Information processing Flashcards

(35 cards)

1
Q
  1. Describe the overall process of transcription
A

The Transcription process is similar to Replication
- opening of bubble - seperation of strands - new molecule
- HOWEVER:
- In transcription only one strand from original DNA molecule is the template, the other is the coding strand
- Transcription has small bubble ~17bp open at one time and extends only in one direction, other end closes as one end opens.
- enzyme completely covers open strand
- RNA base pairs with one DNA template strand –> facilitated via RNA polymerase

Transcription in prokaryotes:
- chemical reaction catalysed by RNA polymerase is same as DNA polymerase, its just that an RNA strand is growing instead
- An NTP is an RNA nucleotide because it doesnt have d in front (dNTP - deoxynucleotide with deoxyribose sugar)
- New RNA strand also grows from 5’—>3’ end

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2
Q
  1. Identify the coding strand and template strand from a gene sequence.
A

Coding strand is the non-template strand
- this strand has same structure as transcribed RNA except for thymine instead of uracil

When we talk about “genes” we are talking about non-template CODING strand

IMPORTANT NOTE:
- Genes can face opposite directions because they are on different strands
- Genes may be transcribed from either strand and so either starnd can act like a coding or template strand

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3
Q
  1. Write the sequence of the coding strand, template strand or mRNA from a given coding strand, template strand or mRNA sequence.
A
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4
Q
  1. Explain how an RNA polymerase catalyses the formation of the RNA backbone
A

In Eukaryotes we have more complex system for transcription - 3 RNA polymerases
> RNA pol I = transcribes genes encoding for rRNA
> RNA pol II = transcribes genes encoding for mRNA
- identifies gene by finding a sequence in the promoter called TATA box
> RNA pol III = transcribes genes encoding for tRNA, rRNA and small RNA molecules

RNA POLYMERASE 2
- Same at its core like prokaryotes (has 2 Mg2+ ions and Aspartic acid residues)
- large and complex - 12 subunits
- grey proteins around outside are extra subunits in eukaryotes to allow for more transcription regulation which means more proteins can interact with RNA pol II to influence whether it transcribes a gene

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5
Q
  1. Explain how the location of a gene is defined in eukaryotes
A
  • A promoter is a DNA sequence upstream of the gene that tells RNA polymerase where to start transcription
  • Transcription start site is called +1 and is the first base of RNA transcript
    • everything downstream after +1 is part of RNA transcript
    • everything upstream before +1 is part of promoter region

–35 and –10 are binding sites for RNA polymerase’s sigma factor

They help position RNA polymerase correctly

The spacing between –35 and –10 (~17 bp) is important for efficient transcription

Promoters recognised by RNA polymerase II by eukaryotes
- TATA box located at -10 site of promotor in eukaryotes (Pribnow sequence for prokaryotes)
- Full sequence 5’ TATAAA 3’ - sequence has directionality
- RNA polymerase binds to that sequence to identify the gene after it and start transcription

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6
Q
  1. Define the term General Transcription factor
A

> RNA polymerase II requires the action of general transcription factors
- General transcription factors are required for expression of all genes, e.g. TBP or TF2IIA

TYPES OF TRANSCRIPTION FACTORS:
> General transcription factors - required for basic transcription (bind to promoter)
> Regulatory transcription factors (gene regulatory proteins) regulate expression of a subset of genes) - bind to operator or regulatory to control gene expression
e.g if there are two genes on a chromosome, it can activate transcription of one and suppress the other

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7
Q
  1. Describe the roles of RNA polymerase II, TBP, TFIIB, TFIIH in transcription
A
  1. TBP binds to TATA box on promoter where RNA pol II will bind to begin transcription
    - TBP looks like a dimer but it binds to DNA as a monomer
    - TBP causes huge gap in DNA
  2. TFIIB will bind to TBP on promoter that is bound to TATA box and recruits RNA pol II
  3. TFIIH also binds with other proteins for assembly - This protein assembly is called PREINITIATION COMPLEX (complex isnt working yet cuz other things are needed still for initiation)
  4. TF11H has helicase and kinase activity
    • unwinds DNA and phosphorylates specific region called CTD (C-terminal domain) of RNA pol II
  5. Now the PREINITIATION COMPLEX —> INITIATION COMPLEX - RNA polymerase starts to transcribe DNA
  6. Elongation factors assist in elongation of RNA as RNA polymerase moves 5’–>3’
  7. Elongation factors will dissociate and termination factors will bind –> terminates transcription at end of gene
  8. CTD phopsphorylation is facilitated by termination factors
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8
Q
  1. List the three major types of processing that occur to make a mature eukaryotic mRNA, where they occur in the cell, and the domain of RNA pol II that coordinates them
A

Eukaryotic mRNA is processed to make a mature mRNA:
1. 5’ Cap
2. PolyA tail
3. Splicing of introns

POLY A TAIL
🧬 POLY-A TAIL — SIMPLE EXPLANATION
What is it?

A chain of adenines (A’s) (like: AAAAAAA…) added to the 3’ end of eukaryotic mRNA.

🧪 PROCESS
🧾 Signal: mRNA has a special sequence near the end: AAUAAA

✂️ Cleavage: An endonuclease cuts the RNA just after this signal

➕ Polyadenylation: An enzyme called Poly(A) Polymerase adds 80–200 adenines to the cut end

📦 This creates the Poly-A Tail

🎯 WHY IT’S IMPORTANT
⏳ Increases mRNA stability (longer tail = longer life in cell)

🔁 Allows more translation (more protein copies made before it’s degraded)

📍 WHERE IT HAPPENS
On the CTD (C-terminal domain) of RNA Polymerase II

The CTD is like a platform or scaffold where all the processing machinery (splicing, capping, poly-A tail) assemble

CTD has a repeating sequence: Tyr-Ser-Pro-Thr-Ser-Pro-Ser (YSPTSPS) — this can be phosphorylated to regulate different steps

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9
Q
  1. Explain briefly the structure, role and attachment of a 5’ CAP
A

5’ cap is a modified nucleotide - 7-Methylguanosine that is added to 5’ end of RNA
-7-Methylguanosine is basically an upside down nucleotide and retains 3 phosphate groups instead of one when it binds to 5’ end of RNA because instead of binding to phophate, it binds to the 5’ carbon of the 7-Methylguanosine sugar
- The 5’ cap protects the 5’ end of RNA from endonuclease degradation but also allows recognition by translational machinery

LOCATION:
- CTD of RNA pol II is site of 5’ Capping
- cap is produced at CTD and RNA gets anchored whilst rest of RNA is being transcribed

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10
Q
  1. Briefly describe the process of mRNA splicing, including the overall structure of the ribosome, and the location of mRNA sequences of importance to splicing
A

🔹 What is splicing?
In eukaryotic pre-mRNA, there are:
Exons = coding parts (stay)
Introns = non-coding parts (removed)
Splicing = removing introns and joining exons

🔹 Who does the splicing?
Done by a large complex called the spliceosome
Spliceosome = snRNPs (small nuclear ribonucleoproteins, like U1, U2, U4) + proteins

🔹 Key RNA sequences in introns
5’ end of intron = always GU
3’ end of intron = always AG
Branch point = contains a key adenine (A) inside the intron

🔹 Splicing steps
1. U1 snRNP binds to the GU at 5’ end
2. U2 snRNP binds to the A (branch point)
3. More snRNPs (like U4, U5, U6) join → forming full spliceosome
4. GU site and A site are brought close together
5. A loop (called a lariat, like a lasso) forms between GU and A
6. The intron is cut out as the lariat

Exons are joined together
✅ Final result = mature mRNA with only exons

🔹 Where does this happen?
Happens while transcription is still happening
Splicing occurs at the CTD tail of RNA polymerase II
CTD = C-terminal domain
CTD acts like a platform that brings in the splicing machinery as RNA is made

🔑 Fast Mnemonic
GU–A–AG → Lariat → Cut → Join exons

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11
Q
  1. Translate a gene sequence using a genetic code table
A
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12
Q
  1. Define reading frame and explain how the reading frame of a gene is set
A

Genetic code on DNA and RNA is called the codon
> start codon = AUG
> stop codon = UAA, UAG, UGA
Genetic code is universal
DEGENERATE - some amino acids are encoded by many codons

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13
Q
  1. Predict the effect of a frameshift mutation
A

MUTATIONS
> Point mutation
- silent - dont alter amino acid sequence
- missense - codon codes for different amino acid
- nonsense - encodes a stop codon

> INDEL (frameshift) - moves codon out of frame
- insertion
- deletion

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14
Q
  1. Describe the overall process of translation
A
  1. TRNA needs to have an amino acid attached to it and then the first tRNA and ssRNA (small subunit of RNA) of ribosome binds to mRNA
    - First tRNA is METtRNa and finds to AUG codon of mRNA
    - Hence the start codon and METtRNA sets the reading frame for mRNA
  2. large subunit of ribosome binds and next tRNA comes in —> process of peptide bond formation can start
  3. peptide is produced until ribosome reaches stop codon - termination - peptide is released - protein folding occurs
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15
Q
  1. Describe the roles of the tRNA and ribosome and the aminoacyl-tRNA synthetases in translation
A

> Structure of TRNA (has 2 parts):
- Anticodon arm (reverse complement of codon) –> binds to codon
- Amino acid arm (binds to amino acid sequence coded by codon on mRNA)

> Class of enzymes - aminoacyl-tRNA sythetases for binding of amino acid to tRNA
- Bind & recognise specific tRNA and using ATP energy they add amino acid to amino acid arm (covalent linkage is between nucleic acid and amino acid)
1. Monomeric - Gln-tRNA (E.coli)
2. Dimeric - Asp-tRNA (yeast)

  • There is an ester linkage between nucleotide and carboxyl group of amino acid

Ribosomes
- composed of rNA and proteins
- 35% proteins on outside
- 65% of core is mainly rNA
- Proteins cant carry out the catalysis
- it is a ribozyme (enzyme/protein in active site) that does the catalysis
- no proteins within 18A of the active site where peptides are being formed

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16
Q
  1. Explain the importance of the nucleic acid components, the tRNA and the rRNA.
17
Q
  1. Identify the sequence of an anticodon for any given mRNA codon
18
Q
  1. Define wobble and explain how the sequence of the anticodon allows it to occur
A

In some cases one tRNA can read more than one codon because of an altered tRNA base at the third anticodon (5’ end of anticodon) which allows “wobble” in the third base of a codon, e.g. inosine I
- Inosine has different pattern of base pairing and can actually base pair with any of A, U or C
- So tRNA with inosine would be able to base pair with all 3 of these codons
- For example, CGU, CGC, CGA all encoding for arginine
- so these three codons only need one tRNA to bind as long as the 5’ end of the anticodon that binds to the 3’ end of the codon has an inosine
- Hence, you need fewer tRNA for binding compared to a large number of possible codons

Altered bases:
- Inosine
- 7-methylguanosine
- Psuedouridine
- 4-Thiouridine

Clear Definition:
“wobble” refers to the non-standard base pairing that can occur between the third position of a codon (on mRNA) and the first position of its corresponding anticodon (on tRNA).

19
Q
  1. Explain how the transcriptional start AUG is identified in both eukaryotes and prokaryotes
A

EUKARYOTES
- the ribosome binds the 5’cap and finds an AUG using the Kozak consensus sequence

PROKARYOTES
- Binding of ribosome is guided by Shine-Dalgarno sequence - the site at which ribosome binds
- Next AUG after Shine-Dalgarno sequence is the start codon
- concensus Shine-Dalgarno sequence is found upstream to the start codon
*concencus Shine-Dalgarno sequeucne is similarities between different Shine-Dalgarno sequences identified by different genes

20
Q
  1. Describe the process of the translation components moving through the sites of the ribosome
A

INITIATION
- assembly of components required for formation of peptide bonds between incoming amino acids
- more than 10 proteins involved in initiation adn more in elongation
1. Large subunit and Small subunit of ribosomes that come together
> has 3 different bind sites for tRNA:
- A site = tRNA bound to corresponding amino acid binds here (Aminoacyl tRNA)
- P site = tRNA holding the growing peptide bound here (peptidyl tRNA)
- E site = tRNA leaves (exit site)
- NOTE: ONLY 2 TRNA ARE EVER BOUND AT ONE TIME

ELONGATION
- 1st amino acid that is encoded by the tRNA is the N-terminus of growing polypeptide
- Amino acid bonded in P site is attached to its tRNA via carboxyl group –> opposite end is free amino group
- free amino group of incoming amino acid attacks carboxyl group of amino acid in P site –> breaks the bond between amino acid and tRNA in P site and forms a peptide bond the amino acid in the P site
- E.g. tRNA with 4th amino acid comes in at A site and forms peptide bond with 3rd amino acid at P site
- Growing chain at P site is passed tRNA of A site
- Empty tRNA of P site exits by E site and the growing chain moves into P site
- Large subunit of ribsome slides across followed by small subunit sliding across –> tRNA is A site is now in P site and tRNA is P site is in E site and exits the ribosome complex
- A new tRNA binds at A site and cycle continues until a stop codon is reached

Note - cytoplasm is crowded with tRNAs so only the correct tRNA at any one time that stays long enough in ribosome will form the peptide bond

“The carboxyl group of the amino acid in the P site is bound to the tRNA, and since peptide bonds form between the amino group of the incoming amino acid (in the A site) and the carboxyl group of the growing chain, the bond between the carboxyl group and the tRNA in the P site is broken. This transfers the growing polypeptide chain to the tRNA in the A site.”

TERMINATION
- no tRNA associated with stop codon
- instead a release factor protein binds to the stop codon
- release factor structure is similar to tRNA structure
- release factor will catalyse the hydroxylation of the carboxyl end of the last amino acid bound to the tRNA in the P site , essentially breaking bond between tRNA and growing peptide chain and allowing ribosome to then dissociate

21
Q
  1. Explain which chemical groups of the amino acids are interacting with other amino acids and with the tRNAs during translation
22
Q
  1. Describe the structure and role of a release factor
23
Q
  1. Define polycistronic mRNA
A
  • Prokaryotic mRNA can have several genes in the form of an operon that is controlled by a single promoter
  • When an operon is transcribed, it produces one mRNA with multiple coding regions - Called POLYCISTRONIC MRNA
  • Ribosome binds to multiple binding sites to translate protein required
24
Q
  1. Explain how transcription and translation are linked in prokaryotes but not eukaryotes
A
  • Lack of nucleus in prokaryotes means transcription and translation occurs simultaneously
25
25. Explain the role of a signal sequence and the process by which a ribosome delivers a polypeptide to the ER
Ribosomes in Eukaryotes can be found in two locations > cytosol > RER - Some proteins are modified - adding sugars to protein to form glycoproteins or adding lipids to form glycolipids - beginning of gene coding for these proteins have signal sequences that get transcribed aswell - this signal sequence gets translated first and pokes out of ribosome translating it - the complex (mRNA, peptide, ribosome) gets bound by a protein that transports it to the membrane of ER ---> complex binds to receptors on ER membrane - Polypeptide coming out of top of large ribosomal unit goes into lumen of ER - signal sequence gets removed and the protein releases from ribosome to be modified and transported to different places - a signal peptide is at the start of the protein sequence for those proteins that are modified, trafficked or secreted - rough ER is named because of the blobs of ribosome attached to the membranes of ER - from the lumen of ER it is sorted through the Golgi apparatus to be trafficked to anywhere in the cell or out of the cell 🧬 Where are ribosomes found in eukaryotes? In the cytosol – make proteins that stay in the cell. On the rough ER – make proteins that are secreted, sent to membranes, or modified. 🏷️ How do proteins go to the rough ER? 1. The mRNA has a signal sequence at the start of the gene (gets translated first). 2. This signal peptide sticks out of the ribosome as the protein starts being made. 3. A special protein binds the ribosome-mRNA complex and guides it to the ER membrane. 3. The complex binds a receptor on the ER. 4. The new protein is fed into the ER as it's being made (into the ER lumen). 5. The signal sequence is cut off. 6. The protein is modified (e.g., sugars/lipids added). 7. The protein is then sent to the Golgi apparatus, where it is sorted and sent to where it needs to go (in the cell or out of it). 📦 Summary: Proteins that are secreted or modified start with a signal. Ribosomes go to the rough ER to make them. Proteins enter the ER, get processed, then go to the Golgi to be shipped to the right location. ✅ Translation begins in the cytosol, and if the protein being made has a signal peptide, then: Translation starts in the cytosol. The signal peptide gets translated and pokes out of the ribosome. The SRP binds the signal peptide → pauses translation. The whole complex (ribosome + mRNA + growing polypeptide) is moved to the ER. Once attached to the ER, translation resumes, and the protein is threaded into the ER lumen. So yes, translation is initiated in the cytosol, then completed on the ER if it's a secreted or membrane protein.
26
26. Briefly describe the structure of the human genome, including what proportion is coding, and what are the most common repetitive sequences
- A third of the human genome is actually coding > 45% is made of transposons (mobile elements) - A transposon is an active piece of DNA that can MOVE from place to place and is usually found in between genes or inside introns - DNA transposons move using DNA intermediate - Retrotransposons move using RNA intermediate *They arent really moving, just are making new copy of themselves in RNA using reverse transcriptase to make DNA copy that inserts elsewhere in genome - predominantly LINE and SINE segments > SINES & LINES = Retrotransposons - Retrotransposons are remnant of retrovirus that no longer makes coat (capsid) or move out of cell - they can only integrate into DNA and can be transcribed/translated - can't leave cell - Central dogma said copies of DNA can be made by DNA replication copies of RNA can be made by transcription for protein translation - But reverse transcriptase does this in reverse - takes RNA and makes DNA copy - LINES = 6kb long and has open reading frame encoding for reverse transcriptase *reverse transcriptase can only make one copy of LINE elements from RNA into DNA which can insert somewhere else (autonomously) - SINE = 350bp long and dont encode reverse transcriptase so cant move autonomously *can only move from one place to the other in a genome is there is a LINE element producing reverse transcriptase that can act on RNA of SINE elements > RETROVIRUSES: - Bind to plasma membrane and inject their RNA genome and reverse-transcriptase into another cell's cytosol - Reverse-transcriptase converts ssRNA into dsDNA - DsDNA can integrated into host genome and another viral genome in RNA can be produced by transcription - mRNA is translated to produce proteins in virus capsids and enzymes like reverse-transcriptase - these proteins get assembled into new virus particles and bursts out of cell to infect other cells - This is a retrovirus not a retrotransposon 🧬 Human Genome: Only ~1/3 of our genome codes for proteins. ~45% is made of transposons – bits of DNA that can copy and insert themselves elsewhere. 🔄 Transposons (Jumping Genes): Two Types: - DNA Transposons – move as DNA. - Retrotransposons – move using RNA → DNA (via reverse transcriptase). 🌀 Retrotransposons: They don't actually "move" — they: Get transcribed into RNA. Use reverse transcriptase to turn that RNA into DNA. That new DNA inserts somewhere else in the genome. 📏 Types of Retrotransposons: 1. LINEs (Long Interspersed Nuclear Elements) ~6,000 bases long. Encode reverse transcriptase → can copy themselves. Move on their own. 2. SINEs (Short Interspersed Nuclear Elements) ~350 bases long. Don’t have reverse transcriptase. Need LINEs to help them move. REVERSE TRANSCRIPTASE USE: | Who uses it? | Why? | **Retroviruses** | To insert their genome into host DNA so they can hijack the cell | | **Retrotransposons** | To make DNA copies of themselves and "jump" to new genome locations | | **Molecular biology** | Scientists use it to make DNA from RNA (e.g., making cDNA from mRNA) |
27
27. Explain the relationship between retrotransposons and retroviruses
28
28. Define and compare LINEs and SINEs
29
29. Compare the features of the human nuclear genome and the human mitochondrial genome
Nuclear genome - only 1.5% is coding - rest is are introns and non-coding Mitochondrial genome - more densely packed - No introns and genes dont have much space between them - variation in genetic code - 4 of 64 genes are unique - fewer tRNAs used - mitochondria produces own tRNA - circular genome - mitochondria needs proteins encoded by both mitochondrial and nuclear genome
30
30. Explain the significance of the two human genomes to genetic diseases affecting mitochondria
- Mitochondrial diseases affect energy development, vision and cause seizures - Can be caused by mutations in mitochondrial genome or mitochondrial genes in nuclear genome
31
31. Explain the technique of semi-quantitative RT-PCR for examining gene expression
Molecular Biologists may ask following questions about a gene: - What cell type expresses the gene1? - Under what conditions do they express it? - What can change or control the expression of gene1?
32
32. List the major reagents of semi-quantitative RT-PCR and define which are specific for the gene of interest
33
33. Explain the technique of Western blots for examining gene expression
34
34. Compare the techniques and applications of RT-PCR and Western blots
35
Steps of Translation in brief?
1. The small subunit of the ribosome binds to the Met-tRNA at the P site first and the mRNA. 4. The large subunit of the ribosome binds to the mRNA 3. An amino-acyl tRNA base pairs with the codon in the A site. 5. The ribosome catalyses the formation of a peptide bond. 2. The ribosome moves along so that the tRNA in the A site is moved into the P site.