Mechanics Flashcards

(36 cards)

1
Q

Displacement

A

Metre

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2
Q

Velocity

A

M/s

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3
Q

Acceleration

A

M/s/sMS(^-2)

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4
Q

Force/weight

A

N

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5
Q

Distance

A

M

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6
Q

Speed

A

M/S MS^-1

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7
Q

Time

A

S

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8
Q

Mass

A

Kg

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9
Q

Speed is the…

A

Magnitude of velocity vector

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10
Q

Distance is….

A

Magnitude of displacement vector.

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11
Q

Particle

A

Dimensions of the object are negligible
1. mass at single point
-rotational forces + air resistance ignored

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12
Q

Rod

A

All dimensions but 1 one are negligible
-No thickness
-mass concentrated along a line
-rigid (don’t bend)

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13
Q

Inextensible string

A

Don’t stretch under load
Means- acceleration same in any connected objects.

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14
Q
A
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15
Q

On a displacement time graph…

A

Gradient represents velocity
If straight line V constant

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16
Q

Average velocity

A

Displacement form starting/ time taken

17
Q

Speed

A

Distance / time

18
Q

If in a straight diagonal line

A

Displacement increase at constant rate over time + object moving with constant velocity

19
Q

If in a curved line that slowly increases

A

Displacement increase at greater rate as time increase.

20
Q

Velocity

21
Q

If there no change in displacement

A

The line is straight
Velocity is 0

22
Q

If returns to starting point

A

Displacement is zero

23
Q

When object reached highest point on displacement time graph..

A

Velocity is zero

24
Q

From the time ball is thrown to the time it reaches highest point…the motion

A

Velocity of ball is + (upwards) and decreases (decelerating) until reach 0 at highest point.

25
Air resistance negligible
Ignore frictional effects of air on football
26
Football modelled as a particle
Ignore rotational effect of external forces acting on it + air resistance and effects of air resistance and assume all the mass acts as single point
27
28
Vector
I/J I is x direction J is y
29
AB has vector 3i + 4j BC has vector 5i - 12j What is the magnitude of the total displacement form A to C
Add the i together Then add the j together Then do Pythagoras Square root of i^2 + j^2
30
Total distance the man has walked from A to C
Add i + j and do Pythagoras Same with the second one Then add together
31
SUVAT
S= distance U= initial velocity V= final velocity A = acceleration T= time
32
V =
U + AT
33
S =
(U+V)/2 x T
34
S =
UT + 0.5 x A x T^2
35
S=
VT - 0.5 x A x T^2
36
V^2 =
U^2 + 2as