Mechanics Flashcards

(33 cards)

1
Q

given constant acceleration, we have 5 quantities of motion - suvat, which stands for

A

s = displacement
u = initial velocity
v - final velocity
a = acceleration
t = time

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2
Q

modelling assumption

A

particle :
- mass of object concentrated at a single point
- rotational forces/air resistance can be ignored

smooth/light pulley
- no friction, means tension is the same on either side of the pulley
- pulley has no mass

rod:
- mass is concentrated along the line

peg/support
- dimensionless and fixed. can be rough or smooth

uniform body - mass is concentrated at a single point

rough surface - object in contact with the surface experience a frictional force

smooth surface - no friction

inextensible string - acceleration is the same

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3
Q

earth gravity number

A

9.8

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4
Q

units

A

mass - kg
length/displacement - m
speed / velocity - m s ^-1
acceleration - ms^-2
force/weight - N (kg m s^-2)

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5
Q

how to convert to vector form from scalar form

A

use basic trig to find the x and y

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6
Q

how to convert from vector to scalar

A

find the magnitude

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7
Q

velocity and speed

A

velocity is vector
speed is scalar

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8
Q

average velocity equation

A

displacement from starting point/time taken

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9
Q

average speed equation

A

total distance travelled/time taken

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10
Q

acceleration is

A

the rate of change of velocity

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11
Q

the area under a velocity time graph is…

A

the distance travelled

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12
Q

differentiating displacement gives…

A

velocity, and integrating velocity gives displacement

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13
Q

deceleration =

A

gradient

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14
Q

deceleration =

A

gradient

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15
Q

deceleration =

A

gradient

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16
Q

weight equation

A

W = mg (mass x gravity)

17
Q

what is the normal reaction

A

a force that acts perpendicular to the surface

18
Q

newtons 1st law of motion

A

states that an object at rest will stay at rest
- an object moving with constant velocity will remain at that velocity
- unless an unbalanced force acts on that object

19
Q

newtons second law

20
Q

if a particle is at equilibrium…

A
  • it’s at rest or moving at constant velocity
  • there is no resultant force
  • left = up and right=down
21
Q

State how you have used the fact that the object is modelled as a particle

A

The weight of the objectacts at point

22
Q

when do you use suvat and when do you use distance = speed x time

A

Use “distance = speed x time” when speed is constant, and “SUVAT equations” when acceleration is constant

23
Q

horizontal motion projectiles

A

s = vt as velocity is constant

  • the horizontal component will also always remain constant
24
Q

What causes a string to go slack in mechanics problems?

A

When one object (e.g. B) stops or hits a surface, tension disappears, so the string becomes slack and no longer transmits force.

25
What happens to tension when a string goes slack?
Tension = 0. The string no longer pulls on the other object.
26
If a particle was being pulled by a string and the string goes slack, what happens to its motion?
It continues moving due to its momentum but slows down because there's no longer any force pulling it forward (only resistive forces like gravity on a slope).
27
If a particle is on a slope and the string goes slack, what acceleration acts on it?
Only component of weight down the slope remains: a=gsinθ
28
When a particle continues up a slope after the string goes slack, how do you find the extra distance it travels
Use SUVAT: Initial speed = speed at moment string goes slack Final speed = 0 Acceleration = −gsinθ Use v ^2 =u ^2 +2as
29
How do you know when to split the motion into two phases?
When something stops moving suddenly (like B hitting the ground), the motion splits: Phase 1: Both objects move together with tension Phase 2: One object moves independently (string slack)
30
How do you get the total distance travelled if the string goes slack?
Total distance = ➕ Distance travelled before string went slack ➕ Extra distance after string goes slack (using SUVAT)
31
Common mistake when the string goes slack?
Still using the same acceleration from when the string was taut After slack: reassess forces and re-calculate acceleration
32
when something is smoothly hinged
use x and y, not r and mew r
33
When do I divide by g in mechanics?
Use F = (W/g) × a when you're given weight in newtons (N) instead of mass. Why? Because weight = mass × g, so: mass = weight ÷ g So if you're using weight directly, you must divide it by g to get the mass.