GENERAL PRINCIPLES - CLIMB AND DESCENT Flashcards
(106 cards)
What is the formula for Climb Gradient ?
Gradient % = {(T - D)/ W } x 100
Merely by looking at the above formula certain facts are self evident:
For a given weight, the greater the “Excess Thrust” (T – D) the steeper the climb gradient. The less the Excess Thrust the more shallow the climb gradient.
For a given Excess Thrust (T – D), the greater the weight the more shallow the climb gradient. The less the weight the steeper the climb gradient.
A twin engine turbojet aircraft has engines of 60,000N each; its mass is 50 tonnes and it has a L/D
of 12:1, what is the % climb gradient? What will be the climb gradient with One Engine Failed ? Use ‘g’ = 10m/s/s.
From the above information the values to include in the formula have to be derived:
Thrust = 60,000N x 2 engines = 120,000N
Drag = Weight / 12
Weight = 50 tonnes x 1000 = 50,000kg x 10m/s/s = 500,000N
Drag therefore = 500,000N / 12 = 41,667N
120,000N - 41,667 N
x 100 = 78,333 N x 100 = 15.7 %
500,000 N 500,000 N
Let us now consider the same values, but with one engine failed:
60,000N - 41,667 N
x 100 = 3.7 %
500,000 N
Thrust has decreased by 50%, but climb gradient has decreased by approximately 75% or to one
quarter of the gradient possible with all engines operating.
Why losing 50% of the Thrust Available reduces Excess Thrust by approximately 75% ?
Losing 50% of the Thrust Available reduces Excess Thrust by approximately 75% because the same value of aerodynamic Drag must still be balanced. That a two engine aeroplane with one engine inoperative, has a severely reduced ability to climb. Flaps reduce the climb angle because they increase
aerodynamic Drag and therefore decrease Excess Thrust.
Thrust is the force required to balance _____________; plus the _____________ when the aircraft is in a steady climb.
Thrust is the force required to balance aerodynamic Drag; plus the backward component of Weight when the aircraft is in a steady climb.
What is the Formula of thrust produced by an Engine and what is the effect of increasing speed on the thr thrust produced ?
–Thrust Available = Mass Flow x Acceleration (Exhaust velocity – Intake velocity).
–When the aircraft is at low forward speed, any increase in speed will reduce the velocity change through
the engine without a corresponding increase in Mass Flow and Thrust Available will decrease slightly. When the aircraft is flying at higher speed, the ram effect helps to increase mass flow with increasing forward speed and Thrust Available no longer decreases, but actually increases slightly with speed.
What is EGT limited Thrust ?
– Generally, the Thrust of any turbo-jet engine is restricted by the maximum temperature the turbine blades can withstand. The more heat resistant the material from which the turbine blades are made and the more efficient the blade cooling, the higher the maximum turbine inlet temperature and therefore the greater the Thrust the engine can safely develop.
–For a given engine, the higher the OAT the lower the mass air flow and therefore the lower the
fuel flow before the maximum turbine inlet temperature is reached and consequently, the lower
the Thrust the engine is able to develop – this is known as EGT limited Thrust.
What is the meaning of Flat Rated Thrust ?
–Thrust increasing with decreasing OAT at a given Pressure Altitude, but only down to an OAT of ISA +15C. Below ISA + 15C Thrust remains constant. This is the engines “Flat Rated” Thrust. At OAT’s below ISA +15C, Thrust is no longer limited by turbine inlet temperature but by the maximum air pressure the compressor is built to withstand. Below airport OAT’s of ISA + 15C it does not matter how far the flight crew advance the throttle, the engine management computer will maintain “Flat Rated” Thrust – this
is the maximum certified Thrust of the engine.
– From a Performance point of view, if engines are not “Flat Rated” and the throttles are fully advanced at OAT’s below ISA + 15C a lot more than maximum certified Thrust will be delivered. While this may not be immediately destructive to the engine if done occasionally, it completely compromises the certification of the aeroplane. Engine-out critical speeds (VMCG, VMCA and VMCL) are based on the yawing moment generated at maximum certified Thrust. If significantly more Thrust is produced during one-engine-out flight with the IAS at the recommended minimum, directional control of the aeroplane will be lost.
Define Vx
The IAS at which the aeroplane generates the greatest amount of Excess Thrust and is therefore
capable of its steepest climb gradient, is called Vx. (Vx is referred to as the Best Angle of Climb
Speed).
Increased Weight reduces maximum climb gradient and ______ Vx.
Increased Weight reduces maximum climb gradient and increases Vx.
If flaps (or gear) are extended Parasite Drag will increase, but there will be no significant change in Induced Drag. True/ False
True
Flaps or gear reduce ____________ and __________ Vx.
It therefore seems a very good idea to retract the gear as soon as possible after lift-off, after a
positive rate of climb is achieved and also not to use flaps during a climb so that the climb angle
is as large as possible. But, you may recall the purpose of flaps is to decrease the take-off and
landing run.
Flaps or gear reduce maximum climb gradient and decrease Vx.
It therefore seems a very good idea to retract the gear as soon as possible after lift-off, after a
positive rate of climb is achieved and also not to use flaps during a climb so that the climb angle
is as large as possible. But, you may recall the purpose of flaps is to decrease the take-off and
landing run.
Define Density Alt in simple terms
A high density altitude is one that represents a higher altitude in the International Standard Atmosphere
–Note that Vx will _______ with changes in air density, because at _______________.
– However, you will recall that as air density decreases, True Air Speed _______________.
–So although the IAS for Vx is constant with increasing density altitude, the TAS for Vx will of
course increase.
–You may recall from earlier lessons that high humidity will also ________ air density and will
therefore also ___________- aeroplane performance.
–Note that Vx will remain constant with changes in air density, because at a constant IAS (Vx) Drag will not vary.
– However, you will recall that as air density decreases, True Air Speed must be increased to maintained the required dynamic pressure.
–So although the IAS for Vx is constant with increasing density altitude, the TAS for Vx will of
course increase.
–You may recall from earlier lessons that high humidity will also decrease air density and will
therefore also decrease aeroplane performance.
What is the Air Gradient and ground gradient ?
The affect that wind has on climbing depends upon the type of climb gradient being considered,
(wind being motion of a body of air over the ground). There are two types of climb gradient:
Air gradient and Ground gradient. Air gradient is used by aviation authorities to lay down
minimum climb performance limits. E.g. a Class ‘A’ aeroplane: “….. starting at the point at which
the aeroplane reaches 400 ft (122 m) above the take-off surface, the available gradient of climb may not be less than 1.2% for two-engines aeroplanes”.
What is the Air gradient ?
Air gradient is the vertical distance gained in a body of air divided by the horizontal distance
travelled through the same body of air. The fact that the body of air might be moving over the
ground is NOT considered. So wind has no affect on Air gradient. The body of air stationary relative to the ground; this is referred to as “Zero Wind” or “Still Air”. The aeroplane has climbed to the top right corner of the body of air and the Air gradient is shown as Gamma ‘a’.
AIR GRADIENT _________ by wind)
GROUND GRADIENT ( _________ by wind) –Also known as the _________
A tailwind does not change the _____ gradient, but __________ the ____________ gradient
A headwind does not affect the ______ gradient, but ___________ the __________ gradient.
–The only time wind is used to calculate climb gradient is when____________
AIR GRADIENT (Not affected by wind)
GROUND GRADIENT ( Influenced by wind) –Also known as the Flight Path Angle (FPA)
A tailwind does not change the Air gradient, but decreases the Ground gradient
A headwind does not affect the Air gradient, but increases the Ground gradient.
–The only time wind is used to calculate climb gradient is when obstacle clearance is being considered. In all other cases of climbing, still air is used, even if a wind value is supplied.
It is important to remember that if the ground gradient is to be used for the calculation of obstacle
clearance, the application of headwinds and tailwinds must include the _____ headwind and ______ tailwind
rule.
It is important to remember that if the ground gradient is to be used for the calculation of obstacle
clearance, the application of headwinds and tailwinds must include the 50% headwind and 150% tailwind
rule.
Example 1: An aeroplane has an Air gradient of 12%, its TAS is 100 kt and the headwind is 20 kt. Calculate the Ground gradient.
Example 2: An Air gradient of 12% with a TAS of 160 kt and a headwind of 20 kt. Calculate the Ground gradient.
Example 1: An aeroplane has an Air gradient of 12%, its TAS is 100 kt and the headwind is
20 kt. Calculate the Ground gradient. (Figure 3.35).
The 20 kt headwind makes the ground speed (GS) 80 kt (100 – 20 = 80).
100 TAS divided by 80 GS gives a wind factor of 1.25. Multiplying the Air gradient of 12% by
the wind factor gives a Ground gradient of 15%.
Example 2: An Air gradient of 12% with a TAS of 160 kt and a headwind of 20 kt. 160
divided by 140 gives a wind factor of 1.14. Multiplying the Air gradient of 12% by the wind
factor gives a Ground gradient of 13.7% (12 x 1.14 = 13.5).
Example 3: the same Air gradient of 12% with a TAS of 100 kt but now a tailwind of 20 kt. Calculate the ground gradient.
Example 4: an Air gradient of 12% with a TAS of 160 kt and a tailwind of 20 kt makes
the ground speed (GS) 180 kt. Calculate the ground gradient.
Example 3: the same Air gradient of 12% with a TAS of 100 kt but now a tailwind of 20 kt.
In the above example, the 20 kt tailwind makes the ground speed (GS) 120 kt
(100 + 20 = 120).
100 kt TAS divided by 120 kt GS gives a wind factor of 0.83. Multiplying the Air gradient of 12%
by the wind factor gives a Ground gradient of 10% (12 x 0.83 = 9.96).
Example 4: an Air gradient of 12% with a TAS of 160 kt and a tailwind of 20 kt makes
the ground speed (GS) 180 kt. 160 kt TAS divided by 180 kt GS gives a wind factor of 0.89.
Multiplying the Air gradient of 12% by the wind factor gives a Ground gradient of 10.7% (12 x
0.89 = 10.7).
Determine the ground distance for a Class B aeroplane to reach a height of 2000
ft above Reference Zero in the following conditions:
OAT: 25°C
Pressure altitude: 1000 ft
Gradient: 9.4%
Speed: 100 KIAS
Wind component: 15 kts Headwind
(Reference Zero is the point on the runway or clearway plane at the end of the Take-Off Distance
Required (Figure 3.37). It is the reference point for locating the start point of the take-off Flight
Path.)
- The TAS is calculated from the KIAS using your circular slide rule.
(at 1000ft Pressure altitude and 25 deg C, 100 KIAS = 104 KTAS) - Due to the 15kt headwind, the Ground Speed will be (104 KTAS – 15 Kt) = 89 KTAS.
(Wind speed is always a TAS) - TAS divided by GS gives a wind factor of 1.17.
- Multiplying the Air gradient by the wind factor gives a Ground gradient of 11%
(Approximately).
Following take-off, a light twin engine aeroplane has a 10% climb gradient. By how much will it will clear a 900m high obstacle situated 9740m from the end of the Take-off Distance Available (TODA)?
The distance of the obstacle from the end of the TODA is 9740 m, so we need to discover how
many times the horizontal ratio of 100 will divide into that distance (9740 / 100 = 97.4). This
means that the horizontal distance is 97.4 times greater, so the height gain will also be 97.4 times
greater. Multiplying 10 by 97.4 will give the height gain in metres, (97.4 x 10 = 974m) in this
case, 974 m.
However, it must be remembered that the climb segment starts at 15 m (50 ft) above Reference
Zero. So the screen height must be added to the height gain (974 m + 15 m = 989 m), in this
example, 989 m
The aircraft will clear the 900 metre obstacle by 89 metres.