Module 4 Flashcards
Core Organic Chemistry (31 cards)
General formula
The simplest algebraic formula for a homologous series
(Definition not required - understanding)
Structural formula
The minimal detail
that shows the arrangement of atoms in a
molecule
(Definition not required - understanding)
Displayed formula
The relative positioning of atoms and bonds between them
(Definition not required - understanding)
Skeletal formula
Simplified organic formula which removes H from alkyl chains, leaving carbon and f-groups
(Definition not required - understanding)
Explain structural isomers
Compounds with the same molecular
formula but different structural formulae
Homolytic fission
Breaking of a covalent bond, where each atom receives one electron, forming 2 radicals
Heterolytic fission
Breaking of a covalent bond, where one atom receives the pair of electrons, forming one positive and one negative ion
Radical
Species with an unpaired electron
σ-bond
Overlap of orbitals directly between bonding atoms
π-bond
Sideways overlap of adjacent orbitals above/below bonding atoms
Stereoisomers
Molecules with the same structural formula but a different spatial arrangement of atoms
E/Z isomerism
A type of stereoisomerism - 2 different groups attached to each carbon of the C=C group (restricted rotation)
Cis-trans isomerism
A type of E/Z isomerism - same group attached to each carbon of the C=C bond (restricted rotation)
Methods for sustainable processing of waste polymers (3)
- combustion for energy production
- organic feedstock for production of plastics / organic chemicals
- removal of toxic waste products e.g., HCl
Alkene –> Alkane
Alkene + H2 –> Alkane
Ni catalyst required
Alkene –> Dihaloalkane
Alkene + halogen –> dihaloalkane
Alkene –> Haloalkane
Alkene + hydrogen halide –> Haloalkane
Alkene –> Alcohol
Alkene + H2O (steam) –> Alcohol
H3PO4 catalyst
Electrophile
Electron pair acceptor
Limitation of radical substitution
Produces a variety of organic compounds (further substitution and reactions)
Major product of CH2=CHBr + HBr
+ Explanation
CH3-CHBr2
This product forms from the most stable carbocation intermediate
IMFs in alcohols
Hydrogen bonds (and IDDs)
Explain different bpt. for primary/secondary/tertiary alcohols
Primary is straightest chain, so more and stronger IDDs can form between molecules
Secondary is more branched (tertiary the most branched) so less surface contact - fewer and weaker IDDs.
More energy needed to break more/stronger IDDs
Products of complete combustion of alcohol
C2H5OH + 3O2 –> 2CO2 + 3H2O
Carbon dioxide and water