Genetics Exam 3 Flashcards

(31 cards)

1
Q
  1. What is the purpose of a complementation test?

A. to determine whether an organism is homozygous dominant or recessive at a particular locus
B. to determine whether an allele is dominant. or recessive
C. to determine whether lethal alleles are present
D. to determine whether two mutants with the same phenotype have defects in the same gene

A

D. to determine whether two mutants with the same phenotype have defects in the same gene

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2
Q
  1. If fewer than 100% of individuals of a dominant genotype express the dominant phenotype, the phenotype is described as having reduced___

A. Expression
B. Pension
C. Penetrance
D. Expressivity

A

C. Penetrance

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3
Q
  1. Which structure that forms during meiosis leads directly to the formation of recombinant chromosomes?

A. Microtubule
B. Centromere
C. Sister Chromatid
D. Cross Over

A

D. Cross over

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4
Q
  1. In horses, black coat color is dominant over chestnut brown. Suppose a black horse is mated to a chestnut brown and the offspring are twins. One foal is black and the other is chestnut brown. What can you conclude about the genotype of he black parent?

A. The genotype must be homozygous dominant
B. The genotype type must be homozygous recessive
C. The genotype must be heterozygous
D. The genotype cannot be determined from the data

A

C. The genotype must be heterozygous

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5
Q
  1. In a cross between parents with the genotypes AaBb and aabb, where A and B loci are unlinked, what percentage of the offspring will have a phenotype that differs from the phenotype of the AaBb and aabb parents.

A. 100%
B. 75%
C. 50%
D. 25%

A

C. 50%

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6
Q
  1. In Mendel’s peas purple flower is dominant to white. From which of the following phenotypes can you not infer the genotype completely?

A. purple
B. White
C. True Breeding Purple
D. True Breeding White.

A

A. purple

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7
Q
  1. Which of the following is not one of Mendel’s conclusions based on his monohybrid crosses?

A. alleles exist in pairs
B. alleles have different DNA sequences
C. alleles segregate equally into gametes
D. one allele can mask the expression of another allele

A

B. alleles have different DNA sequences

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8
Q
  1. What does 10 map units represent?

A. 1% recombination between two genes on the same chromosomes
B. 10% recombination between two genes on some chromosome
C. 1% recombination between two different genes on different chromosomes
D. 10% recombination between two genes on different chromosomes

A

A. 1% recombination between two genes on the same chromosomes

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9
Q
  1. What term is used for a block of single-nucleotide polymorphisms (SNPs) that are almost always inherited together?

A. Genome
B. Marker
C. Polymorphism
D. Haplotype

A

D. Haplotype

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10
Q
  1. A different version of a gene is

A. allele
B. loci
C. genotype
D. phenotype

A

A. allele

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11
Q
  1. Which of the following statements is true

A. The genotype is the physical appearance of a trait
B. Alleles, genes, and loci, are different names for the same thing
C. The phenotype of the dominant allele is never seen in the F1 progeny of a monohybrid cross
D. A test cross can be used to determine whether an individual is homozygous or heterozygous for a dominant allele

A

D. A test cross can be used to determine whether an individual is homozygous or heterozygous for a dominant allele

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12
Q
  1. Which of the following factors cannot impact sex development in different organisms?

A. Mitosis
B. Genotype
C. Environment
D. Sex chromosomes

A

A. Mitosis

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13
Q
  1. Which of the following leads to gametes receiving incorrect number of chromosomes?

A. Apoptosis
B. Synapsis
C. Heterozygosity
D. Non-disjunction

A

D. Non-disjunction

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14
Q
  1. Which of the following is not a common dosage compensation mechanism in organisms

A. X-inactivation
B. Y- over expression
C. X over expression
D. X under expression

A

B. Y- over expression

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15
Q
  1. A form of a gene that has a slightly different sequence than other forms of he same gene but encodes the same type of an RNA or protein, is called a(n)

A. complementation group
B. Linkage group
C. Allele
D. trait

A

C. Allele

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16
Q
  1. The difference between co-dominance and incomplete dominance?

A. With co-dominance, neither allele produces sufficient protein. With incomplete dominance, both alleles make sufficient protein.
B. With co-dominance, both alleles produce protein. With incomplete dominance, neither allele makes sufficient
C. With co-dominance, the phenotype lies between the phenotypes of the parental extremes. For incomplete dominance, the phenotype of both alleles is seen
D. In co-dominance, the phenotype reflects both alleles. For incomplete dominance, the phenotype lies between the phenotypes of the parental extremes

A

D. In co-dominance, the phenotype reflects both alleles. For incomplete dominance, the phenotype lies between the phenotypes of the parental extremes

17
Q
  1. What are Barr bodies?

A. Highly condensed and inactivated X chromosomes in males
B. Highly condensed and inactivated X chromosomes in females
C. Highly condensed and inactivated SRY gene in males
D. Highly condensed and inactivated SRY gene in females

A

B. Highly condensed and inactivated X chromosomes in females

18
Q
  1. Which of the following can a genome-wide association study do?

A. Identify the dominant and recessive alleles of an individual
B. Identify alleles associated with a trait
C. Identify regions of the genome that influence a trait
D. Identify causative genes underlying a trait.

A

B. Identify alleles associated with a trait

19
Q
  1. While doing fieldwork in Madagascar you discover a new dragonfly species with either red or clear wings. You preformed 2 crosses using different sets of red-winged parents with unknown genotypes and collected the following data.
    Cross. Offspring phenotype
  2. Red X Red 147 red-winged + 52 clear-winged
  3. Red X Red 396 red-winged
    From these results you can conclude:

A. Red is recessive and clear is dominant
B. Clear is recessive and red is dominant
C. There is evidence of epistasis
D. Red and clear are codominant

A

B. Clear is recessive and red is dominant

20
Q
  1. What does a Manhattan show?

A. The inheritance pattern of a particular trait
B. Associations of traits with locations of the chromosomes
C. The genes associated with a particular trait
D. The distribution of phenotypes in a population

A

B. Associations of traits with locations of the chromosomes

21
Q
  1. What is the role of the SRY gene in humans?

A. it initiates the X inactivation process in females
B. It is located on the X chromosome and causes X to pair with the Y chromosome during male meiosis
C. It is located on the Y chromosome and initiates the developmental pathways toward the male phenotype
D. It is located on an autosomal chromosome and represses the expression of autosomal genes in order to balance their expression level with genes on the X chromosome

A

C. It is located on the Y chromosome and initiates the developmental pathways toward the male phenotype

22
Q
  1. Hemophilia in humans is usually caused by a defective factor 8 protein. The factor 8 gene is on the human X chromosome. Which statement about the inheritance of hemophilia is more correct?

A. This condition occurs almost exclusively in males born to a carrier mothers due to Y-linked recessive inheritance
B. This condition occurs almost exclusively in females sired to carrier fathers due to X-linked recessive inheritance
C. this condition almost exclusively occurs in females sired to carrier fathers due to Y-linked recessive inheritance
D. this condition occurs almost exclusively in males born to carrier mothers due to X-linked recessive inheritance

A

D. this condition occurs almost exclusively in males born to carrier mothers due to X-linked recessive inheritance

23
Q
  1. The capital R locust determines flower color in a new plant species. However, Rr plants have pink flowers. What type of inheritance does this demonstrate for flower color in the plants?

A. complete dominance
B. Incomplete dominace
C. Codominance
D. Complementation

A

B. Incomplete dominace

24
Q
  1. In humans, blood types A&B are codominant to each other and each is dominant to type O. What blood type are possible amongst the offspring of a couple whose blood types are AB and A.

A. A, B, AB, and O
B. A, B, and AB only
C. A, B, and O only
D. A and AB only

A

B. A, B, and AB only

25
26. If two independently isolated mutations with the same phenotype complement each other, each provides the function the other lacks, so they are mutations of _____ genes. A. Different B. Similar C. Identical D. Homologous
A. Different
26
27. A 2015 study found that hot temperatures altered the expression of sex chromosomes in Australia's bearded dragon lizards. The lizards were female in appearance and were capable of laying eggs, despite having the ZZ chromosomes usually associated with male lizards. The is an example of A. The ZZ, ZW sex determination of lizards and birds B. The temperature-dependent sex determination of lizards and reptiles C. When females are the heterogametic sex D. When males are the homogametic sex
B. The temperature-dependent sex determination of lizards and reptiles
27
28. ________ involve mutations at specific nucleotide positions that have at least tow or more variants that are found in at least 1% of the population. A. microarrays B. Single nucleotide polymorphisms or SNPs C. linkage groups D. haplotypes
B. Single nucleotide polymorphisms or SNPs
28
29. ______ results in daughter cells that each contains the complete identical genome of the parent cell A. Meiosis B. Mitosis C. Aneuploidy D. Trisomy
B. Mitosis
29
30. In dogs, short fur is dominant over long fur. A dog with short fur is crossed with a dog with long fur. In a litter of four, all of the puppies have short fur. What is the best conclusion A. the dog with short fur is definitely homozygous B. the dog with short fur is probably homozygous C. the dog with short fur is definitely heterozygous D. the dog with short fur is probably heterozygous
B. The dog with short fur is probably homozygous
30
31. In corn colored seed (C) is dominant to colorless seed (c) and full seed (S) is dominant to shrunken seed (s). A completely heterozygous CcSs plant was testcrossed against a homozygous recessive plant and the following genotypes were inferred. C-S- 4292 ccss 4605 C-ss 86 ccS- 44 A. Are the parental types in Cis or Trans configuration? B. Are the recombinant types in Cis or Trans configuration? C. What is the map distance between the two loci? _____C_________S______
A. Cis B. Trans C. Map distance (in centimorgans, cM) is calculated by: Recombination frequency (RF)=Number of recombinantoffspring/Total number of offspring×100 C–ss = 86 ccS– = 44 Total recombinants = 86 + 44 = 130 Total offspring = 4292 + 4605 + 86 + 44 = 9027 RF=(130/9027)×100≈1.44% Answer C: Map distance = ~1.4 cM
31
33. A. X and Y axis for microarray
A. the x-axis typically represents genes, while the y-axis represents the intensity of expression or the expression ratio of a gene