Lecture 2: Central Metabolism, PPP, and ED pathway - Exam 4 Flashcards

1
Q

Who has the Pentose Phosphate Pathway? Why is PPP required?

A

It is highly conserved and found in all three domains.
PPP doesn’t produce reducing agents for ETC, but produces NADPH for biosynthetic reductions and aromatic AA precursors. It produces sugars required to produce DNA and RNA. No ATP is used or produced in the PPP.

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2
Q

Who uses the Enter-Duodoroff pathway (ED)? What is it primarily used for?

A

ED is unique to prokaryotes and widespread among G- bacteria.
It is primarily used for growth on gluconic acids or by strict aerobes incapable of carrying out Phase 1 of glycolysis.

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3
Q

What is the PPP?

A

An alternative branch off glycolysis that produces the pentose sugars that make up DNA and RNA, and for the 4-carbon molecules needed for aromatic amino acids.

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4
Q

What are the two phases of the PPP?

A

Oxidative phase and non-oxidative phase.

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5
Q

What are the two reducing agents? What do each of them do?

A

NADH and NADPH are both important reducing agents.
NADH: donates e- to ETC
NADPH: donates e- for biosynthesis (anabolic reactions).

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6
Q

What is the ratio of NAD+ to NADH?
What is the ratio of NADP+ to NADPH?

A

The ratio of NAD+ to NADH is high (more NAD+ than NADH)
The ratio of NADP+ to NADPH is low (more NADPH than NADP+)

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7
Q

What is NAD+ needed for?
What is NADPH needed for?

A

NAD+ is needed as an oxidizing agent (e- acceptor) for all sorts of catabolic reactions.
NADPH is needed as a reducing agent to donate electrons in anabolic reactions.

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8
Q

NADPH has a similar structure to what other molecule?

A

NADH, which is a high energy electron shuttle.

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9
Q

Describe NADPH. What is it often used in? What role does it play? Why is its structure important?

A

NADPH has an added phosphate group that is used in the cell to donate electrons, just like NADH.
NADPH is used in reactions that build molecules (e.g. Calvin cycle) and occurs in a high concentration in the cell, so that it is readily available for these types of reactions.
NADPH plays a vital role in the glutathione detoxification of reactive oxygen species that protects cells from oxidative stress.

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10
Q

What are the four main reasons that the PPP is important?

A
  1. Production of precursor (ribose-5-phosphate) for nucleic acids.
  2. Production of erythrose-4-phosphate (precursor of aromatic amino acids.)
  3. Production of NADPH, a major reducing molecule for anabolic reactions. (NADPH can also be generated during photosynthesis ore reverse electron flow in some bacteria, but the PPP is a major pathway)
  4. Catabolism of pentoses or nucleic acids as a carbon source (as with hemicellulose degradation for biofuels).
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11
Q

Describe the oxidative phase.

A

From Glucose-6-phosphate to Ribulose-5-phosphate.
-During this phase, NADPH is generated.
-There are three irreversible reactions in the oxidative phase:
First reaction by the glucose-6-phosphate dehydrogenase is the rate-limiting enzyme of the PPP. Two oxidations lead to synthesis of two NADPH, which is needed for many anabolic reactions.

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12
Q

Glucose-6-phosphate dehydrogenase is the rate-limiting enzyme of the PPP. What does it catalyze?

A

The first reaction, Glucose-6-phosphate to 6-phosphogluconolactone.

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13
Q

The regulation of glucose-6-phosphate dehydrogenase has consequences. What are they? What is this enzyme activated by?

A

The regulation of glucose-6-phosphate dehydrogenase has downstream consequences for the activity of the rest of the PPP.
It is activated by its substrate, glucose-6-phosphate, and low levels of NADPH.

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14
Q

What happens in the non-oxidative phase of PPP? What are the starting molecules? How many reactions are reversible?

A

The ribulose-5-phosphate is converted to ribose-5-phosphate, which may be needed for nucleotide biosynthesis.
If not, the excess ribose-5-phosphate can be converted into other molecules that can be used by the cell:
as a precursor for amino acids (4-carbon molecule) or used in glycolysis (3-carbon or 6-carbon molecules) for energy and/or other metabolic precursors.
All of the reactions are reversible (4).
The starting molecules are ribose-5-phosphate or xylulose-5-phosphate.
Fructose-6-phosphate and glyceraldehyde-3-phosphate go to glycolysis.

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15
Q

What determines if ribulose-5-phosphate (from the oxidative phase) is converted to to ribose-5-phosphate or xylulose-5-phosphate?

A

It is all depending on what the cell needs. It is very modular. If the cell needs nucleotides, then it will convert it to ribose-5-phosphate. If it needs glyceraldehyde-3-phosphate and fructose-6-phosphate to go to glycolysis, then it will convert it to xylulose-5-phosphate.

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16
Q

Who has the Entner-Duodoroff pathway?

A

Only prokaryotes, and is wide-spread among gram negative bacteria.

17
Q

Explain the divergent pathways from 6-phosphogluconate.

A

In glycolysis, PPP, and ED, glucose is converted to glucose-6-phosphate during step 1.
-At this point, the PPP and ED pathways diverge.
Bacteria using PPP and ED convert G-6-P to 6-phosphogluconolactone, then to 6-phosphogluconate.
-From 6-phosphogluconate, the PPP and ED pathways diverge.

18
Q

What are the two enzymes specific to the ED pathway not found in glycolysis or PPP?

A

6-phosphogluconate dehydratase and KDPG aldolase

19
Q

What does the ED pathway generate?

A

1 molecules of glyceraldehyde-3-phosphate (and one molecule of pyruvate) from glucose.
Also generates 1 ATP and 1 NADH (vs. 2 ATP and 2 NADH for glycolysis) and NADPH (not generated in glycolysis).

20
Q

Which reactions in the ED are common with glycolysis?

A

1, 5, 6, 7, 8, 9 steps in the ED are shared with glycolysis (enzymes are the same here, too)

21
Q

Which reactions in the ED are common with PPP?

A

Step 2 in the ED is shared with the PPP (enzymes are the same here, too)

22
Q

Which steps are unique to the ED pathway?

A

Steps 3 & 4.
3: 6-phosphogluconate dehydratase
4: KDPG aldolase

23
Q

In the PPP, each molecule of G-6-P in the oxidative phase yields?

A

2 NADPH and 1 ribulose-5-phosphate. 1 C is lost as CO2.

24
Q

What is the overall reaction for PPP?

A

3M Glucose-6-P –> 3CO2 + 1PGALD + 6NADPH + 6H+

25
Q

What is the overall reaction for ED pathway?

A

1M Glucose –> 2 Pyruvate + 1 NADPH + 1 NADH + 2H+ + 1ATP

26
Q

The ED pathway shares its second step with the PPP pathway. What happens in this step and what does it yield?

A

Uses G-6-P dehydrogenase for conversion of G-6-P to 6-phosphogluconate (both pathways share this). This oxidation step yields 1 NADPH (again this is shared)

27
Q

What does 6-phosphogluconate dehydratase do?

A

Converts 6-P-gluconate to KDPG.

28
Q

What does KDPG aldolase do?

A

KDPG aldolase generates 1 Pyruvate and 1 PGALD from KDPG.
-The second pyruvate is generated from the conversion of the PGALD via the glycolytic payoff pathway.

29
Q

Glycolysis, PPP and ED pathways all result in the production of?

A

Pyruvate

30
Q

Aerobically, how is pyruvate oxidized to Acetyl-CoA?

A

1) A carboxyl group is removed from pyruvate, releasing carbon dioxide.
2) NAD+ is reduced to NADH
3) An acetyl group is transferred to coenzyme A, resulting in acetyl CoA.

31
Q

What does pyruvate dehydrogenase do?
How is the pyruvate dehydrogenase reaction inhibited? Why is it important? How is the enzyme stimulated?

A

The activity of pyruvate dehydrogenase enzyme regulates how much pyruvate is converted to acetyl CoA to enter the TCA cycle.
Pyruvate dehydrogenase activity is regulated by PEP or AMP and negatively by NADH or acetyl-CoA. When PEP and/or AMP is high, more pyruvate is converted to acetyl CoA. When NADH and/or acetyl-CoA is high, this assures that the cell only produces the amount of acetyl CoA that can be used immediately.

32
Q

What happens to acetyl-CoA generated by pyruvate dehydrogenase?

A

It is oxidized to CO2 in the TCA cycle or in glyoxylate shunt to oxaloacetic acid and succinate during respiratory growth. During fermentative growth, converted to acetate or to ethanol.

33
Q

Anaerobically, pyruvate-ferredoxin oxidoreductase or pyruvate-formate lyase can be used. What are the electron acceptors in each? Why would this be important for fermenting organisms?

A

Pyruvate-ferredoxin oxidoreductase: certain anaerobes, sulfur-reducing bacteria, and some archaea use. This involves oxidation and decarboxylation of pyruvate to acetyl-CoA with ferredoxin as e- acceptor instead of NAD+ (b/c is is more difficult to oxidize NADH to NAD+ in anaerobic/fermenting conditions).
Pyruvate-formate Lyase:
Some fermenting bacteria. A carboxyl is removed instead of CO2, so no other molecule is reduced - instead electrons stay with the carboxyl group in formate. Neither ferredoxin nor NADH are formed, so neither need to be oxidized.