higher biology DNA and the genome Flashcards
Deoxyribose sugar
pentose sugar, 1’ carbon joins to base, 5’ carbon joins to phosphate
DNA nucleotide labelled
Phosphate, deoxyribose sugar, base
DNA bases
Adenine, thymine, guanine, cytosine
Name of DNA backbone
Sugar-phosphate backbone
Bonds in a DNA molecule
Weak hydrogen bonds between base pairs and chemical covalent bonds between phosphate and 3’ carbon of deoxyribose sugar
Relationship between two strands of DNA
They are antiparallel
Leadimg strand and lagging strand carbons at end and beginning
Leading strand 5’ to 3’, lagging strand 3’ to 5’
Prokaryote and example
Cell without a nucleus, bacteria
Eukaryote
Cell with a nucleus, plant, animal and fungal cells
Prokaryote organisation of DNA
Contain plasmids and a large circular DNA molecule associated with few or no proteins
Plasmid locations
Found in bacteria cells and some yeast cells
Eukaryotic cell chromosomal DNA organisation
DNA in the nucleus is found in linear form associated with proteins, they also contain small circles of DNA present in the chloroplasts and mitochondria
DNA in linear chromosomes
Tightly coiled around proteins to help package it into the nucleus
What is DNA replication important for
Mitosis
Correct model for DNA replication
Semi-conservative model
Before DNA replication can begin
The molecule must unwind and then the hydrogen bonds must break to separate the two strands creating a y-shaped replication fork
DNA polymerase and limitations
Enzyme that binds the sugar phosphate backbone together, can only add nucleotides to a pre-existing chain so primers must be present
Primer
A primer is a short sequence of nucleotides formed at the 3’ end of the leading strand and in several places on lagging strand, it allows bonding of sugar phosphate backbone to begin
DNA ligase
Joins fragments of DNA on the lagging strand
Replication of leading strand
A primer is formed at the 3’ end of the leading strand and free nucleotides align with their complementary base pairings on the strand, they become bound to the 3’ end of the primer, DNA ligase forms the sugar-phosphate backbone
Replication of lagging strand
Primers must form at different points on the lagging strand so DNA must be replicated in fragments. DNA polymerase binds free nucleotides to the primers to form these fragments and then DNA ligase joins the fragments together
There are many replication forks along the length of a
Chromosome
DNA can be replicated continuously from
5’ to 3’
PCR
The amplification of DNA, allows many copies to be created from one piece of DNA
In vitro
Outside the body of an organism
Roles of primers in PCR
Once DNA is separated the primers anneal to the 3’ ends of the DNA strands to allow Taq polymerase to start making a chain, the primer also acts a target section of DNA and Taq polymerase replicates it
Taq polymerase
Heat-tolerant DNA polymerase enzyme so that it does not become denatured at high temperatures as DNA needs to become denatured at this temperature
PCR stages
DNA molecule is denatured breaking the hydrogen bonds, solution is cooled to allow primers to anneal to the DNA, solution is heated to allow extension from primers, this process is usually repeated at least 30 times
PCR temperatures
95 degrees Celsius, 60 degrees Celsius, 72 degrees Celsius
Applications of PCR
Can be used as a tool in genetic fingerprinting, can be used as a diagnostic tool for genetic diseases and can be used for paternal identification
How is RNA different to DNA
It has uracil, ribose sugar and only one strand
Role of mRNA in protein synthesis
Carries genetic information from the nucleus to the ribosome in the cytoplasm
tRNA function in protein synthesis
Attached to amino acids and match up with mRNA codon to anticodon to form the correct sequence for a protein
Role of ribosomal RNA in protein synthesis
Make up a a ribosome along with a complex protein structure, tRNA combines with protein to form the large and small subunits which make up a ribosome
Transcription summary
The genetic code on DNA is used to determine the base sequence on mRNA
Three bases on DNA and mRNA names
DNA triplet, mRNA codon
RNA polymerase role in transcription
The enzyme responsible for transcription as it uncoils and unzips DNA so that mRNA can be made against a template strand, it also forms chemical bonds between nucleotides
Transcription stage 1
RNA polymerase uncoils and unzips DNA exposing the bases
Transcription stage 2
Free RNA nucleotides are attracted to the exposed bases and complementary base pairing takes place
Transcription stage 3
RNA polymerase forms covalent bonds between adjacent nucleotides
Transcription stage 4
When the mRNA is compete it breaks off and travels into the cytoplasm, this strand is known as the primary RNA transcript
Introns
Non-coding areas of a gene
Exons
Coding areas of a gene
Splicing
In transcription introns are cut out of the mRNA and the exons are spliced together to form an mRNA strand that can code for a protein
Two differences between tRNA and mRNA
tRNA molecules are 3D as they are folded back on themselves and hydrogen bonds form between bases. tRNA molecules have anticodons and mRNA molecules have codons
Two sites found on tRNA
Amino acid attachment site and anticodon
How many anticodons does a tRNA molecule have
1
Start and stop codons
Start codons code for the first amino acid on a polypeptide chain and stop codons do not code for an amino acid do stop the chain allowing it to peel off
tRNA role in translation
Pick up specific amino acids from the cytoplasm and carry them to the ribosome where they match up with mRNA
Translation stage 1
mRNA attaches to a ribosome
Translation stage 2
tRNA molecules carrying amino acids match up with mRNA at the ribosome anticodon to codon
Translation stage 3
Peptide bonds form between adjacent amino acids to form a polypeptide chain
Translation stage 4
This process is repeated until a stop codon is reached and the polypeptide chain is released from the ribosome
One gene, many proteins (methods)
Alternative splicing and post-translational modification
Alternative splicing explanation
alternative segments of DNA can be treated as exons and introns, this means a primary transcript can produce several different mRNA molecules from the same DNA strand as the base triplets are different
Importance of alternative splicing (antibodies)
It allows antibodies (for example) to have slightly different functions, some move freely and others are bound to the membrane of white blood cells
Post-translational modification
Once translation has been completed modification may be required to allow the protein to function correctly
Post-translational modification
Cleavage (insulin)
A polypeptide chain may be needed to be cut in order for it to become active, insulin cannot function as a single polypeptide so the central section is cut out so insulin can function as two polypeptides held together by sulphur bridges