Group 7 Flashcards

1
Q

Fluorine at room temperature

A
  • Yellow poisonous gas
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2
Q

Chlorine at room temperature

A
  • Green poisonous gas
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3
Q

Chlorine in aqueous solution

A
  • Pale green solution / colourless in low concentrations
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4
Q

Bromine at room temperature

A

Brown vapour or red/brown liquid

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5
Q

Bromine in aqueous solution

A
  • Orange solution
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6
Q

Iodine at room temperature

A

Grey / black solid sublimes to purple vapour

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7
Q

Iodine in aqueous solution

A
  • Brown solution
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8
Q

Reaction of chlorine with water to form chloride ions and chlorate (I) ion

A

Cl2 + H2O —> HCl + HClO

Gives bleaching power of wet chlorine

Disproportionation reaction

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9
Q

Chloric (I) acid to make chlorate ions equation

A

HClO + H2O —> ClO- + H3O+ or H+

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10
Q

Chlorine and water in sunlight equation

A

2Cl2 + 2H2O —> 4HCl + O2

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11
Q

Chlorine with cold dilute NaOH equation

A

Cl2 + NaOH —> NaCl + NaClO + H2O

Sodium chlorate used as bleach

Disproportionation reaction

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12
Q

What can HCl and HClO be used for?

Why can Cl2 be used since it’s toxic?

A
  • Both kill bacteria in drinking water or swimming pools in low concentrations
  • Cl2 used as benefits outweigh the potential health risks to humans
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13
Q

Why are fluoride ions added to water?

A

To prevent tooth decay as they strengthen enamel

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14
Q

Chlorine with NaBr ionic equation and results

A
  • Cl2 + 2Br- —> Br2 + 2Cl-
  • Br2 released so orange colour observed
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15
Q

Chlorine with NaI ionic equation and results

A
  • Cl2 + 2I- —> I2 + 2Cl-
  • Brown colour observed
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16
Q

Bromine with NaCl and NaBr

A

No reaction

17
Q

NaCl with Cl2

A

No reaction

18
Q

Bromine with NaI ionic equation and results

A
  • Br2 + 2I- —> I2 + 2Br-
  • Brown colour observed
19
Q

Iodine with NaCl, NaBr or NaI

A

No reaction

20
Q

Strength of oxidising agent down group 7

A

Decreases down, iodine is the weakest oxidising agent because fluorine smallest ion so electrons most strongly held by the nucleus compared to other ions / less shielding

21
Q

Reduction equation of Cr2O7(2-)

A

Cr2O7(2-) + 6e- + 14H+ —> 2Cr(3+) + 7H2O

22
Q

Reduction equation of MnO4

A

MnO4 + 5e- + 8H+ —> Mn2+ + 4H2O

23
Q

Reduction equation of MnO2

A

MnO2 +2e- + 4H+ —> Mn2+ +2H2O

24
Q

Reduction equation of H2SO4 to SO2

A

H2SO4 + 2e- + 2H+ —> SO2 + 2H2O

25
Colour change of KMnO4 if reduction has occured
* Purple solution will turn pink (or colourless with a dilute solution)
26
Colour change of K2Cr2O7 is reduction has occured
* Orange solution turns green
27
S(2-) to SO4(2-) oxidising equation
S2- + 4H20 ---\> SO4(2-) + 6e- + 8H+
28
Test for HCl, HBr and HI
Damp blue litmus paper will turn red * All hydrogen halides produce white misty fumes
29
Reaction of H2SO4 and sodium halide equation and which react further
* H2SO4 + NaCl ---\> NaHSO4 + HCl * H2SO4 + NaF ---\> NaHSO4 + HF * H2SO4 + NaBr ---\> NaHSO4 + HBr * H2SO4 + NaI ---\> NaHSO4 + HI Only NaBr and NaI react further as they are strong enough reducing agents and can reduce sulfuric acid
30
Strength of reducing agents down the group
* Increases down group * Iodine strongest reducing agent and fluorine the weakest
31
NaBr + H2SO4 full overall equation
2NaBr + 3H2SO4 ---\> 2NaHSO4 + SO2 + 2H2O + Br2
32
NaBr + H2SO4 ionic equation
2Br- + H2SO4 + 2H+ ---\> Br2 + SO2 + 2H2O
33
Why are there 3 potential reactions with NaI and H2SO4
I- is a stronger reducing agent
34
Give the ionic equation and full equation of the reaction with H2SO4 that gives a pruple vapour (I2) and black solid (I2)
* 2I- + H2SO4 + 2H+ ---\> I2 + SO2 + 2H2O * 2NaI + 3H2SO4 ---\> 2NaHSO4 + SO2 + 2H2O + I2
35
Give full equation and ionic equation for reaction with H2SO4 that produces a yellow solid
* 6I- + H2SO4 + 6H+ ---\> 3I2 + S + 4H2O * 6NaI + 7H2SO4 ---\> 6NaHSO4 + S + 4H2O + 3I2
36
Give the full equation and ionic equation of reaction with H2SO4 that produces a rotten egg smell
* 8I- + H2SO4 + 8H+ ---\> H2S + 4I2 + 4H2O * 8NaI + 9H2SO4 ---\> 8NaHSO4 + H2S + 4H20 + 4I2
37
Test for H2S
With lead nitrate paper makes lead sulfide and nitric acid, so paper goes black as black insoluble compound * H2S (g) + Pb(NO3)2 (aq) ---\> PbS (s) + 2HNO3 (aq)