MT 2 Flashcards

(163 cards)

1
Q

Chymotrypsin:

[enzyme type] in [organ]

Can cleave [?] bonds on the [?] terminal side of [?] amino acids [give 4 examples]

Synthesized as [precursor] in the [organ]; it is activated in the [organ] by [?] first, then by [?] in a process called [?]

Active chymotrypsin is composed of [#] chains, connected together by [?] bonds

In the active site, it has conserved reactive [?] that can act as a [?]

A

Serine protease in small intestines

Can cleave peptide bonds on the carboxy terminal side of large hydrophobic amino acids (ie. Trp, Phe, Tyr, Met)

Synthesized as chymotrypsinogen in the pancreas; it is activated in the small intestine by trypsin first, then by itself (autolysis; π-chymotrypsin cleaves itself)

Active chymotrypsin is composed of 3 chains, connected together by disulfide bonds

In the active site, it has conserved reactive Ser (S195) that can act as a strong nucleophile

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2
Q

Protease

A

Enzymes that break peptide bonds

Cleave the peptide bond by hydrolysis (addition of water)

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3
Q

What is the purpose of a protease? (5)

A
  1. Protein turnover (ie. reuse proteins)
  2. Maintaining protein homeostasis (ie. degrading misfolded proteins)
  3. Digestion
  4. Activation or deactivation of proteins (enzymes)
  5. Formation of multiple proteins from one polypeptide chain
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4
Q

Why are peptide bonds stable?

A

Resonance structures

The carbonyl is less electrophilic due to resonance structures, so it is less reactive compare to regular carbonyl groups.

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5
Q

Overview of Mechanism of Serine Proteases (2 steps)

A
  1. The nucleophilic oxygen on serine attacks the electrophilic carbonyl of the peptide bond in a nucleophilic attack, cleaving the peptide bond and covalently forming an acyl-enzyme intermediate.
  2. The intermediate is cleaved by water to generate the new carboxyl group and free enzyme (S195 is regenerated)
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6
Q

Why is S195 so reactive?

A

S195 forms H-bond with imidazole ring of His57

This H-bond positions S195 and polarizes the hydroxyl group of S195 (it has alkoxide character)

His acts as a base catalyst (pulls away H+ from S195)

Asp102 also H-bonds with His57, making it a better proton acceptor

Asp102, His57, and Ser195 are known as catalytic triad (true for all serine proteases)

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7
Q

Step-By-Step Catalysis by Chymotrypsin

A
  1. Substrate binds to the active site; large hydrophobic amino acids fit to the hydrophobic pocket next to the active site
  2. The alkoxide ion on S195 does nucleophilic attack on the carbonyl carbon of the substrate. This causes carbon to transciently adopt a tetrahedral geometry. His57 acts as a base catalyst
  3. The tetrahedral intermediate rearranges to the acyl-enzyme intermediate. The carbonyl reforms and the peptide bond is cleaved. His57 acts as an acid catalyst, donating proton to the amine group. The “new” amino peptide fragment leaves the active site.
  4. Water molecule enters the active site; His57 H-bonds with water, making it hydroxide-like
  5. The nucleophilic oxygen of water acts as a nucleophile, attacking the carbonyl carbon. His57 acts as a base catalyst, stealing H from water. This forms another short-lived intermediate– tetrahedral oxyanion
  6. Tetrahedral intermediate rearranges, reforming the carbonyl and separating the product from Ser195. His57 acts as an acid catalyst (H donor to Ser195). A “new” carboxyl peptide is formed and free Ser195 are generated.
  7. The “new” carboxyl peptide leaves active site. Enzyme is ready to catalyze another reaction.
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8
Q

What are some examples of serine proteases? How do they differ from each other?

A

Serine proteases all use the same catalytic mechanism (ie. same catalytic triad), but they all have different specificity

  1. Chymotrypsin has a large hydrophobic pocket, so it binds amino acids with large, hydrophobic side chains
  2. Trypsin has Asp at the bottom of the pocket, so it binds positively charged amino acids
  3. Elastase has 2 Val residues that narrow down the pocket, so it binds amino acids with small R-groups (ie. Ala, Val)
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9
Q

List 4 types of proteases

A
  1. Cysteine proteases
  2. Aspartate proteases
  3. Metalloproteases
  4. Serine proteases
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10
Q

Cysteine proteases

A

Use cysteine as a nucleophile

Example: caspases in apoptosis

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11
Q

Aspartate proteases

A

Have two aspartates that make water a strong nucleophile

Example: HIV proteases

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12
Q

Metalloproteases

A

Use metal ion to make water a strong nucleophile

Example: MMP - matrix metalloproteinase; regulates tissue remodelling

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13
Q

Hemoglobin and Oxygen Transport

A

Hb Oxygen is soluble in water, but not enough to supply tissues

RBC (red blood cells) use Hb to carry oxygen from lungs (high [O2], low [CO2], pH=7.4) to tissues (low [O2], high [CO2], pH=7.2) Carry O2 from high [O2] to low [O2}

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14
Q

Hemoglobin structure

A

Tetramer (quaternary structure) - 2 alpha and 2 beta subunits

Alpha subunit - 144 amino acids; 7 helices

Beta subunit - 146 amino acids; 8 helices

a1β1-a2β2 interface is weaker, has fewer interactions and is less rigid

The other interface (between α1-β1 and β2-α1) is very stable and has many interactions

Each subunit has 1 heme group (4 in total); the O2 binds to heme

Heme has protoporphyrin ring with Fe2+ in the centre Fe2+ has 6 coordination sites (4 are nitrogens from the ring; 5th is from His below the ring; 6th is above the ring and binds oxygen)

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15
Q

How does heme bind O2?

A

When the 6th site is empty, the iron is a little outside the ring

When it binds to O2, it “pops” into the ring, because the electron density changes

The histidine (at the 5th site) is attached to a-helix, so in turn, the a-helix moves, causing carboxyl end to move

This disrupts and creates new ion pairs in the α1β1-α2β2 interface

This conformational change increases the other hemes ability to bind O2

H6 binds oxygen cooperatively

H6 with 3 O2 bound has a 20x greater affinity to O2 compared to when no O2 is bound – this is known as allosteric interaction (ie. change in shape of a protein that results form binding a molecule at a point other than the active site)

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16
Q

What are the two states of hemoglobin?

A

The untwisted deoxyHb (low O2 affinity) = T-state

Twisted oxyHb (high O2 affinity) = R-state

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17
Q

How does cooperativity help O2 transport?

A

If Hb was always in R-state, it would bind O2 in lungs but never release it in the tissues

If Hb was always in T-state, it would bind only small amounts of O2 in the lungs, which is not enough for metabolism

Because Hb binds oxygen cooperatively, it can exist in R-state in the lungs and become saturated with O2, and then travel to the tissues where it can convert to T-state and release O2

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18
Q

Why does it convert from R-state to T-state? List the two main ideas.

A
  1. Bohr effect
  2. 2,3-bisphosphoglycerate (2,3-BPG)
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19
Q

What is the Bohr Effect?

A

H+ and CO2 promote the release of O2 from oxyHb, lowering affinity

This enhances Hb’s ability to release O2 in the tissues and pick it up in the lungs

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20
Q

What is the [H+] and [CO2] in the tissues and lungs?

A

[H+] and [CO2] is high in the tissues, resulting in low affinity to oxygen due to the Bohr effect.

[H+] and [CO2] is low in the lungs, resulting in high affinity to oxygen due to the Bohr effect.

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21
Q

What is the mechanism of the Bohr effect?

A

H+ : some His residues in the α1β1-α2β2 interface have pKa’s close to 7. In conditions of low pH (high [H2]) the histidines become protonated and will interact with other residues, stabilizing the T-state

CO2 : can bind to the free terminal amino group; carbonate ions can form new ionic interactions that will stabilize the T-state

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22
Q

How does 2,3-bisphosphoglycerate impact the conversion of R-state to T-state?

A

DeoxyHb binds to 2,3-BPG, which stabilizes the T-state, lowering affinity to O2 It binds in a special pocket formed by the 2 β subunits

The pocket has a positive charge to interact with the negatively charged 2,3-BPG

Part of transition from T-state to R-state is the removal of 2,3-BPG from Hb

Conformational changes during T→R make the pocket too small for 2,3-bBPG to fit; thus, 2,3-BPG leaves, stabilizing the R-state.

The binding curve shifts, resulting in higher affinity.

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23
Q

Why do we need the protein part of hemoglobin? Why don’t we just have heme?

A
  1. Cooperativity (only works with protein)
  2. CO binds to heme 25,000x better than O2; Hb lowers the affinity for CO by shielding heme
  3. Prevents iron (Fe2+) from being oxidized (to Fe3+) because the protein has interactions that shield iron from being oxidized
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24
Q

Metabolism

A

Highly integrated network of reactions (chemical pathways) that enable a cell to extract energy from the environment and use this energy for biosynthesis

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25
Catabolism
Reactions that use fuel to generate useful energy
26
Anabolism
Reactions that use energy to form complex structures
27
Cellular respiration equation
glucose + O2 → CO2 + H2O + energy
28
Thermodynamics and ATP
In order for a pathway to proceed: 1. Reactions must be specific to its final product 2. Reactions must be thermodynamically favoured
29
How do endergonic reactions proceed?
Couple with exergonic reactions The overall free energy change for a chemically coupled series of reactions is equal to the sum of the individual steps Common method: couple with ATP hydrolysis
30
What are the reactions and the net reaction for the conversion of glucose to G-6-P?
1. Glucose + Pi → Glu-6-P + H2O 2. ATP + H2O → ADP + Pi Net reaction: Glucose + ATP → Glu-6-P + ADP
31
What is standard state?
25 degrees Celsius (298K), 1 atm pressure, [] = 1M, pH=7
32
ATP
Called the universal energy currency of the cell Consists of ribose, adenine, and three phosphates
33
What structure is this?
Pi Inorganic Phosphate
34
What structure is this?
Ppi Pyrophosphate
35
Why is the hydrolysis of ATP so favourable?
1. Relief of charge repulsion At pH=7, ATP has a -4 charge, and ADP has a -3 charge 2. Resonance stabilization of Pi 3. Ionization of ADP At pH=7, ADP-2 + e- → ADP-3 + H+ 4. Greater solvation of the product (ie. more H-bonds with H2O)
36
Does ATP hydrolysis drive reactions?
No, usually it is not ATP hydrolysis that drives reactions, even if we write it this way; rather, it is phosphoryl transfer from ATP
37
Phosphoryl transfer
Movement of phosphate group from one molecule to another; this is how reactions are coupled Molecules other than ATP can transfer phosphates; all have negative -ΔG0' (more negative means higher phosphoryl transfer capacity; something with more negative ΔG0' can easily phosphorylate something less negative)
38
Creatine phosphate
creatine phosphate + ADP + H+ ⇌ ATP + creatine @ standard state (negative delta G) Creatine phosphate is used to regenerate ATP in muscle during the first few seconds of heavy muscle contraction
39
Exercise Time vs Energy Source
1-3 seconds: ATP 3-9 seconds: Creatine-P Up to 1 minute: Glycolysis Up to 40 minutes: Glycogen \>40 minutes: Fats + glucose
40
Carbohydrates general chemistry
An aldehyde or ketone compounds with multiple hydroxyl-groups General formula: (CH2O)n Sugars can be drawn as linear aldehydes (aldoses) or ketones (ketoses) depending on where the carboxyl is placed Sugars have chiral carbons, thus there exists different enantiomers Sugars with more than 3 carbons have multiple chiral centers (they can exist as diastereomers) Fischer projections help to view enantiomers
41
What are the simplest sugars?
Simplest sugars: trioses (3C's)
42
How do you differentiate between different enantiomers of sugars? Which is which?
When looking at a Fischer projection of a sugar, if the chiral center for the furthest carbonyl carbon has hydroxyl (~OH) group on the right, it is a "D" ; if the ~OH is on the left, it is an "L" form
43
Which enantiomer is present in living cells?
Usually "D" form in living cells
44
Hexose
6 carbon sugar 16 different aldoses; 8 different ketoses
45
Epimers
Sugars that differ only at one chiral carbon
46
Why do sugars exist as ring structures?
Aldehyde and ketones can react with alcohols to form hemiacetals and hemiketals ie. C5-OH of aldohexose (6-C sugar) can attack C1 carbonyl, forming a 6 membered ring called pyranose ie. C5-OH of ketohexose can attack C2 carbonyl, forming a 5-membered ring known as furanose ie. C-O-OH group can also attack C-2 carbonyl, forming a pyranose ring
47
Pyranose
6-membered sugar ring
48
Furanose
5-membered sugar ring
49
Anomeric carbon
- The new chiral center that is formed when the cyclic form is created; it is where the carbonyl carbon was previously - it is reactive
50
Anomers
Alpha/Beta If the hydroxyl group of the anomeric carbon is below the ring, it is α If the hydroxyl group of the anomeric carbon is above the ring, is it β
51
In the cell, glucose can exist as...
1/3 α-ring anomer 2/3 β-ring anomer \<1% is open chain \*note, there is spontaneous conversion ("mutarotation") between anomers
52
Mutarotation
the change in the optical rotation because of the change in the equilibrium between two anomers, when the corresponding stereocenters interconvert cyclic sugars show mutarotation as α and β anomeric forms interconvert
53
What structure is this?
ATP
54
What structure is this?
Ribose (Beta-D Ribofuranose)
55
What structure is this?
Adenine (purine base)
56
What are these bonds called?
Phosphodiester bonds
57
Draw D-Glucose (open-chain)
58
Draw D-Fructose (open-chain)
59
Draw D-Galactose (open-chain)
60
Convert this to ring form (pyranose)
61
Convert this to ring form (furanose)
62
Draw α-D-Glucopyranose
63
Draw α-D-Fructofuranose
64
Draw β-D-Glucopyranose
65
Draw β-D-Fructofuranose
66
What structure is this?
Pyran
67
What structure is this?
Furan
68
Draw α-D-glucopyranosyl-(1→4)-D-glucopyranose What's another name for this molecule?
69
What structure is this?
β-D-galactopyranosyl-(1→4)-β-D-glucopyranose Lactose (β form)
70
What structure is this?
α-D-glucopyranosyl-(1→4)-D-glucopyranose Maltose
71
Draw β-D-galactopyranosyl-(1→4)-β-D-glucopyranose What's another name for this molecule?
72
Draw β-D-fructofuranosyl α-D-glucopyranoside What's another name for this molecule?
73
Draw α-D-glucopyranosyl-(1→1)-α-D-glucopyranoside What's another name for this molecule?
74
What structure is this?
β-D-fructofuranosyl α-D-glucopyranoside Sucrose
75
What structure is this?
α-D-glucopyranosyl-(1→1)-α-D-glucopyranoside Trehalose
76
What can the anomeric carbon react with?
- proteins (glycosylation) ie. serine, threonine, tyrosine → O-glycosylation (-OH group) ie. arginine, asparagine → N-glycosylation (-N) - other sugars → form disaccharides, polysaccharides
77
Draw the condensation reaction between α-D-glucose and β-D-glucose.
78
Polysaccharide
Several molecules of monosaccharides connected by glycosidic bonds Sugars in polysaccharides are in ring structures (pyranose or furanose)
79
What are the bonds between sugar molecules called?
Glycosidic bonds
80
Glycolysis
The sequence of reactions that break down 1 molecule of glucose into 2 molecules of pyruvate with the net production of 2 ATPs.
81
Is glycolysis an aerobic or anaerobic process?
Anaerobic; doesn't require oxygen
82
What can pyruvate be converted into?
1. H2O + CO2 (via Krebs cycle and oxidative phosphorylation) 2. Lactate (lactic fermentation; doesn't require oxygen) 3. Ethanol (alcohol fermentation; doesn't require oxygen)
83
The pathway of glycolysis can be broken down to 2 stages. What are they?
1. Preparatory stages: trapping and destabilization of glucose; cleavage of phosphofructose 2. Payoff stage: ATP and pyruvate are generated
84
How does glucose enter the cell?
Through facilitated diffusion via glucose transporters
85
Glycolysis: Stage 1
Glucose is phosphorylated using ATP by hexokinase on C6, yielding glucose-6-phosphate (G-6-P) This traps glucose in the cell, because it lowers [glucose] and G-6-P also cannot go back through the glucose transporters due to its charge This also destabilizes the molecule of glucose This reaction is irreversible
86
Draw the reaction for step 1 of glycolysis
[Insert picture]
87
Glycolysis: Stage 2
G-6-P is converted to F-6-P by phosphohexose isomerase Multistep process, converting G-6-P to open ring structure before converting it to F-6-P This reaction is reversible
88
Draw the reaction for step 2 of glycolysis
89
Glycolysis: Stage 3
F-6-P is phosphorylated by phosphofructokinase-1 (PFK-1) to fructose-1,6-bisphosphate (F-1,6-BP) This reaction is reversible This is an important regulation point, because it is the committed step; bottleneck step Once this step occurs, it is committed to glycolysis; previous step to form G-6-P is also irreversible, but G-6-P can be used for things other than glycolysis, where as F1,6-BP cannot) This is also the rate-determining step of glycolysis
90
Draw the reaction for step 3 of glycolysis
91
Glycolysis: Stage 4
Aldolase cleaves F-1,6-BP into DHAP and G3P Reversible reaction You now have two 3C fragments Only G3P goes further in glycolysis, so DHAP is converted to G3P in the next reaction
92
Draw the reaction for step 4 of glycolysis
93
Glycolysis: Stage 5
DHAP is converted to G3P by triose phosphate isomerase This reaction is reversible
94
Draw the reaction for step 5 of glycolysis
[insert picture]
95
Glycolysis: Stage 6
G3P is oxidized and phosphorylated to 1,3-BPG by GAPDH Requires inorganic phosphate and NAD+ 1,3-BPG has higher phosphoryl transfer potential Reaction is reversible
96
We can imagine stage 6 of glycolysis as happening in 2 steps to understand the mechanism (in reality, this is not true). What are these 2 steps?
1. Oxidize G3P to a carboxylic acid using NAD+ (NAD+ + 2e- + 2H+ → NADH + H+) This is very favourable; ΔG\<0 2. The carboxylic group is attached to orthophosphate Not favourable; ΔG\>0 Note: these two reactions are coupled by thioester (S-C=O) intermediate, so that the first reaction drives the 2nd reaction (free acid is never formed)
97
GAPDH Mechanism
1. Form hemiacetal with a cysteine residue in the active site 2. NAD+ oxidizes hemiacetal to form thioester; in the process, NAD+ is converted to NADH 3-4. When NADH is replaced by a fresh NAD+, inorganic phosphate can attack the carbonyl and cleave the reaction intermediate from cysteine, forming the product Note: We generate 2 molecules of 1,3-BPG per 1 molecule of glucose, so 2 molecules of NADH are generated
98
Draw the reaction for step 6 of glycolysis
99
Glycolysis: Stage 7
1,3-BPG phosphorylates ADP, forming ATP and 3-phosphoglycerate (3-PG) x2 This is another example of substrate level phosphorylation Catalyzed by phosphoglycerate kinase Reaction is reversible
100
Draw the reaction for step 7 of glycolysis
101
Glycolysis: Stage 8
Phosphoglycerate mutase converts 3-PG to 2-PG (2-phosphoglycerate) x2 Reaction is reversible Requires cofactor: 2,3-bisphosphoglycerate (2,3-BPG)
102
Mutase
An enzyme that causes intramolecular rearrangement (isomerization)
103
Kinase
An enzyme that catalyzes the transfer of phosphate groups from high-energy, phosphate-donating molecules to specific substrates
104
Phosphatase
An enzyme that uses water to cleave a phosphoric acid monoester into a phosphate ion and an alcohol.
105
Phosphoglycerate mutase mechanism
1. Enz-His + 2,3-BPG ⇌ (phosphatase activity) ⇌ Enz-His-P + 2-phosphoglycerate (product) 2. Enz-His-P + 3-phosphoglycerate (substrate) ⇌ (kinase activity) ⇌ Enz-His + 2,3-BPG (cofactor)
106
Draw the reaction for step 8 of glycolysis
107
Glycolysis: Stage 9
Enolase removes water from 2-PG forming an enol: phosphoenolpyruvate (PEP) x2 Reversible reaction PEP is another molecule with high phosphoryl transfer capacity Note: Enol form of PEP exist in tautomer form Phosphate traps PEP in enol form
108
Draw the reaction for step 9 of glycolysis
109
Glycolysis: Step 10
Pyruvate kinase transfers a phosphate from PEP to ADP, forming ATP x2 Irreversible reaction
110
Draw the reaction for step 10 of glycolysis
111
Net Glycolysis Reaction
Glucose + 2ADP + 2Pi + 2NAD+ → 2 pyruvate + 2 ATP + 2 NADH + 2H+ + 2H2O
112
Fermentation
The process used in bacteria and year to convert pyruvate from glycolysis to either CO2 + ethanol (alcohol fermentation) or to lactate (lactic fermentation) to regenerate NAD+ from NADH. Humans can also do lactic fermentation - this happens in skeletal muscle during intensive exercise.
113
Oxidation
Loss of e-
114
Reduction
Gain of e-
115
In biological systems, redox reactions are usually accompanied by addition/removal of \_\_\_\_\_\_\_.
Pairs of hydrogen ions (H+)
116
What is the final electron acceptor in aerobic sysems?
Oxygen 2H+ + 2e- + 1/2 O2 → H2O However, the highly energetic electrons are not transferred to oxygen directly; carriers are used to transfer electrons (and H+) to electron transport chain or to biosynthetic reactions that need them
117
What structure is this?
NAD+ (oxidized form)
118
What structure is this?
NADH (reduced form)
119
What structure is this? [insert picture]
NADP+ (oxidized form)
120
What structure is this?
NADPH (reduced form)
121
What are NAD+ / NADH / NADP+ / NADPH derived from?
ATP and niacin (vitamin B3)
122
What kinds of reactions are NAD+ / NADH used in?
Catabolic reactions
123
What kinds of reactions are NADP+ / NADPH used in?
Anabolic reactions
124
What structure is this? [insert picture]
FAD (oxidized form)
125
What structure is this?
FADH2 (fully reduced form)
126
What structure is this?
FADH (semiquinone)
127
What structure is this? [insert picture]
FMN (oxidized form)
128
What structure is this?
FMNH+ (semiquinone)
129
What structure is this?
FMNH2 (fully reduced)
130
What is FAD / FADH2 / FMN / FMNH2 derived from?
ATP and riboflavin (vitamin B2)
131
What is the equation for the conversion of FAD to FADH2?
FAD + 2H+ + 2e- ⇌ FADH2
132
FAD/FMN vs NADH/NADPH in terms of movement
FAD/FMN is usually bound to something, unlike NADH/NADPH which is free to move around
133
Why must NAD+ be regenerated?
The pool of NAD+/NADH is small, so NAD+ must be regenerated in order for glycolysis to run
134
Fate of Pyruvate: Aerobic systems
NAD+ is regenerated from NADH by the electron transport chain Oxygen is the final electron acceptor, and water is the final electron carrier Pyruvate is converted into acetyl-CoA and oxidized further in the Kreb's cycle
135
Fate of Pyruvate: Anaerobic systems
There is no oxygen to accept electron, so fermentation occurs
136
Fermentation in mammals
Enzyme lactate dehydrogenase reduces pyruvate to lactate and in the process converts NADH to NAD+, which allows glycolysis to continue Pyruvate is a final electron acceptor and lactate is the final electron carrier Happens in skeletal muscle during high intensity exercise
137
Draw the fermentation reaction that occurs in skeletal muscles of mammals.
138
Fermentation in yeast
Pyruvate is first decarboxylated by pyruvate decarboxylase, forming acetaldehyde Acetaldehyde is reduced to ethanol by alcohol dehydrogenase, converting NADH back to NAD+ Note: NAD+ is generated at the second step Acetaldehyde is the electron acceptor Ethanol is the final electron carrier
139
Regulation of glycolysis
Happens on the cellular level Occurs at the three irreversible steps 1. Step #1 - hexokinase 2. Step #3 - PFK-1 3. Step #10 - pyruvate kinase All of these enzymes are regulated allosterically (in most cases)
140
PFK-1 regulation
Most important rate-limiting step Increased [ATP] inhibits PFK-1 Increased [AMP] activates PFK-1 Increased [fructose-2,6-bisphosphate] stimulates PFK-1 (this regulated by hormones and is not an intermediate of glycolysis) Increased [citrate] inhibits PFK-1 (this is a Kreb's cycle intermediate) Increased [H+] inhibits PFK-1 (ie. lactic fermentation results in H+ production)
141
Hexokinase regulation
Reaction #1 It is allosterically inhibited by its product, G-6-P This is an example of product inhibition; prevents excessive glucose phosphorlyation
142
Pyruvate kinase regulation
Reaction #10 Increased [ATP] inhibits pyruvate kinase Increased alanine inhibits pyruvate kinase Increased [fructose-1,6-bisphosphate] activates pyruvate kinase (this is an example of feed forward stimulation) Regulated by hormones
143
What is the logic that explains why alanine inhibits pyruvate kinase?
Alanine is made from pyruvate, so an excessive presence of alanine is indicative of an excessive production of pyruvate (ie. by pyruvate kinase)
144
Feed forward stimulation
Upstream build-up results in downstream activation
145
Draw a diagram that summarizes regulation of glycolysis in the cell.
146
Conversion of pyruvate to acetyl-CoA Done by multienzyme complex called (?) Occurs in (?) Involves (?) of pyruvate to (?), followed by formation of (?) Free (?) never forms, but it helps us to understand the mechanism
Done by multienzyme complex called pyruvate dehydrogenase complex (PDH complex) Occurs in the mitochondrial matrix Involves decarboxylation/oxidation of pyruvate to acetate, followed by formation of acetyl-CoA (thioester) Free acetate never forms, but it helps us to understand the mechanism
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Enzyme complex of PDH - What are the enzymes and cofactors involved?
Enzymes: E1, E2, E3 Cofactors: TPP is bound to E2 FAD is bound to E3 NAD+ is free CoASH is free
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Coenzyme A
aka CoASH, CoA Derived from ADP, vitamin B5 (pantothenate) and B-mercaptoethylamine Carrier of an acyl-group Forms high energy thioester bonds
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Draw acetyl-CoA
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Write out the reaction from acetyl-CoA to CoASH and the corresponding delta G.
Acetyl-CoA + H2O ⇌ acetate + CoASH Delta G at standard state is -31 kJ/mole
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TPP
Thiamine pyrophosphate Derived from vitamin B1 (thiamine) Forms a reactive carbanion easily
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Draw the conversion of pyruvate to acetyl-CoA reaction
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What part of CoA is derived from vitamin B5?
Pantothenic acid component
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What structure is this?
Coenzyme A
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What structure is this?
Thiamine pyrophosphate (TPP)
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What structure is this?
Hydroxyethyl thiamine pyrophosphate
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Lipoic acid aka (?) Attached to (?) via (?), forming (?) (?) (?) to (?) groups, resulting in the (?) group being attached to one of the (#) (?) atoms (breaking the (?)) Acts as a (?)
aka Lipoyllysine Attached to E2 via lysine side chain, forming lipoyllysine Oxidizes hydroxyethyls to acyl groups, resulting in the acyl group being attached to one of the 2 sulphur atoms (breaking the disulphide bridge) Acts as a robotic arm
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5 Step Mechanism of PDH complex
1) Pyruvate enters E1 TPP attacks pyruvate and decarboxylates it to form the reaction intermediate: hydroxyethyl-TPP 2a) The lipoyllysine arm swings towards E1 2b) Hydroxyethyl group is oxidized to acetyl group and transferred to the lipoyllysine arm 3a) The arm swings into E2 3b) The acetyl group is transferred to a free CoASH (coenzyme A), forming acetyl CoA. The lipoyllysine is reduced in the process. 3c) Acetyl CoA leaves the PDH complex 4a) The arm swings to E3 4b) Here, the lipoyllysine arm is oxidized by FAD. FAD is reduced to FADH2. 5) NAD+ enters E3 and re-oxidizes FADH2 back to FAD. In the process, NAD+ is reduced to NADH + H+, which leaves E3. Now we're back to step #1, and another molecule of pyruvate can enter the PDH complex
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Regulation of PDH complex - E2 (dihydrolipoyl transacetylase)
Increased [acetyl CoA] inhibits E2 (product inhibition)
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Regulation of PDH complex - E3 (dihydrolipoyl dehydrogenase)
Increased [NADH] inhibits E3 (product inhibtion)
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Regulation of PDH complex - E1 (pyruvate dehydrogenase)
Majority of PDH complex regulation happens on E1 through phosphorylation (ie. of serine, tyrosine, threonine) 1) PDH-kinase phosphorylates PDH-E1, which deactivates it. Increased [acetyl CoA] activates PDH-kinase Increased [NADH] activates PDH-kinase Increased [ATP] activates PDH-kinase Increased [NAD+] inhibits PDH-kinase Increased [ADP] inhibits PDH-kinase 2) PDH-phosphatase removes phosphate from PDH-E1, which re-activates it. Increased [insulin] activates PDH-phosphatase Increased [Ca2+] activates PDH-phosphatase Note: Ca2+ is released during muscle contraction, thus suggestive is high energy consumption In general, PDH is switched off when energy is high, and switched on when energy is low.
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Draw the tautomerization of pyruvate
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Fill in the standard free energies of hydrolysis of these phosphorylated compounds and acetyl-Co-A (kJ/mol)