GROUP 1

Question 1

(main test)

Ag + dil. HCl

Answer 1

white ppt
(dissolves in dil. Ammonia)

Question 2

(main test)

Pb + dil. HCl

Answer 2

white ppt
(dissolves in dil. Ammonia)

Question 3

(Confirmatory tests)

Pb + K2CrO4 < Potassium chromate>

Answer 3

PbCrO4
Yellow ppt - Lead chromate

Question 4

(Confirmatory tests)

Pb + Kl < Potassium
iodide >

Answer 4

PbI2
Yellow ppt - Lead iodide

Question 5

(Confirmatory tests)

Ag + K2CrO4 < Potassium chromate>

Answer 5

Ag2CrO4
Brick red ppt - silver chromate

Question 6

(Confirmatory tests)

Ag + Kl < Potassium
iodide >

Answer 6

AgI
Pale yellow ppt - Silver iodide

Question 7

(Confirmatory tests)

Pb + dil .H2SO4 (SO4-2) < Dil. Sulphuric acid>

Answer 7

PbSO4
White ppt - Lead sulphate

Question 8

HCI is preferred as it

Answer 8

prevents the formation of the insoluble oxy salts of bismuth, tin and antimony

Question 9

Excess, this renders precipitation more complete and prevents

Answer 9

the precipitated chlorides from going to the colloidal state.

Question 10

a large excess of dil. HCI or conc. HCI would

Answer 10

increase the solubility of chlorides by complex formation

Question 11

AgCl + 2 NH4OH

NH4OH: to dissolve silver as silver ammine chloride complex

Answer 11

[Ag(NH3)2]Cl + 2 H2O
Silver ammine chloride complex