Nuclear Physics Flashcards
(146 cards)
Suggest how the idea of atoms came about
1- The idea of atoms has been around since the time of the Ancient Greeks in the 5th century BC. Democritus proposed that all matter was made up of little identical lumps called ‘atomos’
2- In 1804 John Dalton put forward a hypothesis that agreed with Democritus that matter was made up of tiny spheres (atoms) that couldn’t be broken up. He reckoned that each element was made up of a different type of atom
3- Nearly 100 years later JJ Thompson discovered that electrons could be removed from atoms. So Dalton’s theory wasn’t quite right (atoms could be broken up)
4- Thompson suggested that atoms were spheres of positive charge with tiny negative electrons stuck in them like fruit in a plum pudding
5- Until this point nobody had proposed the idea of the nucleus. Rutherford was the first to suggest atoms did not have uniformly distributed charge and density
What did the Rutherford scattering experiment show the existence of?
The Rutherford scattering experiment showed the existence of a nucleus
Explain the Rutherford scattering experiment
- In 1909 Rutherford and Marsden tried firing a beam of alpha particles at thin gold foil. A circular detector screen surrounding the gold foil and the alpha source was used to detect alpha particles deflected by any angle. They expected that the positively charged alpha particles would be deflected by the electrons by a very small amount if the plum pudding model was true but instead most of the alpha particles just went straight through the foil while a small number were deflected by a large angle. Some were even deflected by more than 90 degrees sending them back the way they came, this was confusing at the time and called for a change to the model of the atom
Describe the conclusions that were made from the Rutherford Scattering experiment
The results of the Rutherford Scattering experiment suggested that atoms must have a small positively charged nucleus at the centre:
1- Most of the atom must be empty space because most of the alpha particles passed straight through the foil
2- The nucleus must have a large positive charge as some positively charged alpha particles were repelled and deflected by a large angle
3- The nucleus must be small as very few alpha particles were deflected back
4- Most of the mass must be concentrated in the nucleus since the fast alpha particles with high momentum are deflected by the nucleus
Explain how to calculate the an estimate for the closest approach of a scattered particle to the nucleus
- When you fire an alpha particle at a gold nucleus you know its initial kinetic energy. An alpha particle that ‘bounces back’ and is deflected through 180 degrees will have reversed direction a short distance from the nucleus. It does this at the point where its electric potential energy equals its initial kinetic energy.
- Its just conservation of energy and can be used to find how close the particle can get to the nucleus
State the formula used to estimate the closest approach of a scattered particle to a nucleus
Ek = Eelec = QgoldQalpha/4πε0r
- ε0 is the permittivity of free space
- r is the distance from the centre of the nucleus in m
What is r in the the formula Ek = Eelec = QgoldQalpha/4πε0r?
r is the distance between the centres of the scattered particle and the nucleus
How do you find the charge of the nucleus?
To find the charge of a nucleus you need to know the atoms proton number, Z which tells you how many protons there are in the nucleus. A proton has a charge of +e where e is the size of the charge on an electron so the charge of a nucleus must be +Ze
What is the distance of closest approach an estimate for?
The distance of closest approach is an estimate of nuclear radius (the radius of the nucleus), it gives a maximum value for it
How does the estimate of nuclear radius provided by electron diffraction compare to the estimate given by the distance of closest approach?
Electron diffraction gives a much more accurate value for nuclear radii than the distance of closest approach does
How many protons and neutrons does an alpha particle have?
It has two protons and two neutrons
How many protons does a gold nucleus have?
79 protons
State the formula used to calculate the closest distance of approach of an alpha particle to a nucleus rearranged for r
r = Ze*2e/4πε0Ek
- Z is the number of protons in the nucleus
- Ek is the initial kinetic energy of the alpha particle
What are the assumptions made with the theory of closest distance of approach?
1- The alpha particle is a point charge (it is not)
2- The nucleus does not recoil and gain some kinetic energy (it will)
3- The scattering is by the electrostatic force and the alpha particles do not get close enough to the nucleus to feel the strong force (they probably will if they have a high enough energy)
You can use electron diffraction to estimate…
Nuclear radius
Why is electron diffraction an accurate method for estimating the nuclear radius?
Electrons are a type of particle called a lepton. Leptons don’t interact with the strong nuclear force whereas neutrons and alpha particles do so because of this electron diffraction is an accurate method for estimating the nuclear radius
Why can electron beams be diffracted?
As electrons show wave-particle duality
State the formula used to calculate the De Broglie wavelength of a beam of electrons moving at high speeds
λ = hc/E
- E is the electron energy in Joules
- h is the planck constant
- c is the speed of light in a vacuum
To investigate the nuclear radius what must the wavelength of the electrons be?
To investigate the nuclear radius the wavelength of the electrons must be tiny, so the electrons will have a very high energy
What will happen if a beam of high energy electrons is directed onto a thin film of material in front of a screen?
If a beam of high-energy electrons is directed onto a thin film of material in front of a screen a diffraction pattern will be seen on the screen
State the formula used to calculate where the first minimum appears on an electron diffraction pattern
Sinθ = 1.22λ/2R
- R is the radius of the nucleus the electrons have been scattered by
How do you calculate the radius of a nucleus from an electron diffraction pattern?
- Use the equation λ = hc/E to calculate the De Broglie wavelength of the electrons from their energy
- Use the equation Sinθ = 1.22λ/2R to solve for R
Why is electron diffraction a more accurate method for estimating nuclear radius than alpha scattering?
1- Electrons are not affected by the strong nuclear force
2- Electrons are a better approximation to point charges than alpha particles
3- Electrons penetrate the nucleus but alpha particles do not because they are repelled by the nucleus before they reach it so electrons give a better value for the radius of the nucleus
4- There is less recoil of the nucleus when electrons hit it due to their lower mass. The recoil can complicate calculations
What does the intensity of the maxima in an electron diffraction pattern vary with?
Diffraction angle