Inequalities and Absolute Values Flashcards
(19 cards)
Inequality Addition
You can only add inequalities when their signs are in the same direction:
- If a > b and c > d (signs in same direction: > and >) –> a+c > b+d
- Example: 3 < 4 and 2 < 5 –> 3+2 < 4+5
Inequality Subtraction
You can only subtract inequalities when their signs are in the opposite directions:
- If a > b and c < d (signs in opposite directions: > and <) –> a-c > b-d
- Example: 5 > 1 and 3 < 4 → 5-3 > 1-4
Inequality Multiplication
If both sides of both inequalities are positive and the inequalities have the same sign, you can multiply them.
- x < a and y < b
- xy < ab
Inequality Division
But if both sides of both the inequalities are positive and the signs of the inequality are opposite, then you can divide them
- x < a and y > b
- x/y < a/b → final sign takes the sign of the numerator
Never multiply or divide an inequality by a variable unless the sign of the variable is known
px < 5x
→ p < 5 or
→ p > 5
Compound Inequality
When a compound inequality is divided or multiplied by a negative number, both of the signs must be reversed.
Multiple Inequalities
Set up a number line
e.g., If a > b, c > a, and d < b, what’s true?
Simplifying Inequalities with x2
If x2 > b and b is positive, then | x | > √b
→ x > √b or x < -√b
If x2 < b and b is positive, then | x | < √b
→ -√b < x < √b
The min or max value of xy
If a ≤ x ≤ b and c ≤ y ≤ d, to find the max and min value of xy, evaluate: ac, ad, bc, bd
- Max = the largest of these four
- Min = the smallest of these four
BE CAREFUL with the inequality signs. If a < x < b and c < y < d and x and y are integers, choose values that are within the range, not a, b, c, d!
If 2 absolute values are equal, it must be true that the expressions with the absolute value bars are either equal or opposite.
- 16x + 14 = 8x + 6
- 16x + 14 = -(8x + 6) → No need to test the other way around
Data sufficiency question: Does | r + s | = | m + n |?
- r + s = -m - n
- r + s = m + n
Answer = D.
16x + 14 | = | 8x + 6 | → Test 2 scenarios
Adding absolute values: | a + b | ≤ | a | + | b |
If | a + b | = | a | + | b |, either…
- One or both quantities is 0; or
- Both quantities are of the same sign
a + b | ≤ | a | + | b | is always true
Subtracting absolute values: | a - b | ≥ | a | - | b |
If | a - b | = | a | - | b |
- The 2nd quantity is 0; or
- Both quantities are of the same sign and the absolute value of the 1st quantity is ≥ the absolute value of the 2nd quantity
→ If b ≠ 0 and | a - b | = | a | - | b |, then a and b must have the same sign and | a | ≥ | b |
a - b | ≥ | a | - | b | is always true
→ a and b can be either positive or negative
If | x | < b
Then -b < x < b
If | x | > b
Then x > b or x < -b
If the absolute value of an expression is equal to a negative number…
There’s no solution
e.g., | x + 1 | = -2 → No need to solve.
BE CAREFUL: | x - 1 | = 2x → Solve it, but CHECK your answers
If x2 = | x |
x must be -1, 0, or 1
if x is none of these 3 values, then x2 > | x | or x2 < | x |
Is x2 > y2
Simplify and look at signs → (x+y)(x-y) > 0
Inequality Operations (example 1)
If 5a > 2b, is the sum of a and b greater than 0?
- 2b > 4a
- b > 0
Answer: D. For #1:
- 5a - 2b > 0 and 2b - 4a > 0
- Add them up → a > 0
- 2b > positive #, so b > 0 as well
Inequality Operations (example 2)
If x > y > 0, is x > 3?
- 2/x + 1/y = 11/15
- 2x + 3y = 16
Answer = D. Process = solve for y in terms of x, then substitute y in the x > y inequality