Operators, Expectation Values and Uncertainties Flashcards
(57 cards)
What are the Hamiltonian, Momentum and Spatial operators?
To determine the effect of one operator, or multiple operators, what do you do?
You apply the operators to a test function f(x)
Lct:11 for more processed steps
The eigenvalue can take ANY value for a momentum eigenstate- momentum is continuous, not quantised, unlike energy.
INFO: Just take the solution as it is, do not need to prove that u(x) is delta function.
What is Postulate 2?
N2K
Let u(x) = v(x) + w(x)
No, A is not a linear operator
N2K What is the property of the Hermitian operator? State in Bra-ket and integral form.
N2K Why must observables correspond to Hermitian Operators?
The eigenvalues of Hermitian operators are real, hence are observable - why they represent experimental observables.
The eigenvectors of Hermitian operators form an orthogonal basis
Hint: Use two generic functions f(x) + g(x)
Hint: Use two arbitrary functions f(x), g(x)
Units of energy = h(bar) * omega
State V(x) for a Quantum Harmonic Oscillator (QHO)
State the ladder operators of a QHO
What is the result of applying both ladder operators on each other? Rearrange for the Hamiltionian.
What is Postulate 3?
What does it mean if PSI(x) is already an eigenstate of the Operator?
It means EVERY MEASUREMENT is known with complete certainty (does NOT CHANGE- SAME EIGENVALUE AND EIGENVECTOR).
This is called a determinant state
IMPORTANT: u2(x) is an eigenstate of the Hamiltonian, hence it is a determinant state, and all measurements will return the same value.
What happens if PSI(x) is not an eigenstate(i.e. a superposition of eigenstates)?
PSI(x) is not a determinant state, hence we can no know with certainty that every measurement will return the same value. It is likely a different eigenstate of the superposition (can only be the eigenstates of the superposition - all other amplitudes are 0) will be measured.
State the probability of obtaining the nth eigenstate upon measuring the observable of a superposition state. (Born’s Rule)
Normalise is the first step
Important: Measuring observables with two operators of the SAME basis return eigenvalues(different) corresponding to the SAME eigenvector- will always measure same eigenstate.
The system is in a deteminant state. When the same eigenstate is returned for two operators, they are compatible.