Motion (Uniform And Accelerated) Flashcards

0
Q

Velocity functions

A

A change in position over time

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1
Q

Position functions

A

The location of a given object at a point in time

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2
Q

Acceleration Functions

A

A change in velocity over time

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3
Q

Displacement

A

The net change in position

d=Δs

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4
Q

Displacement formula (given acceleration)

A

Δs=vit+(at^2)/2

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5
Q

Displacement formula (without acceleration)

A

Δs=t*(vi+vf)/2

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6
Q

Final position

A

Sf=v*t+si

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7
Q

Calculating the position function from the acceleration function

A

s(t)=∫∫a(t)

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8
Q

Average postion

A

Savg=(Sf+Si)/2

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9
Q

Average velocity (from position values)

A

Vavg=Δs/Δt

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10
Q

Average velocity (from velocity values)

A

Vavg=(vi+vf)/2 otherwise Vavg=(x-xi)/t

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11
Q

Final velocity (given time)

A

vf=a*t+vi

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12
Q

Final velocity (given displacement)

A

vf=√(2aΔs+vi^2)

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13
Q

Calculating the velocity function from the position function

A

v(t)=∂s(t)

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14
Q

Calculating the position function from the velocity function

A

s(t)=∫v(t)

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15
Q

Calculating the velocity function from the acceleration function

A

v(t)=∫a(t)

16
Q

Average acceleration (given displacement)

A

Aavg=Δs/(Δt)^2

17
Q

Average Acceleration (from velocity values)

A

Aavg=Δv/Δt

18
Q

Calculating Acceleration (without time)

A

a=(vf^2-vi^2)/(2Δs)

19
Q

Calculating acceleration (without final velocity)

A

a=(Δs-vi*t)/t^2

20
Q

Acceleration function from the velocity function

A

a(t)=∂v(t)

21
Q

Acceleration function from the position function

A

a(t)=∂∂s(t)

22
Q

Velocity at a given position on a graph

A

v=[(s(t+h)-s(t)]/h

Where ‘h’ is an arbitrarily small number

23
Q

Acceleration at a given velocity on a graph

A

a=[(v(t+h)-v(t)]/h

Where ‘h’ is an arbitrarily small number

24
Acceleration at a given position on a graph
a=(([(s(t+h)-s(t)]/h)-([(s(t)-s(t-h)]/h))/h Difference of two velocity-from-position functions, that vary by 'h' in two different directions, divided by 'h'
25
Time (from acceleration and displacement)
t=√(Δs/a)
26
Time (from acceleration and velocity)
t=Δv/a
27
Time (from final position and velocity)
t=(Sf-Si)/v
28
Time (from displacement and velocity)
t=Δs/v
29
Time (from final position and acceleration)
t=√((Sf-Si)/a)
30
Time (from final velocity and acceleration)
t=(Vf-Vi)/a
31
Maximum hight of vertical projectiles
Write it out | Ymax=(.5)(-9.81)(vi/9.81)^2+(vi^2)/9.81+yi
32
Time at which a vertical projectile reaches maximum hieght
t=vi/9.81
33
Time at which the vertical projectile returns to yi
t=2(vi)/9.81