Information processing Flashcards
(35 cards)
- Describe the overall process of transcription
The Transcription process is similar to Replication
- opening of bubble - seperation of strands - new molecule
- HOWEVER:
- In transcription only one strand from original DNA molecule is the template, the other is the coding strand
- Transcription has small bubble ~17bp open at one time and extends only in one direction, other end closes as one end opens.
- enzyme completely covers open strand
- RNA base pairs with one DNA template strand –> facilitated via RNA polymerase
Transcription in prokaryotes:
- chemical reaction catalysed by RNA polymerase is same as DNA polymerase, its just that an RNA strand is growing instead
- An NTP is an RNA nucleotide because it doesnt have d in front (dNTP - deoxynucleotide with deoxyribose sugar)
- New RNA strand also grows from 5’—>3’ end
- Identify the coding strand and template strand from a gene sequence.
Coding strand is the non-template strand
- this strand has same structure as transcribed RNA except for thymine instead of uracil
When we talk about “genes” we are talking about non-template CODING strand
IMPORTANT NOTE:
- Genes can face opposite directions because they are on different strands
- Genes may be transcribed from either strand and so either starnd can act like a coding or template strand
- Write the sequence of the coding strand, template strand or mRNA from a given coding strand, template strand or mRNA sequence.
- Explain how an RNA polymerase catalyses the formation of the RNA backbone
In Eukaryotes we have more complex system for transcription - 3 RNA polymerases
> RNA pol I = transcribes genes encoding for rRNA
> RNA pol II = transcribes genes encoding for mRNA
- identifies gene by finding a sequence in the promoter called TATA box
> RNA pol III = transcribes genes encoding for tRNA, rRNA and small RNA molecules
RNA POLYMERASE 2
- Same at its core like prokaryotes (has 2 Mg2+ ions and Aspartic acid residues)
- large and complex - 12 subunits
- grey proteins around outside are extra subunits in eukaryotes to allow for more transcription regulation which means more proteins can interact with RNA pol II to influence whether it transcribes a gene
- Explain how the location of a gene is defined in eukaryotes
- A promoter is a DNA sequence upstream of the gene that tells RNA polymerase where to start transcription
- Transcription start site is called +1 and is the first base of RNA transcript
- everything downstream after +1 is part of RNA transcript
- everything upstream before +1 is part of promoter region
–35 and –10 are binding sites for RNA polymerase’s sigma factor
They help position RNA polymerase correctly
The spacing between –35 and –10 (~17 bp) is important for efficient transcription
Promoters recognised by RNA polymerase II by eukaryotes
- TATA box located at -10 site of promotor in eukaryotes (Pribnow sequence for prokaryotes)
- Full sequence 5’ TATAAA 3’ - sequence has directionality
- RNA polymerase binds to that sequence to identify the gene after it and start transcription
- Define the term General Transcription factor
> RNA polymerase II requires the action of general transcription factors
- General transcription factors are required for expression of all genes, e.g. TBP or TF2IIA
TYPES OF TRANSCRIPTION FACTORS:
> General transcription factors - required for basic transcription (bind to promoter)
> Regulatory transcription factors (gene regulatory proteins) regulate expression of a subset of genes) - bind to operator or regulatory to control gene expression
e.g if there are two genes on a chromosome, it can activate transcription of one and suppress the other
- Describe the roles of RNA polymerase II, TBP, TFIIB, TFIIH in transcription
- TBP binds to TATA box on promoter where RNA pol II will bind to begin transcription
- TBP looks like a dimer but it binds to DNA as a monomer
- TBP causes huge gap in DNA - TFIIB will bind to TBP on promoter that is bound to TATA box and recruits RNA pol II
- TFIIH also binds with other proteins for assembly - This protein assembly is called PREINITIATION COMPLEX (complex isnt working yet cuz other things are needed still for initiation)
- TF11H has helicase and kinase activity
- unwinds DNA and phosphorylates specific region called CTD (C-terminal domain) of RNA pol II
- Now the PREINITIATION COMPLEX —> INITIATION COMPLEX - RNA polymerase starts to transcribe DNA
- Elongation factors assist in elongation of RNA as RNA polymerase moves 5’–>3’
- Elongation factors will dissociate and termination factors will bind –> terminates transcription at end of gene
- CTD phopsphorylation is facilitated by termination factors
- List the three major types of processing that occur to make a mature eukaryotic mRNA, where they occur in the cell, and the domain of RNA pol II that coordinates them
Eukaryotic mRNA is processed to make a mature mRNA:
1. 5’ Cap
2. PolyA tail
3. Splicing of introns
POLY A TAIL
🧬 POLY-A TAIL — SIMPLE EXPLANATION
What is it?
A chain of adenines (A’s) (like: AAAAAAA…) added to the 3’ end of eukaryotic mRNA.
🧪 PROCESS
🧾 Signal: mRNA has a special sequence near the end: AAUAAA
✂️ Cleavage: An endonuclease cuts the RNA just after this signal
➕ Polyadenylation: An enzyme called Poly(A) Polymerase adds 80–200 adenines to the cut end
📦 This creates the Poly-A Tail
🎯 WHY IT’S IMPORTANT
⏳ Increases mRNA stability (longer tail = longer life in cell)
🔁 Allows more translation (more protein copies made before it’s degraded)
📍 WHERE IT HAPPENS
On the CTD (C-terminal domain) of RNA Polymerase II
The CTD is like a platform or scaffold where all the processing machinery (splicing, capping, poly-A tail) assemble
CTD has a repeating sequence: Tyr-Ser-Pro-Thr-Ser-Pro-Ser (YSPTSPS) — this can be phosphorylated to regulate different steps
- Explain briefly the structure, role and attachment of a 5’ CAP
5’ cap is a modified nucleotide - 7-Methylguanosine that is added to 5’ end of RNA
-7-Methylguanosine is basically an upside down nucleotide and retains 3 phosphate groups instead of one when it binds to 5’ end of RNA because instead of binding to phophate, it binds to the 5’ carbon of the 7-Methylguanosine sugar
- The 5’ cap protects the 5’ end of RNA from endonuclease degradation but also allows recognition by translational machinery
LOCATION:
- CTD of RNA pol II is site of 5’ Capping
- cap is produced at CTD and RNA gets anchored whilst rest of RNA is being transcribed
- Briefly describe the process of mRNA splicing, including the overall structure of the ribosome, and the location of mRNA sequences of importance to splicing
🔹 What is splicing?
In eukaryotic pre-mRNA, there are:
Exons = coding parts (stay)
Introns = non-coding parts (removed)
Splicing = removing introns and joining exons
🔹 Who does the splicing?
Done by a large complex called the spliceosome
Spliceosome = snRNPs (small nuclear ribonucleoproteins, like U1, U2, U4) + proteins
🔹 Key RNA sequences in introns
5’ end of intron = always GU
3’ end of intron = always AG
Branch point = contains a key adenine (A) inside the intron
🔹 Splicing steps
1. U1 snRNP binds to the GU at 5’ end
2. U2 snRNP binds to the A (branch point)
3. More snRNPs (like U4, U5, U6) join → forming full spliceosome
4. GU site and A site are brought close together
5. A loop (called a lariat, like a lasso) forms between GU and A
6. The intron is cut out as the lariat
Exons are joined together
✅ Final result = mature mRNA with only exons
🔹 Where does this happen?
Happens while transcription is still happening
Splicing occurs at the CTD tail of RNA polymerase II
CTD = C-terminal domain
CTD acts like a platform that brings in the splicing machinery as RNA is made
🔑 Fast Mnemonic
GU–A–AG → Lariat → Cut → Join exons
- Translate a gene sequence using a genetic code table
- Define reading frame and explain how the reading frame of a gene is set
Genetic code on DNA and RNA is called the codon
> start codon = AUG
> stop codon = UAA, UAG, UGA
Genetic code is universal
DEGENERATE - some amino acids are encoded by many codons
- Predict the effect of a frameshift mutation
MUTATIONS
> Point mutation
- silent - dont alter amino acid sequence
- missense - codon codes for different amino acid
- nonsense - encodes a stop codon
> INDEL (frameshift) - moves codon out of frame
- insertion
- deletion
- Describe the overall process of translation
- TRNA needs to have an amino acid attached to it and then the first tRNA and ssRNA (small subunit of RNA) of ribosome binds to mRNA
- First tRNA is METtRNa and finds to AUG codon of mRNA
- Hence the start codon and METtRNA sets the reading frame for mRNA - large subunit of ribosome binds and next tRNA comes in —> process of peptide bond formation can start
- peptide is produced until ribosome reaches stop codon - termination - peptide is released - protein folding occurs
- Describe the roles of the tRNA and ribosome and the aminoacyl-tRNA synthetases in translation
> Structure of TRNA (has 2 parts):
- Anticodon arm (reverse complement of codon) –> binds to codon
- Amino acid arm (binds to amino acid sequence coded by codon on mRNA)
> Class of enzymes - aminoacyl-tRNA sythetases for binding of amino acid to tRNA
- Bind & recognise specific tRNA and using ATP energy they add amino acid to amino acid arm (covalent linkage is between nucleic acid and amino acid)
1. Monomeric - Gln-tRNA (E.coli)
2. Dimeric - Asp-tRNA (yeast)
- There is an ester linkage between nucleotide and carboxyl group of amino acid
Ribosomes
- composed of rNA and proteins
- 35% proteins on outside
- 65% of core is mainly rNA
- Proteins cant carry out the catalysis
- it is a ribozyme (enzyme/protein in active site) that does the catalysis
- no proteins within 18A of the active site where peptides are being formed
- Explain the importance of the nucleic acid components, the tRNA and the rRNA.
- Identify the sequence of an anticodon for any given mRNA codon
- Define wobble and explain how the sequence of the anticodon allows it to occur
In some cases one tRNA can read more than one codon because of an altered tRNA base at the third anticodon (5’ end of anticodon) which allows “wobble” in the third base of a codon, e.g. inosine I
- Inosine has different pattern of base pairing and can actually base pair with any of A, U or C
- So tRNA with inosine would be able to base pair with all 3 of these codons
- For example, CGU, CGC, CGA all encoding for arginine
- so these three codons only need one tRNA to bind as long as the 5’ end of the anticodon that binds to the 3’ end of the codon has an inosine
- Hence, you need fewer tRNA for binding compared to a large number of possible codons
Altered bases:
- Inosine
- 7-methylguanosine
- Psuedouridine
- 4-Thiouridine
Clear Definition:
“wobble” refers to the non-standard base pairing that can occur between the third position of a codon (on mRNA) and the first position of its corresponding anticodon (on tRNA).
- Explain how the transcriptional start AUG is identified in both eukaryotes and prokaryotes
EUKARYOTES
- the ribosome binds the 5’cap and finds an AUG using the Kozak consensus sequence
PROKARYOTES
- Binding of ribosome is guided by Shine-Dalgarno sequence - the site at which ribosome binds
- Next AUG after Shine-Dalgarno sequence is the start codon
- concensus Shine-Dalgarno sequence is found upstream to the start codon
*concencus Shine-Dalgarno sequeucne is similarities between different Shine-Dalgarno sequences identified by different genes
- Describe the process of the translation components moving through the sites of the ribosome
INITIATION
- assembly of components required for formation of peptide bonds between incoming amino acids
- more than 10 proteins involved in initiation adn more in elongation
1. Large subunit and Small subunit of ribosomes that come together
> has 3 different bind sites for tRNA:
- A site = tRNA bound to corresponding amino acid binds here (Aminoacyl tRNA)
- P site = tRNA holding the growing peptide bound here (peptidyl tRNA)
- E site = tRNA leaves (exit site)
- NOTE: ONLY 2 TRNA ARE EVER BOUND AT ONE TIME
ELONGATION
- 1st amino acid that is encoded by the tRNA is the N-terminus of growing polypeptide
- Amino acid bonded in P site is attached to its tRNA via carboxyl group –> opposite end is free amino group
- free amino group of incoming amino acid attacks carboxyl group of amino acid in P site –> breaks the bond between amino acid and tRNA in P site and forms a peptide bond the amino acid in the P site
- E.g. tRNA with 4th amino acid comes in at A site and forms peptide bond with 3rd amino acid at P site
- Growing chain at P site is passed tRNA of A site
- Empty tRNA of P site exits by E site and the growing chain moves into P site
- Large subunit of ribsome slides across followed by small subunit sliding across –> tRNA is A site is now in P site and tRNA is P site is in E site and exits the ribosome complex
- A new tRNA binds at A site and cycle continues until a stop codon is reached
Note - cytoplasm is crowded with tRNAs so only the correct tRNA at any one time that stays long enough in ribosome will form the peptide bond
“The carboxyl group of the amino acid in the P site is bound to the tRNA, and since peptide bonds form between the amino group of the incoming amino acid (in the A site) and the carboxyl group of the growing chain, the bond between the carboxyl group and the tRNA in the P site is broken. This transfers the growing polypeptide chain to the tRNA in the A site.”
TERMINATION
- no tRNA associated with stop codon
- instead a release factor protein binds to the stop codon
- release factor structure is similar to tRNA structure
- release factor will catalyse the hydroxylation of the carboxyl end of the last amino acid bound to the tRNA in the P site , essentially breaking bond between tRNA and growing peptide chain and allowing ribosome to then dissociate
- Explain which chemical groups of the amino acids are interacting with other amino acids and with the tRNAs during translation
- Describe the structure and role of a release factor
- Define polycistronic mRNA
- Prokaryotic mRNA can have several genes in the form of an operon that is controlled by a single promoter
- When an operon is transcribed, it produces one mRNA with multiple coding regions - Called POLYCISTRONIC MRNA
- Ribosome binds to multiple binding sites to translate protein required
- Explain how transcription and translation are linked in prokaryotes but not eukaryotes
- Lack of nucleus in prokaryotes means transcription and translation occurs simultaneously