Lecture 10 Chemistry Flashcards

(38 cards)

1
Q

Threshold E to produce e transitions in water

A

7.4 ev

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

Depending on the amount of E transferred to the e, the molecule can undergo

A

ionization (E threshold in water 13eV, excitation (7.4 ev), thermal transfer (vibrational rotation)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

Average E loss and most probably E loss

A

E straggling

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

E needed to break C=C

A

4.9 ev

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

cell composition

A

70-85% H2O, 10-20% protein, 10% carbs, 2-3% lipids

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

Initial physical event

A

transfer of 7-100 ev to cause ionizations or excitations in H2O molecule

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

E of subexcitation e in H2O

A

<7.4 ev

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

The time scale for physical stage

A

10^(-16)s

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

Species produced at the physical stage of the interaction of particle in water

A

H2O* (excitation), H2O+ (ionization), e (E=7.4 ev)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

Prechemical stage

A

initial reactants produce radicals as they diffuse in medium.

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

what is a radical

A

atom that contains an unpaired e and thus is very reactive (can be neutral or charged)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

what is a e aq

A

e captured by water through dipolar interactions, becoming solvated

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

E needed to break O-H bond

A

5 ev

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

Name radicals produced in water due to irradiation

A

H2O8=HO. (oxidizer)+ H., H2O+ = H+ + OH., H2O-= H. +OH-, ,and e aq from H2O

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

what is oxidation

A

the loss of e. e transferred to an oxidizing agent which becomes reduced

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

Time scale for prechemical stage

A

10^-15-10^-12 s

17
Q

Chemical stage time scale

18
Q

Characterize the chemical stage

A

the radicals and ions react with each other HO. +HO. = H2O2, HO. +e aq = OH-, HO. +H. = H2O , H+ + e aq=H. and etc. Most of the reactions remove the chemically reactive species

19
Q

Time when most of the radicals and ions diffuse that far that the further reaction is unlikely

A

10^-6. The chemical stage is over by this time. G value will not change after

20
Q

the formula for radical diffusion

A

D = distance^2/6 time

21
Q

Simulations of the track of charged particle is possible via

A

Monte Carlo method : generation of e, passage model. generations of reactive species, diffusion of species, recombination events.

22
Q

G value

A

Radiochemical yield: # of species produced/100 ev of E loss by charged particle and its secondaries when it stops in water.

23
Q

How different the species produced by a, b, e radiation in 10^-15s in track regions

A

they are the same H2O*, H2O+, e. The difference in the spatial E deposition patterns (track density)

24
Q

Limitation of Fricke dosimeter

A

stong LET dependence

25
Fricke dosimeter characteristics
a most useful method to measure # of reactive species in solution; 1mM FeSO4 in 0.8M H2SO4: when irradiated Fe2+ oxidized to Fe3+ which has blue color (spectrophotometer measurement), D response linear up to 400 Gy and up to 700Gy
26
How many Fe3+ are produced in Fricke dosimeter
G= 2G(H2O2)+3G(H.)+G(HO.) if O2 is present, otherwise: | G(H)+G(OH)+2G(H2O2)
27
What is the use of a Fricke dosimeter?
to test scavengers and the effect of LET on E deposition as an effect on scavengerable species
28
Direct effect of radiation
E deposited into a molecule (DNA): ionization, excitation leading to radicals formation inside the biomolecule. The dose-response relationship is linear
29
Indirect action of radiation
ionization of the solvent molecules. Indirect actions are diffusion-limited and the dose-response rate can be complex.
30
Primary species that are responsible for rad damage in DNA
HO.
31
For high LET radiations
direct action is a predominant mechanism of DNA damage
32
Repair processes of DNA damage
Recombination, restoration, repair
33
Recombination of DNA
recombination: reaction of nearby radical with the DNA radical to regenerate the original DNA (<10^-11s);
34
Restoration
restitution: chem restoration of DNA (no enzyme involved). Some intracellular agents can react with radicals
35
The most important intracellular agent that reacts with radicals
gsh glutathione. It donates one H. to the DNA and restores it. <10^-3s
36
Repair stage of DNA
cellular enzymes recognize damage and repair DNA within min and hours
37
Scavengers
Chemicals that can react with reactive species like HO. can block indirect effects of radiation: can be helpful in estimating the relative contributions of direct and indirect effects; define chemistry, and they showed that 60-70% of all damages from low LET are caused by HO.
38
name several scavenger reactants
N2O, O2, Acid