Lecture 2 - Rotational spectroscopy Flashcards

1
Q

What is rotational spectroscopy?

A

-Involves the rotation of molecules measured relative to a fixed axis in a lab.
-Very low energy transitions.
-Only done with gases at low pressure (important).
-Need low temps and press as too high will have too much collisions and the detail will decrease as lines become broad.

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2
Q

What is moment of intertia?

A

-Depends on the mass and how far away it is from the rotation axis.
-Large moments of inertia are called disks, most mass is away from the centre - example benzene ring.
-Small moments of inertia are rods, most mass sits on the rotation axis - example is a linear molecule.

-Inertia is given be I = mr^2
-Inertia also depends on the bond lengths and angles.
-An object can have 3 moments of inertia, rotation around 3 axes.
Around X, IA, has the smallest. Around Y, IB, has middle. Around Z, IC, has the largest. (These are all known as the DOF)
-Linear molecule has very small rotations around X axis, and so IA for linear molecules is 0, so only depends on IB and IC.
- So, linear molecules only have 2 DOF and is given by 3N-5
- Non-linear given by 3N-6.

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3
Q

What is angular momentum?

A

-The equivalent to linear momentum, instead of mass x velocity, angular momentum is moment of inertia x angular velocity (P=I x AV)
-Linear motion (a ball for example) is based on m x v. This is because how hard a ball is thrown depends on its weight and its velocity.
-Angular momentum is the same but something going round in circles, inertia is the mass and angular velocity is how fast its going.
-Angular momentum is quantized and so has a formula.

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4
Q

What is the rotational kinetic energy?

A
  • The rotational kinetic energy is the kinetic energy of a rotation which contributes to the total kinetic energy of a system
  • Normal kinetic energy is given by 1/2mv^2, rot KE is given by Erot = 1/2I x I x AV^2
    -Rearrange P = I x AV for AV = P/I and sub this into the kinetic energy.
  • This gives E = BJ(J+1)
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5
Q

What is B in E = BJ(J+1)

A

B is the rotational constant
This can be divided to give in cm-1, so B = h/8(pi^2)cI

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6
Q

How is BJ(J+1) used?

A

-For example, if a molecule is being excited from J=0 to J=1 then J=1.
- E = BJ(J+1) = B(1+1) = 2B
-So the energy of J=1 is 2B
- For 2 its 6B
- For 3 its 12B.
-The lines on a spectrum will be taller as these numbers increase.
-Transition energy (energy needed to go from 1 state to another would be given by taking the 2 E’s away from each other)

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7
Q

How is the energy difference between neighbouring levels found?

A

DeltaE = DeltaE(j+1)-Ej
= B(J+1)(J+2) - BJ(J+1)
=2B(J+1)

As J increases, then spacing between energy levels increase.

The difference between J=0 and J=1 is 2B.
The difference between J=1 and J=2 is 4B and so on.
The difference keeps increasing by 2B.

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8
Q

What are the selection rules for rotational spectroscopy?

A

-Molecules must have a permanent dipole and it must change during rotation.
-So linear molecules must be of the opposite molecules (H-Cl)
- DeltaJ = (+/-) 1 but many states are occupied so many transitions possible.
-Also needs to be gases at low temps and pressures.
-Spectrum needs to be evenly spaced lines of 2B. (Intensity can increase as energy level increases)
-Bonds lengths can be calculated from I = mr^2

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9
Q

How do the peak intensities work?

A

-The intensity of each line (as J increases) will increase (BUT ALSO SPACED BY 2B) until a certain point, nut will then start dropping.
- This is due to the fact that higher energy levels wont have sufficient thermal energy (T) to be filled at room temp and low press (Boltzmann distribution)

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10
Q

How can the Boltzmann distribution be used?

A

The Boltzmann distribution can give the relative population of states.
N1/N0 = g1/g0 exp(DeltaE/kT)

Shows how much a state is populated over another.
Given as n0 = xn1
As the ground state will be more populated.

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