cannot = 2
If the restriction is x cannot = 2 what also can we say about x = 2 on the graph
we have a point on the graph not filled in or a hole
or a removable discontinuity (or not continuous graph)
If you can cancel out your domain problem (ie. the denominator can be cancelled out by factoring) then you have what
a hole
If you cannot cancel out your domain problem (ie. the denominator by factoring) what is it
an asymptote
What are the restrictions for 3x / x-4
do you have a hole or asymptote
- x cannot = 4
- we cannot factor the denominator out so we have a vertical asymptote
what are the restrictions for
f(x) = 2 + square root of x-1
What is the domain and what is the range
x-1 cannot = be negative or must be greater than or = to zero
so x must be greater than or equal to 1
Domain:
interval
[1, infinity)
Range: [2, infinity)
how do you find your range?
plug in your domain (for now, for simple items)
what is the domain and range for y = (x+1)/ (x-1)
Domain: x cannot = 1
bc 1 -1 =0 in the denominator
all real numbers except 1
now plug in 1 into the whole equation you get
2/ 0 which is a vertical asymptote
Range: if you solve for y you get
x = y+1 / y-1
y cannot = 1
horizontal asymptote
What are even functions
functions that have 2s, 4s, 6s, and 8,s in them etc